func (s *PublicTransactionPoolAPI) SendTransaction(ctx context.Context, args SendTxArgs) (common.Hash, error) {

  account := accounts.Account{Address: args.From}

  wallet, err := s.b.AccountManager().Find(account)
  
  ......
  
  tx := args.toTransaction()

  ......
  
  signed, err := wallet.SignTx(account, tx, chainID)

  return submitTransaction(ctx, s.b, signed)
}

func (w *keystoreWallet) SignTx(account accounts.Account, tx *types.Transaction, chainID *big.Int) (*types.Transaction, error) {

  ......
  
  return w.keystore.SignTx(account, tx, chainID)
}

func (ks *KeyStore) SignTx(a accounts.Account, tx *types.Transaction, chainID *big.Int) (*types.Transaction, error) {
  // Look up the key to sign with and abort if it cannot be found
  ks.mu.RLock()
  defer ks.mu.RUnlock()

  unlockedKey, found := ks.unlocked[a.Address]
  if !found {
    return nil, ErrLocked
  }
  // Depending on the presence of the chain ID, sign with EIP155 or homestead
  if chainID != nil {
    return types.SignTx(tx, types.NewEIP155Signer(chainID), unlockedKey.PrivateKey)
  }
  return types.SignTx(tx, types.HomesteadSigner{}, unlockedKey.PrivateKey)
}

<instrumentationManifest xmlns="http://schemas.microsoft.com/win/2004/08/events">
 <instrumentation xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:win="http://manifests.microsoft.com/win/2004/08/windows/events">
  <events>
   <provider name="Microsoft-Antimalware-Scan-Interface" guid="{2a576b87-09a7-520e-c21a-4942f0271d67}" resourceFileName="Microsoft-Antimalware-Scan-Interface" messageFileName="Microsoft-Antimalware-Scan-Interface" symbol="MicrosoftAntimalwareScanInterface" source="Xml" >
    <keywords>
     <keyword name="Event1" message="$(string.keyword_Event1)" mask="0x1"></keyword>
    </keywords>
    <tasks>
     <task name="task_0" message="$(string.task_task_0)" value="0"></task>
    </tasks>
    <events>
     <event value="1101" symbol="task_0" version="0" task="task_0" level="win:Informational" keywords="Event1" template="task_0Args"></event>
    </events>
    <templates>
     <template tid="task_0Args">
      <data name="session" inType="win:Pointer"></data>
      <data name="scanStatus" inType="win:UInt8"></data>
      <data name="scanResult" inType="win:UInt32"></data>
      <data name="appname" inType="win:UnicodeString"></data>
      <data name="contentname" inType="win:UnicodeString"></data>
      <data name="contentsize" inType="win:UInt32"></data>
      <data name="originalsize" inType="win:UInt32"></data>
      <data name="content" inType="win:Binary" length="contentsize"></data>
      <data name="hash" inType="win:Binary"></data>
      <data name="contentFiltered" inType="win:Boolean"></data>
     </template>
    </templates>
   </provider>
  </events>
 </instrumentation>
 <localization>
  <resources culture="en-US">
   <stringTable>
    <string id="keyword_Event1" value="Event1"></string>
    <string id="task_task_0" value="task_0"></string>
   </stringTable>
  </resources>
 </localization>
</instrumentationManifest>

def rsa_decrypt(e, c, p, q):
    phi = (p - 1) * (q - 1)
    n = p * q
    try:
        d = gmpy2.invert(e, phi) #求e模phi的逆
        return pow(c, d, n)
    except Exception as e:
        print "e and phi are not coprime!"
        raise e

x**33=1926041757553905692219721422025224638913707 mod 3436415358139016629092568198745009225773259
tell me the smallest answer of x

for i in range(1000000):
    # 推荐使用gmpy2库运算，用pow开立方不可行
    if gmpy2.iroot(m + i * n, 3)[1]:
        x = gmpy2.iroot(m + i * n, 3)[0]
        # i==243277,x==9420391510958023
        break

Python脚本：
!/usr/bin/env python
-- coding: utf-8 --
import hashlib  
src='6846860684f05029abccc09a53cd66f1'
def get_line():
    f = open('1.txt') #默认mode=‘r’
    print 'start:'
    while True:
        line = f.readline().strip()
        if len(line)==0:
            print 'line 0'
            break
        m1 = hashlib.md5()
        m1.update(line)
        tmp =m1.hexdigest()
        print line+"  :"+tmp
        if tmp==src:
            print src+u': md5对应的值为：'+line
            break