Don't miss out on the Offer of The Day!🤩
Join our Complete Interview Preparation Course@ Lowest price ever!
💁🏼♀️Yes you heard that right!
Use Coupon "GOLCIP20" to get an Instant 20% Discount💫
HURRY! Offer Valid till today only.
To avail of this offer: https://practice.geeksforgeeks.org/courses/complete-interview-preparation?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=cip
Join our Complete Interview Preparation Course@ Lowest price ever!
💁🏼♀️Yes you heard that right!
Use Coupon "GOLCIP20" to get an Instant 20% Discount💫
HURRY! Offer Valid till today only.
To avail of this offer: https://practice.geeksforgeeks.org/courses/complete-interview-preparation?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=cip
"Problem of the Day"
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a BST and a number X, find Ceil of X.
Note: Ceil(X) is a number that is either equal to X or is immediately greater than X.
Full Problem: https://bit.ly/3Pz5JtN
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a BST and a number X, find Ceil of X.
Note: Ceil(X) is a number that is either equal to X or is immediately greater than X.
Full Problem: https://bit.ly/3Pz5JtN
practice.geeksforgeeks.org
Ceil in BST | Practice | GeeksforGeeks
Given a BST and a number X, find Ceil of X.
Note: Ceil(X) is a number that is either equal to X or is immediately greater than X.
Example 1:
Input:
5
/ \
1 7
\
2
\
 
Note: Ceil(X) is a number that is either equal to X or is immediately greater than X.
Example 1:
Input:
5
/ \
1 7
\
2
\
 
Steal it with the Offer of the day.
Grab our C++ Programming Foundation, self-paced course at 25% discount, the lowest price ever.
Use Coupon Code: GOLCPPF25
OFFER VALID FOR TODAY ONLY.
To avail of this offer: https://practice.geeksforgeeks.org/courses/CPP-Foundation?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=cppf
Grab our C++ Programming Foundation, self-paced course at 25% discount, the lowest price ever.
Use Coupon Code: GOLCPPF25
OFFER VALID FOR TODAY ONLY.
To avail of this offer: https://practice.geeksforgeeks.org/courses/CPP-Foundation?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=cppf
Can you pick the "ODD ONE OF THE SQUAD"
Let's find out in this fun quiz. Participate in this fun quiz and stand a chance to win amazon vouchers. 🤩
In it to Win it.✨
As simple as that. 😉
You can submit your entry till 19th July, 04:59 PM
Let the fun begins: https://bit.ly/3cnwCmg
Let's find out in this fun quiz. Participate in this fun quiz and stand a chance to win amazon vouchers. 🤩
In it to Win it.✨
As simple as that. 😉
You can submit your entry till 19th July, 04:59 PM
Let the fun begins: https://bit.ly/3cnwCmg
"Problem of the Day"
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given an array Arr of size N containing positive integers. Count number of smaller elements on right side of each array.
Full Problem: https://bit.ly/3PE5gqo
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given an array Arr of size N containing positive integers. Count number of smaller elements on right side of each array.
Full Problem: https://bit.ly/3PE5gqo
practice.geeksforgeeks.org
Count Smaller elements | Practice | GeeksforGeeks
Given an array Arr of size N containing positive integers. Count number of smaller elements on right side of each array.
Example 1:
Input:
N = 7
Arr[] = {12, 1, 2, 3, 0, 11, 4}
Output: 6 1 1 1 0 1 0
Explanation: There are 6
Example 1:
Input:
N = 7
Arr[] = {12, 1, 2, 3, 0, 11, 4}
Output: 6 1 1 1 0 1 0
Explanation: There are 6
Winner Winner Chicken Dinner🙌
Bring your squad to the battleground in this BGMI Tournament and stand a chance to win the amazing rewards.
Happening at 06:30 PM on our Discord.
And the Countdown begins 🤩🤩
To enter the arena: https://discord.gg/7355eaw5
Bring your squad to the battleground in this BGMI Tournament and stand a chance to win the amazing rewards.
Happening at 06:30 PM on our Discord.
And the Countdown begins 🤩🤩
To enter the arena: https://discord.gg/7355eaw5
This media is not supported in your browser
VIEW IN TELEGRAM
Good things come to those who practice for it.❤
Weekly contest series to help you crack the SDE interviews. Brought to you, partnered with Amazon.
All you need to do is:
- Appear on the leaderboard,
- Earn Geekbits
- Redeem rewards
Stop procastinating and start doing!
Check out for more details: https://practice.geeksforgeeks.org/events/rec/interview-series?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=interviewseries
Weekly contest series to help you crack the SDE interviews. Brought to you, partnered with Amazon.
All you need to do is:
- Appear on the leaderboard,
- Earn Geekbits
- Redeem rewards
Stop procastinating and start doing!
Check out for more details: https://practice.geeksforgeeks.org/events/rec/interview-series?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=interviewseries
Give a booster shot to your SDE Interview Preparation.
Grab our OS DBMS CN for SDE Interview Preparation, self-paced course at 25% off, the lowest price ever.
Hurry Up! Offer Valid Only For Today.
Grab it now: https://practice.geeksforgeeks.org/courses/SDE-theory?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=sdet
Grab our OS DBMS CN for SDE Interview Preparation, self-paced course at 25% off, the lowest price ever.
Hurry Up! Offer Valid Only For Today.
Grab it now: https://practice.geeksforgeeks.org/courses/SDE-theory?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=sdet
"Problem of the Day"
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a string, find the minimum number of characters to be inserted to convert it to palindrome.
Full Problem: https://bit.ly/3zjHjzf
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a string, find the minimum number of characters to be inserted to convert it to palindrome.
Full Problem: https://bit.ly/3zjHjzf
Missed out on this quiz? 🙌🙌
Worry not, you can still participate in this quiz.
Test your C++ Foundation with these MCQs and win assured rewards.
Submit your entry by 11:59 PM IST today.
Participate Now: https://forms.gle/VdxWpTT5pbfrLP2D8
Worry not, you can still participate in this quiz.
Test your C++ Foundation with these MCQs and win assured rewards.
Submit your entry by 11:59 PM IST today.
Participate Now: https://forms.gle/VdxWpTT5pbfrLP2D8
Learn the various frameworks of Javascript with Offer of the day. 🙌
Get Advanced Javascript, self-paced course at 25% discount, the lowest price ever.
Offer Valid For Today Only.
Grab it now: https://practice.geeksforgeeks.org/courses/advanced-javascript-self-paced?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=ajs
Get Advanced Javascript, self-paced course at 25% discount, the lowest price ever.
Offer Valid For Today Only.
Grab it now: https://practice.geeksforgeeks.org/courses/advanced-javascript-self-paced?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=ajs
"Problem of the Day"
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Now, we'll try to solve a famous stack problem.
You are given an array A of size N. You need to first push the elements of the array into a stack and then print minimum in the stack at each pop.
Full Problem: https://bit.ly/3zlMA9n
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Now, we'll try to solve a famous stack problem.
You are given an array A of size N. You need to first push the elements of the array into a stack and then print minimum in the stack at each pop.
Full Problem: https://bit.ly/3zlMA9n
Don't forget to Say Hi,🙋♀️ to the offer of the day!
Build fast and responsive websites with our Complete Bootstrap Course for Beginners, at 25% discount, the lowest price ever.
OFFER VALID FOR TODAY ONLY.
Start learning today: https://practice.geeksforgeeks.org/courses/bootstrap?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=boot
Build fast and responsive websites with our Complete Bootstrap Course for Beginners, at 25% discount, the lowest price ever.
OFFER VALID FOR TODAY ONLY.
Start learning today: https://practice.geeksforgeeks.org/courses/bootstrap?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=boot
"Problem of the Day"
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a graph with V vertices. We say two vertices u and v belong to a single province if there is a path from u to v or v to u. Your task is to find the number of provinces.
Full Problem: https://bit.ly/3RS8Z5x
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a graph with V vertices. We say two vertices u and v belong to a single province if there is a path from u to v or v to u. Your task is to find the number of provinces.
Full Problem: https://bit.ly/3RS8Z5x
Let's celebrate this milestone with the greatest geek of all time. 🙌
Join Mr. Sandeep Jain at 6 PM IST, in a live session, exclusively on our Discord.
To join the live stream: https://discord.gg/hyEepxM9
Join Mr. Sandeep Jain at 6 PM IST, in a live session, exclusively on our Discord.
To join the live stream: https://discord.gg/hyEepxM9
Ohh look 👀 Offer of the day is here. 🤩
Get industry-ready with our Test Series for Product-Based Companies at 25% discount, the lowest price ever.
OFFER VALID FOR TODAY ONLY.
Grab it now: https://practice.geeksforgeeks.org/courses/test-series-bundle?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=pbts
Get industry-ready with our Test Series for Product-Based Companies at 25% discount, the lowest price ever.
OFFER VALID FOR TODAY ONLY.
Grab it now: https://practice.geeksforgeeks.org/courses/test-series-bundle?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=pbts
"Problem of the Day"
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
You are playing a game. At each level of the game, you have to choose one of the roads to go to the next level. Initially, you have h amount of health and m amount of money.
Full Problem: https://bit.ly/3OvGac2
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
You are playing a game. At each level of the game, you have to choose one of the roads to go to the next level. Initially, you have h amount of health and m amount of money.
Full Problem: https://bit.ly/3OvGac2
Test your web development skills with this weekly quiz. 🤓
Solve these MCQs based on Complete Bootstrap and win assured rewards.
You can submit your entry by 24th July, 11:59 PM IST.
To participate now: https://forms.gle/2q1uGcsxJ1twsmoDA
Solve these MCQs based on Complete Bootstrap and win assured rewards.
You can submit your entry by 24th July, 11:59 PM IST.
To participate now: https://forms.gle/2q1uGcsxJ1twsmoDA
"Problem of the Day"
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a Binary Tree, find the maximum sum path from a leaf to root.
Full Problem: https://bit.ly/3zv8iru
Solve this question to get points.
Maintain the 24days streak and earn Geekbits, Rewards, and much more.
Given a Binary Tree, find the maximum sum path from a leaf to root.
Full Problem: https://bit.ly/3zv8iru
practice.geeksforgeeks.org
Maximum sum leaf to root path | Practice | GeeksforGeeks
Given a Binary Tree, find the maximum sum path from a leaf to root.
Example 1:
Input:
1
/ \
2 3
Output:
4
Explanation:
Following the path 3 -> 1, results in a
sum of 4, which is the maximum path sum
from
Example 1:
Input:
1
/ \
2 3
Output:
4
Explanation:
Following the path 3 -> 1, results in a
sum of 4, which is the maximum path sum
from
Kickstart your interview preparation with the offer of the day. 🙌🙌
Grab our Low Level Design, self paced course at 25% discount, the lowest price ever.
OFFER VALID FOR TODAY ONLY.
To get this course now: https://practice.geeksforgeeks.org/courses/object-oriented-design?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=lld
Grab our Low Level Design, self paced course at 25% discount, the lowest price ever.
OFFER VALID FOR TODAY ONLY.
To get this course now: https://practice.geeksforgeeks.org/courses/object-oriented-design?utm_source=telegram&utm_medium=marketingteam_telegram&utm_campaign=ootd&utm_term=lld