In triangle ABC right angled at B if tan A = 1/root 3 find the value of sin A cos C + cos A sin C

Q: In triangle ABC, right-angled at B, if tan A = 1/√3, find the value of:
(i) sin A cos C + cos A sin C (ii) cos A cos C – sin A sin C
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Chemical Reactions and Equations Class 10 MCQ Term 1 | Science Chapter 1 MCQ Class 10 Term-1 Exam

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In Triangle PQR Right Angled at Q PR + QR is equal to 25 cm and PQ = 5 cm Determine values of sin P


Q: In Δ PQR right-angled at Q PR + QR = 25 cm and PQ = 5 cm Determine the values of sin P, cos P and tan P.
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Q: Given tan A = 4/3, find the other trigonometric ratios of the angle A.

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MCQ of Real Numbers for Class 10 | Real Numbers Class 10 MCQ Online Test |MCQ of Ch 1 Maths Class 10

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If Angle B and Angle Q are Acute Angles such that Sin B=Sin A then prove that Angle B=Angle Q


Q: If ∠ B and ∠ Q are acute angles such that sin B = sin Q, then prove that ∠ B = ∠ Q


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Show that 0.2353535..... can be expressed in the form p/q where p and q are integers and q not = 0.


Q: Show that 0.2353535... = 0.235 can be expressed in the form p/q , where p and q are integers and 𝑞≠0


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In Triangle ABC Right Angled at B AB = 5 cm and Angle ACB = 30° Determine the lengths of BC and AC


Q: In  ∆ ABC, right-angled at B, AB = 5 cm and ∠ ACB = 30° (see Fig. 8.19). Determine the lengths of the sides BC and AC


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In Triangle PQR Right Angled at Q. PQ = 3 cm and PR = 6 cm. Determine Angle QPR and Angle PRQ


Q: In Δ PQR, right-angled at Q (see Fig. 8.20), PQ = 3 cm and PR = 6 cm. Determine ∠ QPR and ∠ PRQ.


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.If sin A-B =1/2, cos A+B =1/2 THEN FIND THE VALUE OF A and B



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evaluate sin 60 degree cos 30 degree + sin 30 degree cos 60 degree


Q: Evaluate the following sin 60° cos 30° + sin 30° cos 60°


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Evaluate Cos 45/Sec30+Cosec30 | Evaluate Cos 45 Degrees by Sec30 Degree + Cosec 30 Degree

Q: Evaluate cos 45° /sec 30° + cosec 30°


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Evaluate 5cos260°+4 sec230°− tan245° sin230°+ cos230°


Q: Evaluate 5cos^260°+4 sec^230°− tan^245° sin^230°+ cos^230°


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Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.


Hint 💡
sin A= 1/Cosec A
tan A = 1/Cot A
sec^2 A = 1 + – tan^2 A
cosec^2 A = 1 + cot^2 A


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