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Triangles Class10 | Class 10 Chapter 6 Maths | NCERT Solutions for Class 10 Maths Chapter 6 Triangles | IIT JEE FOUNDATION COURSE FOR CLASS 10: https://www.youtube.com/playlist?list=PL-hYriZY1lNx1NOHIJ9OFMZhifuhDa8cF
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ANSWER
let us assume that c.p of the horse = x
let us assume that c.p of the horse = y
As given
A man bought 4 horses and 9 cows for rs 1340.
Than the equation
4x + 9y = 1340
As given
He sells the horses at a profit of 10% and cows at profit of 20% and his whole gain is Rs188
10 % written in the decimal form
= 0.01
20 % written in the decimal form
= 0.20
than the equation
0.01 ×4x + 0.20× 9y = 188
simplify the equation
4x + 18y = 1880
the two equation becomes
4x + 9y = 1340 and 4x + 18y = 1880
subtracting 4x + 9y = 1340 from 4x + 18y = 1880
9y = 1880 - 1340
9y = 540
y =60
put in 4x + 9y = 1340
4x + 540 = 1340
4x = 1340 - 540
x =200
He pay for each horse be Rs 200.
He pay for each cows Rs 60
total money paid for horses Rs 4x200= Rs800
let us assume that c.p of the horse = x
let us assume that c.p of the horse = y
As given
A man bought 4 horses and 9 cows for rs 1340.
Than the equation
4x + 9y = 1340
As given
He sells the horses at a profit of 10% and cows at profit of 20% and his whole gain is Rs188
10 % written in the decimal form
= 0.01
20 % written in the decimal form
= 0.20
than the equation
0.01 ×4x + 0.20× 9y = 188
simplify the equation
4x + 18y = 1880
the two equation becomes
4x + 9y = 1340 and 4x + 18y = 1880
subtracting 4x + 9y = 1340 from 4x + 18y = 1880
9y = 1880 - 1340
9y = 540
y =60
put in 4x + 9y = 1340
4x + 540 = 1340
4x = 1340 - 540
x =200
He pay for each horse be Rs 200.
He pay for each cows Rs 60
total money paid for horses Rs 4x200= Rs800
https://youtu.be/2i7QzvtD1KQ
Quiz on very important chapter carbon and its compound. Quiz timings daily at 8:30 p.m.
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mcq of carbon and its compounds class 10 | mcq on carbon and its compounds class 10
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