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#ChallengeAbsoluteDifference #Algorithm #DataStructure #Loop #Array

Consider an array of integers, arr[0], arr[1] ... arr[n-1]. We define the absolute difference between two elements, arr[i] and arr[j] (where i != j), to be the absolute value of arr[i] - arr[j]

Given an array of integers, find and print the minimum absolute difference between any two elements in the array. For example, given the array arr=[-2, 2, 4] we can create 3 pairs of numbers: [-2, 2], [-2, 4], and [2, 4] . The absolute differences for these pairs are |(-2)-2|=4, |(-2)-4|=6, and |2-4|=2 . The minimum absolute difference is 2.

Q: Define the minimumAbsoluteDifference function which has a parameter arr. It should return an integer that represents the minimum absolute difference between any pair of elements.
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Many of you are participated in this challenge. Thanks for your participation.
Your answers are correct and accepted.
But you always find the most efficient and optimized algorithm to solve problems.

Here is the efficient solution for the challenge. Share it.

def minimumAbsoluteDifference(arr):
arr.sort()
result = []
for i in range(len(arr)-1):
result.append(abs(arr[i+1]-arr[i]))
return sorted(result)[0]

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