// 3. Problem Solving
What's the output?
const shape = {
radius: 10,
diameter() {
return this.radius * 2;
},
perimeter: () => 2 * Math.PI * this.radius,
};
console.log(shape.diameter());
console.log(shape.perimeter());
A: 20 and 62.83185307179586
B: 20 and NaN
C: 20 and 63
D: NaN and 63
What's the output?
const shape = {
radius: 10,
diameter() {
return this.radius * 2;
},
perimeter: () => 2 * Math.PI * this.radius,
};
console.log(shape.diameter());
console.log(shape.perimeter());
A: 20 and 62.83185307179586
B: 20 and NaN
C: 20 and 63
D: NaN and 63
DevScrolls
// 3. Problem Solving What's the output? const shape = { radius: 10, diameter() { return this.radius * 2; }, perimeter: () => 2 * Math.PI * this.radius, }; console.log(shape.diameter()); console.log(shape.perimeter()); A: 20 and 62.83185307179586…
What's the output for the above?
Anonymous Poll
46%
A: 20 and 62.83185307179586
38%
B: 20 and NaN
15%
C: 20 and 63
0%
D: NaN and 63
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DevScrolls
// 3. Problem Solving What's the output? const shape = { radius: 10, diameter() { return this.radius * 2; }, perimeter: () => 2 * Math.PI * this.radius, }; console.log(shape.diameter()); console.log(shape.perimeter()); A: 20 and 62.83185307179586…
Answer: B
20 and NaN
Note that the value of diameter is a regular function, whereas the value of perimeter is an arrow function.
With arrow functions, the this keyword refers to its current surrounding scope, unlike regular functions! This means that when we call perimeter, it doesn't refer to the shape object, but to its surrounding scope (window for example).
There is no value radius on that object, which returns NaN.
20 and NaN
Note that the value of diameter is a regular function, whereas the value of perimeter is an arrow function.
With arrow functions, the this keyword refers to its current surrounding scope, unlike regular functions! This means that when we call perimeter, it doesn't refer to the shape object, but to its surrounding scope (window for example).
There is no value radius on that object, which returns NaN.
4. Problem solving
What's the output?
+true; !'Lydia';
What's the output?
+true; !'Lydia';
Anonymous Poll
50%
A: 1 and false
33%
B: false and NaN
17%
C: false and false
Answer: A
The unary plus operator tries to convert an operand to a number. true is 1, and false is 0.
The string 'Lydia' is a truthy value.
By using the not operator at the beginning of truthy value it became false.
The unary plus operator tries to convert an operand to a number. true is 1, and false is 0.
The string 'Lydia' is a truthy value.
By using the not operator at the beginning of truthy value it became false.
5. Problem Solving
Which one is true? const bird = { size: 'small', }; const mouse = { name: 'Mickey', small: true, };
Which one is true? const bird = { size: 'small', }; const mouse = { name: 'Mickey', small: true, };
Anonymous Quiz
35%
A: mouse.bird.size is not valid
27%
B: mouse[bird.size] is not valid
15%
C: mouse[bird["size"]] is not valid
23%
D: All of them are valid
DevScrolls
5. Problem Solving
Which one is true? const bird = { size: 'small', }; const mouse = { name: 'Mickey', small: true, };
Which one is true? const bird = { size: 'small', }; const mouse = { name: 'Mickey', small: true, };
Answer: A
In JavaScript, all object keys are strings (unless it's a Symbol). Even though we might not type them as strings, they are always converted into strings under the hood.
JavaScript interprets (or unboxes) statements. When we use bracket notation, it sees the first opening bracket [ and keeps going until it finds the closing bracket ]. Only then, it will evaluate the statement.
mouse[bird.size]: First it evaluates bird.size, which is "small". mouse["small"] returns true
However, with dot notation, this doesn't happen. mouse does not have a key called bird, which means that mouse.bird is undefined. Then, we ask for the size using dot notation: mouse.bird.size. Since mouse.bird is undefined, we're actually asking undefined.size. This isn't valid, and will throw an error similar to Cannot read property "size" of undefined.
In JavaScript, all object keys are strings (unless it's a Symbol). Even though we might not type them as strings, they are always converted into strings under the hood.
JavaScript interprets (or unboxes) statements. When we use bracket notation, it sees the first opening bracket [ and keeps going until it finds the closing bracket ]. Only then, it will evaluate the statement.
mouse[bird.size]: First it evaluates bird.size, which is "small". mouse["small"] returns true
However, with dot notation, this doesn't happen. mouse does not have a key called bird, which means that mouse.bird is undefined. Then, we ask for the size using dot notation: mouse.bird.size. Since mouse.bird is undefined, we're actually asking undefined.size. This isn't valid, and will throw an error similar to Cannot read property "size" of undefined.
DevScrolls
What's the output?
Answer: A
In JavaScript, all objects interact by reference when setting them equal to each other.
First, variable c holds a value to an object. Later, we assign d with the same reference that c has to the object.
When you change one object, you change all of them.
In JavaScript, all objects interact by reference when setting them equal to each other.
First, variable c holds a value to an object. Later, we assign d with the same reference that c has to the object.
When you change one object, you change all of them.
7. What's the output?
A: true false true
B: false false true
C: true false false
D: false true true
let a = 3;
let b = new Number(3);
let c = 3;
console.log(a == b); console.log(a === b); console.log(b === c);A: true false true
B: false false true
C: true false false
D: false true true
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7. What's the output? let a = 3; let b = new Number(3); let c = 3; console.log(a == b); console.log(a === b); console.log(b === c); A: true false true B: false false true C: true false false D: false true true
What's the output?
Anonymous Poll
38%
A: true false true
22%
B: false false true
24%
C: true false false
16%
D: false true true
Answer: C
new Number() is a built-in function constructor. Although it looks like a number, it's not really a number: it has a bunch of extra features and is an object.
When we use the == operator, it only checks whether it has the same value. They both have the value of 3, so it returns true.
However, when we use the === operator, both value and type should be the same. It's not: new Number() is not a number, it's an object. Both return false.
new Number() is a built-in function constructor. Although it looks like a number, it's not really a number: it has a bunch of extra features and is an object.
When we use the == operator, it only checks whether it has the same value. They both have the value of 3, so it returns true.
However, when we use the === operator, both value and type should be the same. It's not: new Number() is not a number, it's an object. Both return false.
8. What's the output?
class Chameleon {
static colorChange(newColor) {
this.newColor = newColor;
return this.newColor;
}
constructor({ newColor = 'green' } = {}) {
this.newColor = newColor;
}
}
const freddie = new Chameleon({ newColor: 'purple' });
console.log(freddie.colorChange('orange'));
A: orange
B: purple
C: green
D: TypeError
class Chameleon {
static colorChange(newColor) {
this.newColor = newColor;
return this.newColor;
}
constructor({ newColor = 'green' } = {}) {
this.newColor = newColor;
}
}
const freddie = new Chameleon({ newColor: 'purple' });
console.log(freddie.colorChange('orange'));
A: orange
B: purple
C: green
D: TypeError
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8. What's the output? class Chameleon { static colorChange(newColor) { this.newColor = newColor; return this.newColor; } constructor({ newColor = 'green' } = {}) { this.newColor = newColor; } } const freddie = new Chameleon({ newColor:…
Answer: D
The colorChange function is static. Static methods are designed to live only on the constructor in which they are created, and cannot be passed down to any children or called upon class instances. Since freddie is an instance of class Chameleon, the function cannot be called upon it. A TypeError is thrown.
The colorChange function is static. Static methods are designed to live only on the constructor in which they are created, and cannot be passed down to any children or called upon class instances. Since freddie is an instance of class Chameleon, the function cannot be called upon it. A TypeError is thrown.