YOO, LOCK IN β 60 MINUTES LEFT
Weβre gonna print so much sol today!!! Stay on!!
The team will push after launch with massive promos to get it on the DEX trending list.
Make sure youβre loaded and ready, Iβm aping big on this to secure gains. π
Weβre gonna print so much sol today!!! Stay on!!
The team will push after launch with massive promos to get it on the DEX trending list.
Make sure youβre loaded and ready, Iβm aping big on this to secure gains. π
β€9π6π₯2
My next 100X play is dropping in 30 minutes from now
This is extreme alpha
Im expecting this to run 3M+
This is extreme alpha
Im expecting this to run 3M+
β€9π5π3π₯1
Who is active right now?? Im on the phone with dev right now guys the hype is real for this one!
β€13π₯4π2π2
READ THIS RIGHT NOW , IMPORTANT
If youβre in many channels then you probably see a lot of Callers posting about this launch which is happening minutes from now
WE ARE GETTING IN BEFORE ALL OF THEM
SO BE READY AND KEEP CHAT OPEN
If youβre in many channels then you probably see a lot of Callers posting about this launch which is happening minutes from now
WE ARE GETTING IN BEFORE ALL OF THEM
SO BE READY AND KEEP CHAT OPEN
β€10π5π₯4π1π«‘1
The developer team just notified me that there was an error with the CA.
SELL OUT OF THE BROKEN COIN
They will redeploy and verify everything works in the next few minutes. Take this time to load up more $SOL
React π once you have sold out and loaded up more Solana
SELL OUT OF THE BROKEN COIN
They will redeploy and verify everything works in the next few minutes. Take this time to load up more $SOL
React π once you have sold out and loaded up more Solana
π10β€7π₯4π1
The developers said that they will get more KOLS during the first round of marketing.
For now, load up $SOL and be ready for the working CA.
Launch should be in about 10 minutes
For now, load up $SOL and be ready for the working CA.
Launch should be in about 10 minutes
β€6π6π«‘2π₯1
π9β€7π₯3π2
My goals are 2-5M+ for this launch, and since this is ECA entry, weβre getting in under 50K Mc!!
β€11π3π₯3