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JPMC Glasgow/London hiring for 2024 Batch
SWE Role
https://jpmc.fa.oraclecloud.com/hcmUI/CandidateExperience/en/sites/CX_1001/job/210505691
SWE Role
https://jpmc.fa.oraclecloud.com/hcmUI/CandidateExperience/en/sites/CX_1001/job/210505691
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Work India is hiring for Intern and FTE
https://www.linkedin.com/posts/moiz-arsiwala-8a990032_hi-all-workindia-is-hiring-for-3-month-activity-7180873334581080066-BYIq
https://www.linkedin.com/posts/moiz-arsiwala-8a990032_hi-all-workindia-is-hiring-for-3-month-activity-7180873334581080066-BYIq
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Summer Internship at TestGrid.io
Batch: 2025
https://www.linkedin.com/jobs/view/3850573143
TechOps Automation (Intern) at BNB Chain Innovation
3-6 Months Paid Internship
https://www.linkedin.com/jobs/view/3848209006
Batch: 2025
https://www.linkedin.com/jobs/view/3850573143
TechOps Automation (Intern) at BNB Chain Innovation
3-6 Months Paid Internship
https://www.linkedin.com/jobs/view/3848209006
Linkedin
TestGrid.io hiring Summer Intern in India | LinkedIn
Posted 11:36:16 PM. Company DescriptionTestGrid.io is a leading provider of end-to-end automation cloud and on-premiseโฆSee this and similar jobs on LinkedIn.
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Please try to react on the post in case you are applying, it will hardly take your 10 secs but enough to motivate me to share more and more opportunities everyday without fail:)
Just one favour if you canโค๏ธ
Just one favour if you canโค๏ธ
โค11๐คฉ3
Server Selection
JP Morgan โ
JP Morgan โ
โค1
def string_replacement(word, substr):
n = len(word)
m = len(substr)
j = 0
word = list(word)
for i in range(n):
if word[i] == '?':
if j < m:
word[i] = substr[j]
j += 1
else:
return "-1"
if j < m:
return "-1"
return ''.join(word)
String Replacement
Python 3โ
JP Morgan
n = len(word)
m = len(substr)
j = 0
word = list(word)
for i in range(n):
if word[i] == '?':
if j < m:
word[i] = substr[j]
j += 1
else:
return "-1"
if j < m:
return "-1"
return ''.join(word)
String Replacement
Python 3โ
JP Morgan
The Organized Shop
JP Morgan โ
JP Morgan โ
๐1
Meeting Scheduler โ
JP Morgan
JP Morgan
#include<bits/stdc++.h>
using namespace std;
int a[100][100];
int N,K,M;
int getmax(int t,int q,int Z,int Y)
{
int max=0;
for(int i=t;i<Z;i++)
{
for(int j=q;j<Y;j++)
{
if (max<a[i][j])
{
max=a[i][j];
}
}
}
return max;
}
int main()
{
cin>>N>>K>>M;
for(int i=0;i<N;i++)
for(int j=0;j<N;j++)
{
cin>>a[i][j];
}
int i,j;
vector<int>p;
for(int i=0;i<N;i++)
{
for(int j=0;j<N;j++)
{
if((j+K)<=N &&(i+K)<=N)
{
int x =getmax(i,j,i+K,j+K);
p.push_back(x);
}
}
}
vector<int>u;
cout<<"\n\nP array=";
for(int i=0;i<p.size();i++)
{
cout<<p[i]<<" ";
if(p[i]>=M)
{
u.push_back(p[i]);
}
}
cout<<"\n\nOUTPUT:";
cout<<endl<<u.size()<<" "<<*min_element(u.begin(), u.end())<<" "<<*max_element(u.begin(), u.end());
return 0;
}
submatrix maximum
Urban โ
using namespace std;
int a[100][100];
int N,K,M;
int getmax(int t,int q,int Z,int Y)
{
int max=0;
for(int i=t;i<Z;i++)
{
for(int j=q;j<Y;j++)
{
if (max<a[i][j])
{
max=a[i][j];
}
}
}
return max;
}
int main()
{
cin>>N>>K>>M;
for(int i=0;i<N;i++)
for(int j=0;j<N;j++)
{
cin>>a[i][j];
}
int i,j;
vector<int>p;
for(int i=0;i<N;i++)
{
for(int j=0;j<N;j++)
{
if((j+K)<=N &&(i+K)<=N)
{
int x =getmax(i,j,i+K,j+K);
p.push_back(x);
}
}
}
vector<int>u;
cout<<"\n\nP array=";
for(int i=0;i<p.size();i++)
{
cout<<p[i]<<" ";
if(p[i]>=M)
{
u.push_back(p[i]);
}
}
cout<<"\n\nOUTPUT:";
cout<<endl<<u.size()<<" "<<*min_element(u.begin(), u.end())<<" "<<*max_element(u.begin(), u.end());
return 0;
}
submatrix maximum
Urban โ
#include <iostream>
using namespace std;
int main() {
int N;
cin >> N;
int parent[N + 1];
for (int i = 0; i <= N; i++) {
parent[i] = 0;
}
for (int i = 0 ; i < N - 1; i++) {
int u, v;
cin >> u >> v;
parent[v] = u;
}
int Q;
cin >> Q;
for (int i = 0; i < Q; i++) {
int p, c;
cin >> p >> c;
bool found = false;
while (c != 0) {
c = parent[c];
if (c == p) {
found = true;
break;
}
}
if (found) {
cout << "1" << endl;
}
else {
cout << "0" << endl;
}
}
return 0;
}
Tree Relation
Urban โ
using namespace std;
int main() {
int N;
cin >> N;
int parent[N + 1];
for (int i = 0; i <= N; i++) {
parent[i] = 0;
}
for (int i = 0 ; i < N - 1; i++) {
int u, v;
cin >> u >> v;
parent[v] = u;
}
int Q;
cin >> Q;
for (int i = 0; i < Q; i++) {
int p, c;
cin >> p >> c;
bool found = false;
while (c != 0) {
c = parent[c];
if (c == p) {
found = true;
break;
}
}
if (found) {
cout << "1" << endl;
}
else {
cout << "0" << endl;
}
}
return 0;
}
Tree Relation
Urban โ
๐1
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
ll divisors(ll num) {
ll cnt = 0;
for(ll d = 1; d * d <= num; d++) {
if (num % d == 0) {
cnt+=1+(num/d!=d);
// cnt += (num / d == d) ? 1 : 2;
}
}
return cnt;
}
ll numOfSubarrays(vector<ll> &nums) {
ll odd = 0, even = 0, sum = 0;
for (ll num : nums) {
if (divisors(num) & 1) {
swap(odd, even);
++odd;
} else {
++even;
}
sum += odd;
}
return sum;
}
int main() {
int n;
cin >> n;
vector<ll> nums(n);
for (ll &num : nums) cin >> num;
cout << numOfSubarrays(nums);
return 0;
}
Chaotic Subarrays
Urban โ
using namespace std;
using ll = long long;
ll divisors(ll num) {
ll cnt = 0;
for(ll d = 1; d * d <= num; d++) {
if (num % d == 0) {
cnt+=1+(num/d!=d);
// cnt += (num / d == d) ? 1 : 2;
}
}
return cnt;
}
ll numOfSubarrays(vector<ll> &nums) {
ll odd = 0, even = 0, sum = 0;
for (ll num : nums) {
if (divisors(num) & 1) {
swap(odd, even);
++odd;
} else {
++even;
}
sum += odd;
}
return sum;
}
int main() {
int n;
cin >> n;
vector<ll> nums(n);
for (ll &num : nums) cin >> num;
cout << numOfSubarrays(nums);
return 0;
}
Chaotic Subarrays
Urban โ
๐1
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
#include<bits/stdc++.h> using namespace std; int a[100][100]; int N,K,M; int getmax(int t,int q,int Z,int Y) { int max=0; for(int i=t;i<Z;i++) { for(int j=q;j<Y;j++) { if (max<a[i][j]) { โฆ
Submatrix Maximum
Urbanโ
Urbanโ
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
#include<bits/stdc++.h> using namespace std; using ll = long long; ll divisors(ll num) { ll cnt = 0; for(ll d = 1; d * d <= num; d++) { if (num % d == 0) { cnt+=1+(num/d!=d); // cnt += (num / d == d) ? 1 : 2; โฆ
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
ll countSubarray(int N, vector<ll> &A) {
ll odd = 0, even = 0, sum = 0;
for (ll num : A) {
ll sqrtNum = sqrt(num);
if (sqrtNum * sqrtNum == num) {
swap(odd, even);
++odd;
} else {
++even;
}
sum += odd;
}
return sum;
}
int main() {
int n;
cin >> n;
vector<ll> A(n);
for (ll &num : A) cin >> num;
cout << countSubarray(n, A);
return 0;
}.
Chotic subarray โ
Urban
using namespace std;
using ll = long long;
ll countSubarray(int N, vector<ll> &A) {
ll odd = 0, even = 0, sum = 0;
for (ll num : A) {
ll sqrtNum = sqrt(num);
if (sqrtNum * sqrtNum == num) {
swap(odd, even);
++odd;
} else {
++even;
}
sum += odd;
}
return sum;
}
int main() {
int n;
cin >> n;
vector<ll> A(n);
for (ll &num : A) cin >> num;
cout << countSubarray(n, A);
return 0;
}.
Chotic subarray โ
Urban
๐ฑ1
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๐Zebra Technologies is hiring for Software Engineer, I
Expected Salary: 8-15 LPA
Experience: 0-2 years
๐Apply here: https://zebra.eightfold.ai/careers?src=srm_linkedin_jb&domain=zebra.com&pid=343618832439
Expected Salary: 8-15 LPA
Experience: 0-2 years
๐Apply here: https://zebra.eightfold.ai/careers?src=srm_linkedin_jb&domain=zebra.com&pid=343618832439
zebra.eightfold.ai
Careers at Zebra
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๐TechGig Code Gladiators 2024: Unlock your career journey !!
๐ Unlock job and internship opportunities through this coding contest.
- Compete With The Best
- Gain Industry Recognition
- Land Your Dream Job
- Win Big
Win prizes worth Rs 10 Lakhs ๐ฐ and earn the title of Best Coder of the World ๐
๐Apply now at: https://bit.ly/43MyDza
Share this opportunity with your friends ๐.
๐ Unlock job and internship opportunities through this coding contest.
- Compete With The Best
- Gain Industry Recognition
- Land Your Dream Job
- Win Big
Win prizes worth Rs 10 Lakhs ๐ฐ and earn the title of Best Coder of the World ๐
๐Apply now at: https://bit.ly/43MyDza
Share this opportunity with your friends ๐.
Techgig
Code Gladiators - Largest Coding Contest in India | TechGig
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๐Sigfyn is hiring for Software Developer (Freshers)
Location: Remote
๐Apply here: https://linkedin.com/jobs/view/3877413684
Location: Remote
๐Apply here: https://linkedin.com/jobs/view/3877413684