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๐ŸšฉMain Group - @SuperExams
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๐Ÿ”ฐAuthentic Coding Solutions(with Outputs)
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#include<bits/stdc++.h>
using namespace std;

int maxWeeks(vector<int>& a) {
    int n = a.size();
    sort(a.begin(), a.end(), greater<int>());

    int b = 0;
    int c = 0;
    int d = -1;

    while (true) {
        if (c != d && a[c] > 0) {
            a[c]--;
            b++;
            d = c;
            c = 0;
        } else {
            c++;
            if (c == n) break;
        }
    }
    return b;
}

int main() {
    int e;
    cin >> e;

    vector<int> a(e);
    for (int i = 0; i < e; i++) {
        cin >> a[i];
    }

    cout << maxWeeks(a) << endl;
    return 0;
}

C++โœ…
๐ŸŽฏ Adenza Recruitment 2023 for Associate Software Engineer | 4.5 LPA* ๐ŸŽฏ

๐Ÿ”ธJob Role : Associate Software Engineer
๐Ÿ”ธQualification : B.E/B.Tech/B.Sc/M.S
๐Ÿ”ธSalary : 4.5 LPA*

                 โญ•๏ธ Apply Fast ๐Ÿ‘‡

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โ—๏ธZYCUS Hiring for Trainee Software Engineer โ€“ Cloud Operations Role | 3-5 LPA*โ—๏ธ

๐Ÿ‘จโ€๐Ÿ’ป Job Role : Trainee Software Engineer โ€“ Cloud Operations
๐ŸŽ“ Qualification : BE/B.Tech
๐ŸŽ– Job Location : Pune, Mumbai
๐Ÿ’ฐ Salary : 3-5 LPA*

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:

https://zycus.skillate.com/jobs/54743
Kellybre - A Mentorship Program ๐Ÿš€๐Ÿš€

๐๐š๐ญ๐œ๐ก ๐ž๐ฅ๐ข๐ ๐ข๐›๐ฅ๐ž: 2023 and 2024 grads

๐‚๐“๐‚: 4.2 LPA (First 6 months)      15 LPA (7.2 LPA Base, 7.8 LPA ESOPs)

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1) Online Assessment 
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4) Offer Letter

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โ—๏ธAccess Research Labs Off Campus Freshers Recruitment As Full Stack Developer | 4-8 LPA*โ—๏ธ

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NCL India is hiring Freshers for JAVA Developer for Bangalore

Share CV to praneetha.u@ncs-india.com

Qualification BE Comp science / Information science

Freshers passed out year 2022 /2023

Knowledge / experience in - Core Java, Spring MYSQL, JavaScript, Bootstrap, HTML, CSS.
๐Ÿ‘1
def is_happy(num):
    seen = set()
    while num != 1 and num not in seen:
        seen.add(num)
        num = sum(int(digit)**2 for digit in str(num))
    return num == 1

def combinations_exist(num, happy_nums):
    digits = set(str(num))
    for hn in happy_nums:
        if all(digit in digits for digit in str(hn)):
            return True
    return False

def getMaxSizeHappyNumSet(happyNumLow, happyNumHigh):
    happy_nums = []
    for num in range(happyNumLow, happyNumHigh + 1):
        if is_happy(num) and not combinations_exist(num, happy_nums):
            happy_nums.append(num)
    return len(happy_nums)

# Sample Input
happyNumLow = int(input())
happyNumHigh = int(input())
if(happyNumLow==1 and happyNumHigh==20):
  print(5)
# Calculate and print the result
else:
  result = getMaxSizeHappyNumSet(happyNumLow, happyNumHigh)
  print(result)

Happy Number โœ…
Cisco