merge array infosys

Maximum Capacity of a Compartment

given a string of size N and array of size M do M operations ... Infosys

vector<int> solve(string s)
{
int l = S.length();
vector<int> lhs(l,0);
vector<int> rhs(l,0);
if(l<1)
return 0;
if(S[0] == '1')
lhs[0] = 1;
if(S[l-1] == '1')
rhs[l-1] = 1;
for(int i=1;i<l;i++)
{
if(S[i] == '1')
lhs[i] = lhs[i-1] + 1;
}
for(int i=l-2;i>=0;i--)
{
if(S[i] == '1')
rhs[i] = rhs[i+1] + 1;
}
int max_ = 0;
for(int i=K-1;i<l;i++)
{
int j = i - (K-1);
int ll = 0,rr = 0;
if(j-1 < 0)
ll = 0;
else
ll = lhs[j-1];
if(i+1>= l)
rr = 0;
else
rr = rhs[i+1];
if(max_ < (ll+rr+K))
max_ = (ll+rr+K);
}
return max_;
}

Vikings solution

2✅
IBM

Special triplets
6 testcases passing

//172. Factorial Trailing Zeroes

def numSubarrayProductLessThanK(self, nums, k):
prod = 1
ans = left = 0
right =0
while right<len(nums):
prod*=nums[right]

while left<=right and prod>=k:
prod/=nums[left]
left+=1
ans+=right-left+1
right+=1

return ans

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Reminder✨

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U can do it 🌻

int diff_primes_in_ranges(int input1, int intput2)
{
int ans = 0;
int i, j, flag;
for (i = input1; i <= intput2; i++)
{
if (i == 1 || i == 0)
continue;
flag = 1;
for (j = 2; j <= i / 2; ++j)
{
if (i % j == 0)
{
flag = 0;
break;
}
}
if (flag == 1)
ans++;
}
return ans;
}


C++✅
KPIT