๐—–๐—ฆ ๐—”๐—น๐—ด๐—ผ ๐Ÿ’ป ๐ŸŒ ใ€Ž๐—–๐—ผ๐—บ๐—ฝ๐—ฒ๐˜๐—ถ๐˜๐—ถ๐˜ƒ๐—ฒ ๐—ฃ๐—ฟ๐—ผ๐—ด๐—ฟ๐—ฎ๐—บ๐—บ๐—ถ๐—ป๐—ดใ€
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๐Ÿ”ฐAuthentic Coding Solutions(with Outputs)
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๐—–๐—ฆ ๐—”๐—น๐—ด๐—ผ ๐Ÿ’ป ๐ŸŒ ใ€Ž๐—–๐—ผ๐—บ๐—ฝ๐—ฒ๐˜๐—ถ๐˜๐—ถ๐˜ƒ๐—ฒ ๐—ฃ๐—ฟ๐—ผ๐—ด๐—ฟ๐—ฎ๐—บ๐—บ๐—ถ๐—ป๐—ดใ€
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#include <bits/stdc++.h>
using namespace std;
#define ll long long
class SegmentTree {
private:
    vector<ll> t;
    ll n;
    void upd(ll i, ll v, ll x, ll s, ll e) {
        if (s == e) {
            t[x] += v;
        } else {
            ll m = (s + e) / 2;
            if (i <= m) {
                upd(i, v, 2 * x, s, m);
            } else {
                upd(i, v, 2 * x + 1, m + 1, e);
            }
            t[x] = t[2 * x] + t[2 * x + 1];
        }
    }
    ll qry(ll l, ll r, ll x, ll s, ll e) {
        if (r < s || e < l) return 0;
        if (l <= s && e <= r) return t[x];
        ll m = (s + e) / 2;
        ll left = qry(l, r, 2 * x, s, m);
        ll right = qry(l, r, 2 * x + 1, m + 1, e);
        return left + right;
    }

public:
    SegmentTree(ll sz) : n(sz) {
        t.resize(4 * n, 0);
    }

    void upd(ll i, ll v) {
        upd(i, v, 1, 0, n - 1);
    }

    ll qry(ll l, ll r) {
        return qry(l, r, 1, 0, n - 1);
    }
};

vector<ll> solve(ll n, vector<ll>& a, ll q, vector<ll>& qrs) {
    vector<ll> res;
    SegmentTree st(n);
    vector<ll> b = a;
    sort(b.begin(), b.end());
    unordered_map<ll, ll> mp;
    for (ll i = 0; i < n; ++i) mp[b[i]] = i;

    auto cnt_inv = [&]() -> ll {
        ll inv = 0;
        for (ll i = n - 1; i >= 0; --i) {
            ll idx = mp[a[i]];
            inv += st.qry(0, idx - 1);
            st.upd(idx, 1);
        }
        for (ll i = 0; i < n; ++i) {
            st.upd(mp[a[i]], -1);
        }
        return inv;
    };

    for (ll x : qrs) {
        reverse(a.begin(), a.begin() + x);
        res.push_back(cnt_inv());
    }
    return res;
}


Reverse Inversion โœ…
๐—–๐—ฆ ๐—”๐—น๐—ด๐—ผ ๐Ÿ’ป ๐ŸŒ ใ€Ž๐—–๐—ผ๐—บ๐—ฝ๐—ฒ๐˜๐—ถ๐˜๐—ถ๐˜ƒ๐—ฒ ๐—ฃ๐—ฟ๐—ผ๐—ด๐—ฟ๐—ฎ๐—บ๐—บ๐—ถ๐—ป๐—ดใ€
Photo
#include <bits/stdc++.h>
using namespace std;
struct ST {
    int n;
    vector<long long> t, lz;
    ST(int sz) {
        n = sz;
        t.resize(4 * n, 0);
        lz.resize(4 * n, 0);
    }
    void p(int nd, int s, int e) {
    if (lz[nd] != 0) {
    t[nd] += lz[nd];
    if (s != e) {
    lz[2 * nd + 1] += lz[nd];
    lz[2 * nd + 2] += lz[nd];
    }
    lz[nd] = 0;
    }
    }
    void ru(int nd, int s, int e, int l, int r, long long v) {
    p(nd, s, e);
    if (s > r || e < l) return;
    if (s >= l && e <= r) {
    lz[nd] += v;
    p(nd, s, e);
    return;
    }
    int m = (s + e) / 2;
    ru(2 * nd + 1, s, m, l, r, v);
    ru(2 * nd + 2, m + 1, e, l, r, v);
    t[nd] = max(t[2 * nd + 1], t[2 * nd + 2]);
    }
long long rq(int nd, int s, int e, int l, int r) {
p(nd, s, e);
if (s > r || e < l) return 0;
if (s >= l && e <= r) return t[nd];
int m = (s + e) / 2;
return max(rq(2 * nd + 1, s, m, l, r), rq(2 * nd + 2, m + 1, e, l, r));
}

void u(int l, int r, long long v) {
ru(0, 0, n - 1, l, r, v);
    }

    long long q(int l, int r) {
        return rq(0, 0, n - 1, l, r);
    }
};

long long SkillUpdate(int n, int q, vector<tuple<int, int, int>>& u) {
    ST st(n);
    vector<long long> mx(q, 0);
    for (auto& [l, r, x] : u) {
        st.u(l - 1, r - 1, x);
    }

    for (int i = 0; i < q; i++)
    {
        auto [l, r, x] = u[i];
        st.u(l - 1, r - 1, -x);
        mx[i] = st.q(0, n - 1);
        st.u(l - 1, r - 1, x);
    }

    return *min_element(mx.begin(), mx.end());
}

Minimize and Maximumโœ…
#include <bits/stdc++.h>
using namespace std;
#define ll long long
int main(){
     int n;
     cin>>n;
     vector<int>arr(n);
     for(int i=0;i<n;i++)cin>>arr[i];
     vector<int>presum(n);
     presum[0]=arr[0];
     for(int i=1;i<n;i++)presum[i]=presum[i-1]+arr[i];
     vector<int>dp(n);
     vector<int>val(n);
     dp[0]=1;
     val[0]=arr[0];

     for(int i=1;i<n;i++){
       
        int l=0,h=i;
        int ind=0;
        while(h>=l){
          int mid=(l+h)/2;
          int sum= presum[i]- (mid>0?presum[mid-1]:0);
          int prev = (mid>0?val[mid-1]:0);
          if(sum>=prev){
            ind=mid;
            l=mid+1;
          }
          else h=mid-1;
        }
        if(ind==0){
          dp[i]=1;
          val[i]=presum[i];
        }
        else{
          dp[i]=dp[ind-1]+1;
          val[i]=presum[i]-presum[ind-1];
        }
     }
     cout<<dp.back();
}
 
Operate the subarrayโœ