def maxProfit(profits, skillsForJobs, skillsOfCandidates):
    from functools import lru_cache

    j_num = len(profits)
    c_num = len(skillsOfCandidates)
    s_num = len(skillsForJobs[0])

    def canHire(c, j):
        return all(skillsOfCandidates[c][k] or not skillsForJobs[j][k] for k in range(s_num))

    can_handle_job = [[canHire(cand, job) for job in range(j_num)] for cand in range(c_num)]

    @lru_cache(None)
    def dp(m, j_idx):
        if j_idx == j_num:
            return 0
        
        max_profit = dp(m, j_idx + 1)  
        for c in range(c_num):
            if can_handle_job[c][j_idx] and not (m & (1 << c)):
                profit = profits[j_idx] + dp(m | (1 << c), j_idx + 1)
                max_profit = max(max_profit, profit)
        return max_profit

    return dp(0, 0)  

Max Profit
Trilogy ✅

#include <iostream>
#include <vector>
#include <string>

class DisjointSet {
    std::vector<int> parent, rank;
    std::vector<bool> parity;
public:
    DisjointSet(int n) : parent(n), rank(n, 0), parity(n, false) {
        for (int i = 0; i < n; i++) parent[i] = i;
    }
   
    int find(int x) {
        if (parent[x] != x) {
            int p = parent[x];
            parent[x] = find(p);
            parity[x] = parity[x] ^ parity[p];
        }
        return parent[x];
    }
   
    bool unite(int x, int y, bool diff) {
        int px = find(x), py = find(y);
        if (px == py) return (parity[x] ^ parity[y]) == diff;
        if (rank[px] < rank[py]) std::swap(px, py);
        parent[py] = px;
        parity[py] = parity[x] ^ parity[y] ^ diff;
        if (rank[px] == rank[py]) rank[px]++;
        return true;
    }
};

std::vector<std::string> solve(const std::vector<std::vector<int>>& A) {
    int maxDim = 0;
    for (const auto& query : A) {
        maxDim = std::max(maxDim, std::max(query[0], query[1]));
    }
    maxDim++;

    std::vector<std::string> result;
    DisjointSet ds(2 * maxDim);

    for (const auto& query : A) {
        int x = query[0], y = query[1];
        int x_val = query[2], y_val = query[3];
       
        bool diff = (x_val != y_val);
        if (ds.unite(x, maxDim + y, diff)) {
            result.push_back("Yes");
        } else {
            result.push_back("No");
        }
    }
   
    return result;
}

int main() {
    std::vector<std::vector<int>> A1 = {{1, 1, 1, 1}, {1, 2, 1, -1}};
    std::vector<std::vector<int>> A2 = {{1, 1, 1, 1}, {1, 2, 1, 1}, {2, 2, 1, 1}, {2, 1, 1, -1}};
   
    auto result1 = solve(A1);
    auto result2 = solve(A2);
   
    std::cout << "Output 1: ";
    for (const auto& s : result1) std::cout << s << " ";
    std::cout << "\nOutput 2: ";
    for (const auto& s : result2) std::cout << s << " ";
    std::cout << std::endl;
   
    return 0;
}

Matrice
Trilogy ✅

#include <vector>
#include <iostream>

using namespace std;

vector<int> solution(int riverWidth, int maxJump, vector<int> platformSizes) {
    int N = 1e5 + 5;
    int maxJumpTemp, totalPlatforms, currentPlatform, prefixSum[N], platformLength[N];
    vector<int> answer(riverWidth, 0); // Initialize answer with 0 and size riverWidth
   
    totalPlatforms = riverWidth;
    currentPlatform = platformSizes.size();
    maxJumpTemp = maxJump;
   
    for (int i = 1; i <= currentPlatform; i++) {
        prefixSum[i] = platformSizes[i - 1];
        platformLength[i] = prefixSum[i];
    }
   
    for (int i = 1; i <= currentPlatform; i++) {
        prefixSum[i] += prefixSum[i - 1];
    }
   
    int currentIndex = 1, gap = 1, maxReach = 0;
    for (int j = 1; j <= currentPlatform; ) {
        if (currentIndex - 1 + prefixSum[currentPlatform] - prefixSum[j - 1] == totalPlatforms) {
            int start = currentIndex;
            for (; currentIndex < platformLength[j] + start; currentIndex++)
                answer[currentIndex - 1] = j, maxReach = currentIndex;
            j++;
            gap = 1;
        } else if (gap < maxJumpTemp) {
            gap++;
            currentIndex++;
            continue;
        } else if (gap == maxJumpTemp) {
            int start = currentIndex;
            for (; currentIndex < platformLength[j] + start; currentIndex++)
                answer[currentIndex - 1] = j, maxReach = currentIndex;
            j++;
            gap = 1;
        }
    }
   
    if (totalPlatforms + 1 - maxReach > maxJumpTemp) {
        return {-1};
    }
   
    return answer;
}

int main() {
    int riverWidth = 7;
    int maxJump = 2;
    vector<int> platformSizes = {1, 2, 1};

    vector<int> result = solution(riverWidth, maxJump, platformSizes);
    for (int num : result) {
        cout << num << " ";
    }
    cout << endl;

    return 0;
}

River vala mario✅
Trilogy

Quest Global

Off Campus Recruitment Drive
Degree: BE / B.Tech / MCA
Year of Completion: 2023 / 2024

https://forms.office.com/pages/responsepage.aspx?id=pCOqk-FuAUaFkjGnYkiTWSEIpM2LK_JOkjumpG3xVgxUMjQ1MVQ1VkkyQTU1MFpXOElTNFJXMlQ2Sy4u

Taskus is hiring Junior Developer

For 2021, 2022, 2023 grads
Location: Chennai

https://jobs.eu.humanly.io/jobs/bd25b188-b5c7-4db9-baa1-71db0f3601b2?source=LinkedIn

Coakroach Labs  International Opportunity  fresh Grads

Role - Backend Engineer
Exp - Fresher
Location- Toronto

Link - https://boards.greenhouse.io/cockroachlabs/jobs/6145671

Spinny Hiring

Interns for Project Engineering profile at our headquarters at Gurugram.

Internship duration: 3-4 months

★Perks Provided on completion:
💡Letter Of Appreciation
💡Letter Of Recommendation Stipend
💡PPO (Based on the performance)

Points of necessary consideration:
- Must be 2023 pass out from Civil Engineering Courses.
- Must have experience with project management.
- Get on board with a team of extragavant professionals and have the necessary boost up to your career.

💻NOTE: Working Assets and Laptops will be provided.

Interested candidates can share their CV at the email address provided below: suryansh.tiwari@spinny.com

Civil Engineering students can apply

🚀Aryson Technologies has launched multiple paid Internship program 🚀

⏳Duration: 6 months
💵Stipend: Rs 5000
📍 Location: Sector 58, Noida

- Software Tester
- Web Designing
- Graphic Designing
- Technical Writer
- SEO

Share your updated resume to:
milanhrdept@arysontechnologies.com

Tech Solutions Hiring
Both freshers/experienced candidates

📌QA Engineer Internship
-Freshers Eligible
-B. Tech or similar field

📌For Associate role QA
Exp: 1 - 3 years

Send your updated resume to:
tejashree.patil@techolution.com

📌Hiring for React & React Native Interns

Stipend: 50k - 60k
Location: Bangalore HSR(5 days WFO)

Interested one share their resume to:
careers@betterhalf.ai

👉Awesome Opportunity 👈

📌Mindwebtree hiring for the following positions:

.NET Developer
PHP Developer
Angular Developer

Eligibility Criteria:
BCA, MCA, or BTech graduates only.
Immediate joiners preferred.

send your CV to hr@mindwebtree.com

Uniwave Software is Hiring for Fresher's

Job Role: Software Engineer

Qualification: BE/B.Tech - CS/IT

Passout: 2023-24 Only with 60% criteria(10th, 12th & Graduation)

Location: Pune
Package: 3.5-4.5 LPA
Skills: Java, Python, Dot Net, SQL, NodeJS

👉Interested candidates can share cv at:
naresh@unijobsolution.com

TEKsystems is hiring freshers for Pune Location.

Skill : L1 Generalist - Support role
Shifts: Night shift( Cab facilities will be provided).
Experience 0-1year
Interview - F2F round (Post selection of 1st round.)

Skills required:
i) Excellent communication skills
ii) Good analytical knowledge

Work Location : Pune (Candidates from Pune or nearby places only)
Education Background: Graduate (Btech / BE / BCA /B.Sc )

If any referrals needed please reach out to pbohara@teksystems.com

Entrust Walkin Interview | Hiring Trainee Software Engineer ❤️❤️❤️

Detailed Eligibility:

Computer Science Graduates M.Sc / MCA / B.E / B.Tech (Computer Science)
2024 Passed outs Only
Experience: Freshers
Shift: General Shift (9 AM to 6 PM)

Walk In Procedure
Step 1: While coming for the Interview, please bring the interview call letter, Resume & Original Govt. ID Proof (No color xerox).
Step 2: Once you enter DLF Premises, you must register in the above link to enter the DLF Premises.

Apply from here (Direct Link): https://tinyurl.com/5xz9str3