#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main() {
    int T;
    cin >> T;
    while (T--) {
        int n;
        cin >> n;
        vector<int> A(n);
        for (int i = 0; i < n; ++i) {
            cin >> A[i];
        }
        vector<int> even, odd;
        for (int i = 0; i < n; ++i) {
            if (A[i] % 2 == 0) {
                even.push_back(A[i]);
            } else {
                odd.push_back(A[i]);
            }
        }
        sort(even.begin(), even.end());
        sort(odd.begin(), odd.end());

        long long validPairs = 0;

        for (int i = 0; i < odd.size(); ++i) {
            validPairs += even.end() - upper_bound(even.begin(), even.end(), odd[i]);
        }

        for (int i = 0; i < even.size(); ++i) {
            validPairs += odd.end() - upper_bound(odd.begin(), odd.end(), even[i]);
        }

        cout << validPairs << endl;
    }
    return 0;
}

Pair Validity ✅

Tech Mahindra - Ahmedabad, Fresher Hiring - Manual Testing


https://docs.google.com/forms/d/e/1FAIpQLSdBZCPr-OzAxa1_mwOzuPU5v2PB8T5tg9J1_QqR6pzE94AHiA/viewform

#include <iostream>
#include <unordered_set>
#include <string>

using namespace std;

bool isSplendid(string num) {
    unordered_set<char> splendid_digits = {'0', '1', '6', '8', '9'};
    unordered_map<char, char> rotation_map = {{'0', '0'}, {'1', '1'}, {'6', '9'}, {'8', '8'}, {'9', '6'}};
    string rotated_num = "";
    for (int i = num.size() - 1; i >= 0; i--) {
        if (splendid_digits.find(num[i]) == splendid_digits.end()) {
            return false;
        }
        rotated_num += rotation_map[num[i]];
    }
    return num == rotated_num;
}

int countSplendidNumbers(string low, string high) {
    int count = 0;
    for (int i = stoi(low); i <= stoi(high); i++) {
        if (isSplendid(to_string(i))) {
            count++;
        }
    }
    return count;
}

int main() {
    string low, high;
    cin >> low >> high;
    cout << countSplendidNumbers(low, high) << endl;
    return 0;
}

Natasha's hobby ✅

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Interview Mode - Face to Face in Kolkata.
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Please share the resume in the below mentioned format.

Name
Highest Education
Year of Pass out
Percentage achieved
Current location
Degree certificate received (Yes/No)
Available for Face-to-Face interview (Yes/No)
Can join immediately (Yes/No)

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If your profile matches kindly share your resumes to info@codingking.in

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Application Deadline: 16th June, 2024

Pre-Requisite: Must be currently enrolled in an Undergraduate program.

ReachInbox is hiring Backend Intern

For 2023, 2024 grads

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Revature Recruitment 2024 Details :
Job Role
Software Engineer
Education
BE/B.Tech/MCA/MSC
Batch
2024/2023
CTC : 4 to 6 Lpa

Apply link ;

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Closest to Zero ✅
Wiley Edge

Pair of integers ✅
IBM

Company Name: WayFair

🛄 Job Title: Software Engineering Intern
✍🏻 YOE: 2025 and 2026 grads


➡️ Apply: https://www.wayfair.com/careers/job/software-engineering-intern/7063610002/apply

Please do share in your college grps and in case you are applying please react on this post:) 😇❤️

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MOD = 10**9 + 7

def consistent_subsequences(N):
    dp_no_consec = [0] * (N + 1)
    dp_with_consec = [0] * (N + 1)
   
    dp_no_consec[1] = 1 

    for i in range(2, N + 1):
        dp_no_consec[i] = (dp_no_consec[i - 1] + dp_with_consec[i - 1] + 1) % MOD
        dp_with_consec[i] = dp_no_consec[i - 1] % MOD

    result = (dp_no_consec[N] + dp_with_consec[N]) % MOD
    return result

Consistent Data ✅

One Block ✅
Wiley Edge

Company Name: IndMoney

🛄 Job Title: Software Engineer
✍🏻 YOE: 2022 and 2023 grads

➡️ Apply: https://docs.google.com/forms/d/e/1FAIpQLScaucx8sC5fX-saowlTitrUB4RUXyXT6UkQoH79Ef0RRAohAg/viewform

Please do share in your college grps and in case you are applying please react on this post:) 😇❤️