📌Monk Commerce is hiring for Frontend Engineer SDE I - Remote (0-2 years)
Apply here:
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Avalara Hiring Fresher For Associate Analyst                        
Location: Pune                    
Qualification: MBA                       
Work Experience: Fresher - 2 Years                 
Salary: 6 LPA 
                               
Apply Link: https://careers.avalara.com/jobs/12839?lang=en-us&iis=Job+Board&iisn=LinkedIn

int solve(int n, int k, int a) {
    int ans = (k + a - 1) % n;
    if (ans == 0) {
        ans = n;
    }
    return ans;
}

Card ✅
Flipkart

def last_candy_recipient(N, K, A):
    remaining_candies = K % N
    last_recipient = (A + remaining_candies - 1) % N
    if last_recipient == 0:
        return N
    else:
        return last_recipient

Card ✅

#include <bits/stdc++.h>
using namespace std;

#define ll long long
#define maxn 1000005
#define inf 1e9

string ff(ll a, ll b, ll c, ll d) {
    ll kit = (b - a + 1) * (d - c + 1);
    ll kat = (b - a + 1) * (d - c);
    return (kat > kit / 2) ? "YES" : "NO";
}

int main() {
    ll a, b, c, d;
    cin >> a >> b;
    cin >> c >> d;
    cout << ff(a, b, c, d) << endl;
    return 0;
}

Guess the full form ✅
Flipkart

def probability_comparison(L1, R1, L2, R2):
    alice_wins = 0
    for i in range(L1, R1+1):
        for j in range(L2, R2+1):
            if i > j:
                alice_wins += 1
   
    total_outcomes = (R1 - L1 + 1) * (R2 - L2 + 1)
   
    if alice_wins > total_outcomes / 2:
        return "YES"
    else:
        return "NO"
L1, R1, L2, R2 = map(int, input().split())
print(probability_comparison(L1, R1, L2, R2))

Prediction ✅

def final_card_person(N, K, A):
    remainder = K % N
    final_position = (A - 1 + remainder) % N
    if final_position == 0:
        final_position = N
    return final_position

Cards and Party ✅

def decode_secret_code(S, N):
    if N == 1:
        return S

    rows = [''] * N
    row = 0
    down = True
   
    for char in S:
        rows[row] += char
       
        if row == 0:
            down = True
        elif row == N - 1:
            down = False
           
        if down:
            row += 1
        else:
            row -= 1

    secret_code = ''.join(rows)
    return secret_code

S = input()
N = int(input())
result = decode_secret_code(S, N)
print(result)

Flipkart ✅

#include <iostream>
#include <vector>

using namespace std;

string findPassword(string s, int n) {
    if (n == 1)
        return s;

    vector<vector<char>> zigzag(n, vector<char>());
    bool down = true;
    int row = 0;

    for (char c : s) {
        zigzag[row].push_back(c);

        if (down)
            row++;
        else
            row--;

        if (row == 0 || row == n - 1)
            down = !down;
    }

    string password;
    for (int i = 0; i < n; i++) {
        for (char c : zigzag[i]) {
            password += c;
        }
    }

    return password;
}

int main() {
    string s;
    int n;

    cin >> s >> n;

   
    cout << findPassword(s, n) << endl;

    return 0;
}

Flipkart✅

#include<bits/stdc++.h>
using namespace std;

int main() {
    int n;
    cin >> n;
    vector<int> arr(n);
    for(int i = 0; i < n; i++) {
        cin >> arr[i];
    }
    stack<int> s;
    vector<int> nwe(n, -1);
    for(int i = 0; i < n; i++) {
        while(!s.empty() && arr[s.top()] > arr[i]) {
            nwe[s.top()] = arr[i];
            s.pop();
        }
        s.push(i);
    }
    for(int i = 0; i < n; i++) {
        cout << nwe[i] << " ";
    }
    cout << endl;
    return 0;
}

#include <iostream>

using namespace std;

int maxChocolateCakes(int A, int P) {
    int totalPieces = A * 3 + P;
    return totalPieces / 2;
}

int main() {
    int A, P;
    cin >> A >> P;
   
    int maxCakes = maxChocolateCakes(A, P);
   
    cout << maxCakes << endl;
   
    return 0;
}

Chocoland ✅

MOD = 998244353
def count_pairs(N):
    count = 0
    b = N
    for a in range(N + 1):
        while b > 0 and (a & b) > N:
            b -= 1
        count = (count + max(b - a + 1, 0)) % MOD
    return count
N = int(input())
print(count_pairs(N))

Flipkart ✅

Rope pair length ✅

Omind is hiring Backend Engineer Intern

For 2025, 2024 grads

Check out this job at Omind: https://www.linkedin.com/jobs/view/3917296438

ZS is Hiring 2023/2024 are eligible

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