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Company - Amazon
Role - Graduate Analyst
Batch - 2024/2023/2022/2021
Location - Pune
https://grow.almabetter.com/auth/signup?utm_source=shareearn&utm_content=job_board&redirectTo=https%3A%2F%2Fgrow.almabetter.com%2Fjob-board%2F8225ad27-3b4a-4303-bf8e-499208f36de7&referralCode=6GL9EW
Role - Graduate Analyst
Batch - 2024/2023/2022/2021
Location - Pune
https://grow.almabetter.com/auth/signup?utm_source=shareearn&utm_content=job_board&redirectTo=https%3A%2F%2Fgrow.almabetter.com%2Fjob-board%2F8225ad27-3b4a-4303-bf8e-499208f36de7&referralCode=6GL9EW
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Company Name : Western Digital
Role : Software Engineer
Batch : 2024 passouts
Link : https://jobs.smartrecruiters.com/WesternDigital/743999978560376-engineer-software-development-engineering-apps-be-2024-pass
Role : Software Engineer
Batch : 2024 passouts
Link : https://jobs.smartrecruiters.com/WesternDigital/743999978560376-engineer-software-development-engineering-apps-be-2024-pass
Western Digital
Western Digital is looking for a Engineer, Software Development Engineering (Apps)- BE - 2024 Pass in Bengaluru, India
Job DescriptionESSENTIAL DUTIES AND RESPONSIBILITIESParticipate in firmware development which is done in embedded C++ on multiple environments using latest standards C++14/17: FPGA, Simulator, eHD...
๐1
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๐ Visa is hiring for the role of SDE
Experience: 0 - 1 years
Expected Salary: 18 - 20 LPA
๐Apply Link -
https://jobs.smartrecruiters.com/Visa/743999979034783-sw-engineer?trid=463ac537-35c8-4256-8fe4-47ea285de0a6
Experience: 0 - 1 years
Expected Salary: 18 - 20 LPA
๐Apply Link -
https://jobs.smartrecruiters.com/Visa/743999979034783-sw-engineer?trid=463ac537-35c8-4256-8fe4-47ea285de0a6
Smartrecruiters
Visa SW Engineer | SmartRecruiters
New Payment Flows (NPF) divisionโs charter is to capture new sources of money movement through card and non-card flows, including Visa Business Solutions, Government Solutions and Visa Direct which presents an enormous growth opportunity. Our team bringsโฆ
๐1
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๐Apply for QA - Manual Engineer - Level 1:
https://career.teksun.com/jobs/qa-manual-engineer-level-1-freshers
https://career.teksun.com/jobs/qa-manual-engineer-level-1-freshers
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Full Stack Developer intern At Orangewood
Batch :2024/2025
https://orangewood.keka.com/careers/jobdetails/39183
Batch :2024/2025
https://orangewood.keka.com/careers/jobdetails/39183
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๐ Alight is Hiring for 2024! ๐
๐ Role: Financial Analyst I
๐ Job Location: Gurgaon, Haryana
๐ Experience: 0 - 2 years
๐ Qualification: B.Com, M.Com, BBA, MBA, CA/CS/ICWA
๐ Link- https://careers.alight.com/us/en/job/ALIGUSR28009EXTERNALENUS/Financial-Analyst-I
All the best ๐๐
๐ Role: Financial Analyst I
๐ Job Location: Gurgaon, Haryana
๐ Experience: 0 - 2 years
๐ Qualification: B.Com, M.Com, BBA, MBA, CA/CS/ICWA
๐ Link- https://careers.alight.com/us/en/job/ALIGUSR28009EXTERNALENUS/Financial-Analyst-I
All the best ๐๐
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Linkedin
Sign Up | LinkedIn
500 million+ members | Manage your professional identity. Build and engage with your professional network. Access knowledge, insights and opportunities.
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๐Ericsson is hiring for Software Developer
Expected Salary: 6-12 LPA
๐Apply here: https://jobs.ericsson.com/careers/job/563121759534531
Expected Salary: 6-12 LPA
๐Apply here: https://jobs.ericsson.com/careers/job/563121759534531
Ericsson
Software Developer | Bangalore,Karnataka,India | Ericsson
- Cloud Technologies (Kubernetes, Docker, AWS, Container, Microservices, spring boot). - Security. - DevSecOps. - Front End Development. - Security Reliability Model (SRM). - Application and Product security. - Agile methodology. - Software Vulnerabilityโฆ
long maxSpanRelation(int idx, vector<int>& arr1, long mini, vector<int>& arr2, long sum, int k, vector<vector<long>>& dp) {
if(idx == arr1.size()) {
if(k == 0) {
return mini * sum;
}
return 0;
}
if(dp[idx][k] != -1) return dp[idx][k];
long pick = maxSpanRelation(idx + 1, arr1, min(mini, (long)arr1[idx]), arr2, sum + arr2[idx], k - 1, dp);
long notPick = maxSpanRelation(idx + 1, arr1, mini, arr2, sum, k, dp);
return dp[idx][k] = max(pick, notPick);
}
long getMaxSpanRelation(vector<int>& arr1, vector<int>& arr2, int k) {
int n = arr1.size();
vector<vector<long>> dp(n, vector<long>(k + 1, -1));
return maxSpanRelation(0, arr1, 5001, arr2, 0, k, dp);
}
int main() {
vector<int> arr1 = {1, 2, 3};
vector<int> arr2 = {4, 5, 6};
int k = 2;
cout << getMaxSpanRelation(arr1, arr2, k) << endl;
return 0;
}
Maximum Span Relation โ
if(idx == arr1.size()) {
if(k == 0) {
return mini * sum;
}
return 0;
}
if(dp[idx][k] != -1) return dp[idx][k];
long pick = maxSpanRelation(idx + 1, arr1, min(mini, (long)arr1[idx]), arr2, sum + arr2[idx], k - 1, dp);
long notPick = maxSpanRelation(idx + 1, arr1, mini, arr2, sum, k, dp);
return dp[idx][k] = max(pick, notPick);
}
long getMaxSpanRelation(vector<int>& arr1, vector<int>& arr2, int k) {
int n = arr1.size();
vector<vector<long>> dp(n, vector<long>(k + 1, -1));
return maxSpanRelation(0, arr1, 5001, arr2, 0, k, dp);
}
int main() {
vector<int> arr1 = {1, 2, 3};
vector<int> arr2 = {4, 5, 6};
int k = 2;
cout << getMaxSpanRelation(arr1, arr2, k) << endl;
return 0;
}
Maximum Span Relation โ
typedef long ll;
ll getmaxfreq(int connect_nodes, vector<int> connect_from, vector<int> connect_to, vector<int> connect_val, int k) {
vector<vector<ll>> adj(connect_nodes + 1);
for (int i = 0; i < connect_from.size(); i++) {
ll u = connect_from[i], v = connect_to[i];
adj[u].push_back(v);
adj[v].push_back(u);
}
auto dfs = [&](ll curr, ll prv, auto && dfs)->pair<ll, ll> {
ll tmp = connect_val[curr - 1];
pair<ll, ll> ans = {tmp, tmp};
for (auto& x : adj[curr]) {
if (x == prv) continue;
auto tmp = dfs(x, curr, dfs);
ans.second += tmp.second;
ans.first += tmp.first;
}
ans.first = max(ans.first, -k);
return ans;
};
return dfs(1, 0, dfs).first;
}
UI Path โ
ll getmaxfreq(int connect_nodes, vector<int> connect_from, vector<int> connect_to, vector<int> connect_val, int k) {
vector<vector<ll>> adj(connect_nodes + 1);
for (int i = 0; i < connect_from.size(); i++) {
ll u = connect_from[i], v = connect_to[i];
adj[u].push_back(v);
adj[v].push_back(u);
}
auto dfs = [&](ll curr, ll prv, auto && dfs)->pair<ll, ll> {
ll tmp = connect_val[curr - 1];
pair<ll, ll> ans = {tmp, tmp};
for (auto& x : adj[curr]) {
if (x == prv) continue;
auto tmp = dfs(x, curr, dfs);
ans.second += tmp.second;
ans.first += tmp.first;
}
ans.first = max(ans.first, -k);
return ans;
};
return dfs(1, 0, dfs).first;
}
UI Path โ
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๐callprep.io is Hiring for the role of Backend Software Engineer (Intern)
Batch: 2022/2023/2024/2025
Stipend: 15,000 โ 20,000
Location: Remote
๐Apply Link: https://wellfound.com/l/2A8XfR
Batch: 2022/2023/2024/2025
Stipend: 15,000 โ 20,000
Location: Remote
๐Apply Link: https://wellfound.com/l/2A8XfR