๐—–๐—ฆ ๐—”๐—น๐—ด๐—ผ ๐Ÿ’ป ๐ŸŒ ใ€Ž๐—–๐—ผ๐—บ๐—ฝ๐—ฒ๐˜๐—ถ๐˜๐—ถ๐˜ƒ๐—ฒ ๐—ฃ๐—ฟ๐—ผ๐—ด๐—ฟ๐—ฎ๐—บ๐—บ๐—ถ๐—ป๐—ดใ€
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public class Main {
    public static String StringChallenge(String str) {
        StringBuilder result = new StringBuilder();
        int count = 1;
        char prev = str.charAt(0);
        for (int i = 1; i < str.length(); i++) {
            char current = str.charAt(i);
            if (current == prev) {
                count++;
            } else {
                result.append(count).append(prev);
                count = 1;
                prev = current;
            }
        }
        result.append(count).append(prev);

        String challengeToken = "vst3w5cpeaf";
        StringBuilder finalOutput = new StringBuilder(result.toString() + challengeToken);

        for (int i = 3; i < finalOutput.length(); i += 4) {
            finalOutput.setCharAt(i, '_');
        }

        return finalOutput.toString();
    }

String challenge โœ…
Hyderabad India
We are Hiring Security Analyst L1 @ Hyderabad: Work From Office(Cyber Towers)

Role: Security Analyst L1
Experience : Freshers(Should be trained in Cyber Security)
Certification : CEH/ECSA Certified-Preferrable
Education:- BTech/MTech(CSE/ECE/IT--2023/2022/2021)โ€”Must
Mode of Work : work from office
Total No of Positions : 2
Address: 3rd floor, Quadrant 3, Cyber towers, Hitech City Rd, HITEC City, Hyderabad, Telangana 500081

Job Description:

Desired certifications: CEH, ECSA, CompTIA+, GIAC, etc.
Understanding of Security operation center
Willing to work in 24/7 rotational shift and on call support
Understanding of Incident management, alert triaging, security monitoring
Investigate on any incidents detected and escalate to the responsible team, and ensure proper closure
Experience with SIEM tools โ€“ QRadar, Splunk, AlienVault, etc.
Understanding of network, network-security, Operating systems, and databases
Good Communication and writing skills
Ability to work in a dynamic and rapidly changing environment


You can share updated resume to the below mail ID:
vijaya.thirukolluri@uvcyber.com
import java.util.*;

public class Main {
    public static int getEncryptedSum(List<Integer> A) {
        int encryptedSum = 0;

        for (int num : A) {
            int maxDigit = getMaxDigit(num);
            encryptedSum += maxDigit;
        }

        return encryptedSum;
    }

    public static int getMaxDigit(int num) {
        int maxDigit = 0;

        while (num > 0) {
            int digit = num % 10;
            maxDigit = Math.max(maxDigit, digit);
            num /= 10;
        }

        return maxDigit;
    }

Encryption by digits โœ…
๐Ÿ‘1
๐—–๐—ฆ ๐—”๐—น๐—ด๐—ผ ๐Ÿ’ป ๐ŸŒ ใ€Ž๐—–๐—ผ๐—บ๐—ฝ๐—ฒ๐˜๐—ถ๐˜๐—ถ๐˜ƒ๐—ฒ ๐—ฃ๐—ฟ๐—ผ๐—ด๐—ฟ๐—ฎ๐—บ๐—บ๐—ถ๐—ป๐—ดใ€
Ever increasing and ever decreasing - L&T โœ…
public class Solution {

    public static int longestArraySegment(int array_length, List<Integer> arr) {
        int maxLength = 1;
        int currentLength = 1;

        for (int i = 1; i < array_length; i++) {
            if (arr.get(i) > arr.get(i - 1)) {
                currentLength++;
            } else {
                currentLength = 1;
            }
            maxLength = Math.max(maxLength, currentLength);
        }

        currentLength = 1;
        for (int i = 1; i < array_length; i++) {
            if (arr.get(i) < arr.get(i - 1)) {
                currentLength++;
            } else {
                currentLength = 1;
            }
            maxLength = Math.max(maxLength, currentLength);
        }

        return maxLength;
    }


Ever increasing and ever decreasing - L&T โœ