Biz Skills Track 1 Slot 1 Answers (TCS) ✅

1 - Respect/Listen
2-trying to network
3- Active associates/passive associates
4- all are correct
5- Meditation
6- A, D
7- Their are many criteria
8-d-it may not reduce
E- it does not outline
9- A,C,F
10-the ability to manage
11-they througly explore
12-b,c.
13-b,c,e
14-a,c,e,f
15-Observe ,design , execute
16-true
17-can take several forms
18-jennifer oversimplified
19-manager or lead encourages
20-b-insight people
C- be respectful
21-she is important but is unable
22-Globalization
24- morals
25-verbal skills
26-gender dominance
27- you may have conversations
29- mind mapping, hypothesis
31-d,f

32-culture/experience
33-twitter,LinkedIn
34-a,bd,e
35-one whose decision making
36-caterogization
37-b,e
38-attending events
39-escalations
40-a,c
41-false
42-we need to maintain
43-a,c
44-self conscientious
46- b,c
47-it help us to look
48-never end up making
50- text based networking
51-flipping a coin
52-true
53-so we can complete more
54-identifying a problem
55-b,d,e
56-b,e
57-bas that is implicit

Biz Skills Track 1 Slot 2 (3 Pm) Answers (TCS) ✅

1)false
2)a, c
Confident, accessibility
3)b
Talk about the weather
4)a
Organizational band
5)c, e, f
Reguraly c
You can get e
You can postion f
6)f
How
7)a b d
Mentor rele a
Mentor helps b
Mentor mene d
8)b
Know there sytle
9)c
Compassion
10)a b c
A every activitity a
Takes breaks b
Indify c
11)the amount of overlap
12)q)offering help raise profile
True
A
13)a d
Remote a
Quick nd eassy d
14)d
Uncertainty
15)b
Define goal
17)b
Equal opportunites

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Software Development Engineer : 9 LPA
Member of technical staff : 7 LPA
Application Engineer : 5 LPA



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Job Description-
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/*
167. Two Sum II - Input Array Is Sorted
Given a 1-indexed array of integers numbers that is already sorted in non-decreasing order, find two numbers such that they add up to a specific target number. Let these two numbers be numbers[index1] and numbers[index2] where 1 <= index1 < index2 <= numbers.length.
Return the indices of the two numbers, index1 and index2, added by one as an integer array [index1, index2] of length 2.
The tests are generated such that there is exactly one solution. You may not use the same element twice.
Your solution must use only constant extra space.
Example 1:
Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore, index1 = 1, index2 = 2. We return [1, 2].
*/
class Solution
{
public:
vector<int> twoSum(vector<int> &nums, int target)
{
int i = 0, j = nums.size() - 1;
while (i < j)
{
int sum = nums[i] + nums[j];
if (sum == target)
return {i + 1, j + 1};
else if (sum > target)
j--;
else
i++;
}
return {}; // Target not found
}
};
// Time Complexity : O(N)
// Space Complexity : O(1)



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RoutePairs
Python 3language✅(Amazon)

Findresturnets. / Diveryplan
Python 3✅(Amazon)

Approach: we need to calculate the forward route list + return route list 2nd point and we will find the maximum of the list after that I will compare the forward route list and +return list if they are equal then I will push in 1 D vector then I will push 2nd vector in answer and finally we will return 2D vector answer


Complexity Analysis:
time complexity O(N*M)
N is the size of the forward route list and return route list
space complexity O(N*M)
and here N and M is the size of our 2D vector answer

'''
Find K Closest Points to the Origin

Approach: The idea is to calculate the Euclidean distance from the origin for every given point and sort the array according to the Euclidean distance found. Print the first k closest points from the list.

Algorithm :
Consider two points with coordinates as (x1, y1) and (x2, y2) respectively. The Euclidean distance between these two points will be:

√{(x2-x1)2 + (y2-y1)2}
Sort the points by distance using the Euclidean distance formula.
Select first K points form the list
Print the points obtained in any order.


Complexity Analysis:

Time Complexity: O(n log n).
Time complexity to find the distance from the origin for every point is O(n) and to sort the array is O(n log n)
Space Complexity: O(n).
As we are making an array to store distance from the origin for each point.

'''
def deliveryPlan(allLocation, NumDeliveries):

allLocation.sort(key = lambda NumDeliveries: NumDeliveries[0]2 + NumDeliveries[1]2)

return allLocation[:NumDeliveries]

Amazon ✅

Electrostatics
Virtusa

Palindrome count