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๐GE HealthCare is hiring!
Position: Trainee Engineer
Experienc๏ปฟe: Freshers (0 -1 Years)
Location: Bengaluru, India
๐ปApply Link: https://careers.gehealthcare.com/global/en/job/R4013874/Trainee-Engineer
Position: Trainee Engineer
Experienc๏ปฟe: Freshers (0 -1 Years)
Location: Bengaluru, India
๐ปApply Link: https://careers.gehealthcare.com/global/en/job/R4013874/Trainee-Engineer
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Company : Intuit
Role : SDE 1
Batch : 2025
CTC : 32 LPA
Apply : https://jobs.intuit.com/job/bengaluru/software-engineer-1/27595/70945687168
Role : SDE 1
Batch : 2025
CTC : 32 LPA
Apply : https://jobs.intuit.com/job/bengaluru/software-engineer-1/27595/70945687168
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
// LOTTERY
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <cstring>
using namespace std;
int dp[1001][1001][26]; // Adjust size as needed based on the problem constraints
int getCharWithDiff(char ch, int diff) {
int code = ch - 'a';
return ((code + diff + 26) % 26) + 'a';
}
int dfs(const string &lotteryID, const string &winnerID, int i, int j, int remainingK, int m, int n) {
if (i == m || j == n) return 0;
if (remainingK < 0) return 0;
if (dp[i][j][remainingK] != -1) return dp[i][j][remainingK];
int result = max(
dfs(lotteryID, winnerID, i + 1, j, remainingK, m, n),
dfs(lotteryID, winnerID, i, j + 1, remainingK, m, n)
);
if (lotteryID[i] == winnerID[j]) {
result = max(result, 1 + dfs(lotteryID, winnerID, i + 1, j + 1, remainingK, m, n));
} else if (remainingK > 0) {
for (int diff = 1; diff <= min(25, remainingK); ++diff) {
if (getCharWithDiff(lotteryID[i], diff) == winnerID[j] ||
getCharWithDiff(lotteryID[i], -diff) == winnerID[j]) {
result = max(result, 1 + dfs(lotteryID, winnerID, i + 1, j + 1, remainingK - diff, m, n));
break;
}
}
}
dp[i][j][remainingK] = result;
return result;
}
int maxLCSAfterOperations(const string &lotteryID, const string &winnerID, int k) {
int m = lotteryID.size();
int n = winnerID.size();
memset(dp, -1, sizeof(dp));
return dfs(lotteryID, winnerID, 0, 0, k, m, n);
}
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
#include <iostream>
#include <vector>
#include <string>
using namespace std;
string findStringFromIcp(vector<vector<int>>& icp) {
int n = icp.size();
for (int i = 0; i < n; i++) {
if (icp[i][i] != n - i) {
return "Impossible";
}
for (int j = i + 1; j < n; j++) {
if (icp[i][j] != icp[j][i]) {
return "Impossible";
}
}
}
string result(n, ' ');
result[0] = 'a';
for (int i = 1; i < n; i++) {
bool assigned = false;
for (int j = 0; j < i; j++) {
if (icp[j][i] > 0) {
result[i] = result[j];
assigned = true;
break;
}
}
if (!assigned) {
result[i] = result[i - 1] + 1;
if (result[i] > 'z') {
return "Impossible";
}
}
}
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
int commonLength = 0;
while (i + commonLength < n && j + commonLength < n && result[i + commonLength] == result[j + commonLength]) {
commonLength++;
}
if (commonLength != icp[i][j]) {
return "Impossible";
}
}
}
return result;
}
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
struct Cell {
int x, y, cost;
};
int minimumEnergy(vector<string> river, int initial_x, int initial_y, int final_x, int final_y) {
int rows = river.size();
int cols = river[0].size();
vector<vector<bool>> visited(rows, vector<bool>(cols, false));
queue<Cell> q;
int dx[] = {-1, 1, 0, 0};
int dy[] = {0, 0, -1, 1};
q.push({initial_x, initial_y, 0});
visited[initial_x][initial_y] = true;
while (!q.empty()) {
Cell current = q.front();
q.pop();
if (current.x == final_x && current.y == final_y) {
return current.cost;
}
for (int i = 0; i < 4; i++) {
int next_x = current.x + dx[i];
int next_y = current.y + dy[i];
if (next_x >= 0 && next_x < rows && next_y >= 0 && next_y < cols &&
river[next_x][next_y] != '#' && !visited[next_x][next_y]) {
visited[next_x][next_y] = true;
int updatedCost = current.cost;
if ((dx[i] == -1 && dy[i] == 0) || (dx[i] == 0 && dy[i] == -1)) {
updatedCost += 1;
}
q.push({next_x, next_y, updatedCost});
}
}
}
return -1;
}
Tekion โ
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Linkedin
Jatin Sisodia on LinkedIn: Referral - Microsoft India | 28 comments
Microsoft IDC is hiring SDE 1/SDE 2/SDE 3/Principal SDEs for its India Development Centers.
Ideal candidate :
1. Good grasp of data structures &โฆ | 28 comments on LinkedIn
Ideal candidate :
1. Good grasp of data structures &โฆ | 28 comments on LinkedIn
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Linkedin
Nistha Gupta on LinkedIn: #intuit #hiring #placement #interview #jobalert | 177 comments
Update: Not accepting anymore!
Want to join Intuit?
Intuit is hiring Software Engineer-1 and summer Intern ๐
If you think you're a good fit, DM me yourโฆ | 177 comments on LinkedIn
Want to join Intuit?
Intuit is hiring Software Engineer-1 and summer Intern ๐
If you think you're a good fit, DM me yourโฆ | 177 comments on LinkedIn
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Linkedin
Akanksha Buchke on LinkedIn: #intuit #referral #hiring #jobs #placement #interview | 121 comments
Intuit is hiring for Software Engineer 1 and Software Engineer Interns [Closed]
Intuit is accepting applications for 2025 and 2026 grads.
Apply link [2025โฆ | 121 comments on LinkedIn
Intuit is accepting applications for 2025 and 2026 grads.
Apply link [2025โฆ | 121 comments on LinkedIn
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Finova Hiring Junior Engineer
Experience upto 1 yr
https://finova.breezy.hr/p/e26f7e1fa4aa01-junior-engineer
Experience upto 1 yr
https://finova.breezy.hr/p/e26f7e1fa4aa01-junior-engineer
finova.breezy.hr
Join the UKโs largest Mortgage and Savings technology provider.
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Linkedin
Ravi Agrawal on LinkedIn: Associate Product Manager- Job Description
Heyloo LinkedIn,
At Propsoch, we are changing how India buys and owns homes. Weโre hiring a mission driven product manager to join our team and help usโฆ
At Propsoch, we are changing how India buys and owns homes. Weโre hiring a mission driven product manager to join our team and help usโฆ
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๐Minfy is hiring for Full stack Developer - MERN
Experience: 0 - 1 year's
Apply here: https://www.linkedin.com/jobs/view/4044807271/?alternateChannel=search
Experience: 0 - 1 year's
Apply here: https://www.linkedin.com/jobs/view/4044807271/?alternateChannel=search
Linkedin
Minfy hiring Full stack Developer - MERN in Hyderabad, Telangana, India | LinkedIn
Posted 9:45:02 AM. Job Description:We are looking for a talented Full Stack Developer proficient in the MERN (MongoDB,โฆSee this and similar jobs on LinkedIn.
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Genesis Ray is hiring for Backend Developer Intern
Apply here: https://docs.google.com/forms/d/e/1FAIpQLSeoHhBvNp2wKjDASV85cKKVS9OoBvkruXbGVosWgAcfda6Vig/viewform
Apply here: https://docs.google.com/forms/d/e/1FAIpQLSeoHhBvNp2wKjDASV85cKKVS9OoBvkruXbGVosWgAcfda6Vig/viewform
โค1
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Pixxel
Product Management Intern
Job Description
Role: Product Management Intern
Employment Type: Internship
Educational Qualification: B.tech
Work Experience: 0-6 months
Role Description: Function: Product Management
At Pixxel, Itโs not enough for us to just dump satellite images downโฆ
Role: Product Management Intern
Employment Type: Internship
Educational Qualification: B.tech
Work Experience: 0-6 months
Role Description: Function: Product Management
At Pixxel, Itโs not enough for us to just dump satellite images downโฆ
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Send your resume to hr@technogenesis.in
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
import java.util.*;
public class Main {
static int countMatches(List<String> grid1, List<String> grid2) {
int count = 0;
int m = grid1.size();
int n = grid1.get(0).length();
int[][] g1 = new int[m][n];
int[][] g2 = new int[m][n];
int[][] orMap = new int[m][n];
for(int i=0; i<m; i++){
char[] str1 = grid1.get(i).toCharArray();
char[] str2 = grid2.get(i).toCharArray();
for(int j=0; j<n; j++){
g1[i][j] = str1[j] - '0';
g2[i][j] = str2[j] - '0';
}
}
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
orMap[i][j] = g1[i][j] | g2[i][j];
}
}
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
if(orMap[i][j] == 1 && dfs(g1, g2, orMap, i, j)) count++;
}
}
return count;
}
private static boolean dfs(int[][] g1, int[][] g2, int[][] orMap, int i, int j) {
int m = orMap.length;
int n = orMap[0].length;
orMap[i][j] = 0;
boolean up = true, down = true, left = true, right = true;
if(i > 0 && orMap[i-1][j] == 1) up = dfs(g1, g2, orMap, i-1, j);
if(i < m - 1 && orMap[i+1][j] == 1) down = dfs(g1, g2, orMap, i+1, j);
if(j > 0 && orMap[i][j-1] == 1) left = dfs(g1, g2, orMap, i, j-1);
if(j < n - 1 && orMap[i][j+1] == 1) right = dfs(g1, g2, orMap, i, j+1);
return g1[i][j] == 1 && g2[i][j] == 1 && up && down && left && right;
}
Pace Securities โ