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๐Ÿ”ฐAuthentic Coding Solutions(with Outputs)
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SELECT
  c.name AS name,
  COUNT(w.customer_id) AS warehouses,
  MIN(w.volume) AS min_volume,
  MAX(w.volume) AS max_volume,
  SUM(w.volume) AS total_volume
FROM
  customers c
INNER JOIN
  warehouses w ON c.id = w.customer_id
WHERE
  w.is_active = 1
GROUP BY
  c.name
ORDER BY
  c.name ASC;

IBM โœ…
def getBitDistances(n):
    binary = bin(n)[2:]
    return max(len(binary) - 1 - i for i, bit in enumerate(binary) if bit == '1')

def getTopKBitDistances(numbers, k):
    bit_distances = [(num, getBitDistances(num)) for num in numbers]
    sorted_numbers = sorted(bit_distances, key=lambda x: (-x[1], -x[0]))
    return [num for num, _ in sorted_numbers[:k]]


IBMโœ…
class Solution {
    public int solution(int[][] peanuts, int[][] carrots) {
        int N = peanuts.length;
        int M = peanuts[0].length;

        int[][] dp = new int[N][M];

        dp[0][0] = peanuts[0][0] - carrots[0][0];

        for (int j = 1; j < M; j++) {
            dp[0][j] = dp[0][j - 1] + peanuts[0][j] - carrots[0][j];
        }

        for (int i = 1; i < N; i++) {
            dp[i][0] = dp[i - 1][0] + peanuts[i][0] - carrots[i][0];
        }

        for (int i = 1; i < N; i++) {
            for (int j = 1; j < M; j++) {
                dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]) + peanuts[i][j] - carrots[i][j];
            }
        }

        return dp[N - 1][M - 1];
    }

Atlan fellowship โœ…
๐Ÿ‘1
๐—–๐—ฆ ๐—”๐—น๐—ด๐—ผ ๐Ÿ’ป ๐ŸŒ ใ€Ž๐—–๐—ผ๐—บ๐—ฝ๐—ฒ๐˜๐—ถ๐˜๐—ถ๐˜ƒ๐—ฒ ๐—ฃ๐—ฟ๐—ผ๐—ด๐—ฟ๐—ฎ๐—บ๐—บ๐—ถ๐—ป๐—ดใ€
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#include <bits/stdc++.h>
using namespace std;
#define int long long

int quadruple(vector<int> arr, int n) {
    int ans = 0;
    vector<int> left(n), right(n);
    left[0] = 0;
    right[n - 1] = 0;
    for (int i = 1; i < n; i++) {
        left[i] = 0;
        for (int j = 0; j < i; j++) {
            if (arr[j] < arr[i]) {
                left[i]++;
            }
        }
    }
    for (int i = n - 2; i >= 0; i--) {
        right[i] = 0;
        for (int j = n - 1; j > i; j--) {
            if (arr[j] > arr[i]) {
                right[i]++;
            }
        }
    }
    for (int i = 1; i < n - 1; i++) {
        for (int j = i + 1; j < n - 1; j++) {
            ans += left[i] * right[j];
        }
    }
    return ans;
}

int32_t main() {
   int t;
    cin >> t;
    while(t--){
         int n;
    cin >> n;
    vector<int> a(n);
    for (int i = 0; i < n; i++) {
        cin >> a[i];
    }
    int ans = quadruple(a, n);
    cout << ans << endl;
    }



}

DB โœ