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Python Developer Trainee
Location : Pune
Interested candidate send your Resume
aghaavte@inferyx.com
Location : Pune
Interested candidate send your Resume
aghaavte@inferyx.com
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Deadline 3 September
https://docs.google.com/forms/d/e/1FAIpQLSe7uqxivfcfJQNYJHczImAXVYX66ZWFR12ir7_ScOmATJ7Mrg/viewform
https://docs.google.com/forms/d/e/1FAIpQLSe7uqxivfcfJQNYJHczImAXVYX66ZWFR12ir7_ScOmATJ7Mrg/viewform
โค3
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Company Name : UST Global
D3 Hackathon 2024
Batch : All Engineering - BTech and MTech
Prizes worth 19 Lakhs to be won + PPO for top performers
Link to register : https://p.hck.re/hDC6
Last Date to register is September 4.
D3 Hackathon 2024
Batch : All Engineering - BTech and MTech
Prizes worth 19 Lakhs to be won + PPO for top performers
Link to register : https://p.hck.re/hDC6
Last Date to register is September 4.
HackerEarth
UST D3CODE Hackathon'24 on HackerEarth
D3CODE, UST presents an exciting opportunity for tech enthusiasts to demonstrate their passion for innovation, problem-solving, design thinking, and programming skills, with the chance to win incredible prizes. D3CODE consists of two main events: regionalโฆ
๐1
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Artmac is hiring for AWS Data Engineer with Databricks - Freshers (2024)
Experience: 0 - 1 year's
Apply here: https://www.linkedin.com/jobs/view/4015661389/
Experience: 0 - 1 year's
Apply here: https://www.linkedin.com/jobs/view/4015661389/
Linkedin
34,000+ Data Engineer jobs in India (1,887 new)
Todayโs top 34,000+ Data Engineer jobs in India. Leverage your professional network, and get hired. New Data Engineer jobs added daily.
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Send your reume to: fresher-jobs@mitrahsoft.com
Contact: 9092480924
Contact: 9092480924
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Zomato Hiring Data Analyst
https://docs.google.com/forms/d/e/1FAIpQLSfL6qJfdBsMW6MZsJdKrqJW1EwaA7CGX6knZKz-O69mYiey8Q/viewform
https://docs.google.com/forms/d/e/1FAIpQLSfL6qJfdBsMW6MZsJdKrqJW1EwaA7CGX6knZKz-O69mYiey8Q/viewform
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Infosys brings a great opportunity for recent MBA graduates from the batch of 2023 & 2024.
https://surveys.infosysapps.com/r/a/InfosysMBAOffcampus
https://surveys.infosysapps.com/r/a/InfosysMBAOffcampus
Infosysapps
Infosys | Surveys
Create Surveys. Collect feedback through a computer assisted, Mobile friendly method. Design Surveys, Send Request , Analyze response and more ...
#include <iostream>
#include <vector>
#include <functional>
#include <array>
using namespace std;
using ll = long long;
ll maxValue(ll a, ll b) {
return (a > b) ? a : b;
}
int getMinServers(int n, vector<int> f, vector<int> t, vector<int> w, vector<int> v) {
vector<ll> size(n), maxDistance(n);
vector<vector<array<ll, 2>>> adjacencyList(n);
for (ll i = 0; i < f.size(); i++) {
f[i]--;
t[i]--;
adjacencyList[f[i]].push_back({t[i], w[i]});
adjacencyList[t[i]].push_back({f[i], w[i]});
}
ll answer = 0;
function<void(ll, ll)> dfs1 = [&](ll u, ll parent) {
size[u] = 1;
ll idx = 0;
while (idx < adjacencyList[u].size()) {
ll vertex = adjacencyList[u][idx][0];
ll weight = adjacencyList[u][idx][1];
if (vertex != parent) {
maxDistance[vertex] = maxValue(maxDistance[u] + weight, weight);
dfs1(vertex, u);
size[u] += size[vertex];
}
idx++;
}
};
function<void(ll, ll)> dfs2 = [&](ll u, ll parent) {
if (u != 0 && maxDistance[u] > v[u]) {
answer += size[u];
} else {
ll idx = 0;
while (idx < adjacencyList[u].size()) {
ll vertex = adjacencyList[u][idx][0];
if (vertex != parent) {
dfs2(vertex, u);
}
idx++;
}
}
};
dfs1(0, -1);
dfs2(0, -1);
return answer;
}
Cisco โ
Minserver
๐3
#include <iostream>
#include <vector>
#include <algorithm>
#include <climits>
using namespace std;
int solve(int i, vector<int>& lst, int ad, const vector<int>& machineCount, const vector<int>& finalMachineCount, int shiftingCost) {
int n = machineCount.size();
if (i == n) {
int res = ad;
for (int k = 0; k < 3; ++k) {
res += abs(lst[k] - finalMachineCount[k]);
}
return res;
}
int res = INT_MAX;
res = min(res, solve(i + 1, lst, ad, machineCount, finalMachineCount, shiftingCost));
for (int j = 0; j < 3; ++j) {
lst[j] += machineCount[i];
if (lst[j] - machineCount[i] != 0) {
res = min(res, solve(i + 1, lst, ad + shiftingCost, machineCount, finalMachineCount, shiftingCost));
} else {
res = min(res, solve(i + 1, lst, ad, machineCount, finalMachineCount, shiftingCost));
}
lst[j] -= machineCount[i];
}
return res;
}
int getMinimumCost(const vector<int>& machineCount, const vector<int>& finalMachineCount, int shiftingCost) {
vector<int> lst(3, 0);
return solve(0, lst, 0, machineCount, finalMachineCount, shiftingCost);
}
GetMinimum Costโ
Cisco
#include <vector>
#include <algorithm>
#include <climits>
using namespace std;
int solve(int i, vector<int>& lst, int ad, const vector<int>& machineCount, const vector<int>& finalMachineCount, int shiftingCost) {
int n = machineCount.size();
if (i == n) {
int res = ad;
for (int k = 0; k < 3; ++k) {
res += abs(lst[k] - finalMachineCount[k]);
}
return res;
}
int res = INT_MAX;
res = min(res, solve(i + 1, lst, ad, machineCount, finalMachineCount, shiftingCost));
for (int j = 0; j < 3; ++j) {
lst[j] += machineCount[i];
if (lst[j] - machineCount[i] != 0) {
res = min(res, solve(i + 1, lst, ad + shiftingCost, machineCount, finalMachineCount, shiftingCost));
} else {
res = min(res, solve(i + 1, lst, ad, machineCount, finalMachineCount, shiftingCost));
}
lst[j] -= machineCount[i];
}
return res;
}
int getMinimumCost(const vector<int>& machineCount, const vector<int>& finalMachineCount, int shiftingCost) {
vector<int> lst(3, 0);
return solve(0, lst, 0, machineCount, finalMachineCount, shiftingCost);
}
GetMinimum Costโ
Cisco
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int SS(const string& rollNumber) {
int num = 0;
for (char c : rollNumber) {
if (isdigit(c)) {
num = num * 10 + (c - '0');
}
}
return num;
}
bool compare(const pair<string, int>& a, const pair<string, int>& b) {
string classA = "", classB = "";
int numA = SS(a.first);
int numB = SS(b.first);
for (char c : a.first) {
if (isalpha(c)) classA += c;
else break;
}
for (char c : b.first) {
if (isalpha(c)) classB += c;
else break;
}
if (classA == classB) return numA < numB;
return classA < classB;
}
int main() {
int N;
cin >> N;
vector<pair<string, int>> students(N);
for (int i = 0; i < N; ++i) {
cin >> students[i].first >> students[i].second;
}
sort(students.begin(), students.end(), compare);
for (const auto& student : students) {
cout << student.first << " " << student.second << endl;
}
return 0;
}
CBX(intern)โ
#include <vector>
#include <algorithm>
using namespace std;
int SS(const string& rollNumber) {
int num = 0;
for (char c : rollNumber) {
if (isdigit(c)) {
num = num * 10 + (c - '0');
}
}
return num;
}
bool compare(const pair<string, int>& a, const pair<string, int>& b) {
string classA = "", classB = "";
int numA = SS(a.first);
int numB = SS(b.first);
for (char c : a.first) {
if (isalpha(c)) classA += c;
else break;
}
for (char c : b.first) {
if (isalpha(c)) classB += c;
else break;
}
if (classA == classB) return numA < numB;
return classA < classB;
}
int main() {
int N;
cin >> N;
vector<pair<string, int>> students(N);
for (int i = 0; i < N; ++i) {
cin >> students[i].first >> students[i].second;
}
sort(students.begin(), students.end(), compare);
for (const auto& student : students) {
cout << student.first << " " << student.second << endl;
}
return 0;
}
CBX(intern)โ
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
bool canRobAll(const vector<int>& houses, int H, int K) {
int hours_needed = 0;
for (int house_count : houses) {
hours_needed += (house_count + K - 1) / K; // Ceiling division
}
return hours_needed <= H;
}
int main() {
int N, H;
cin >> N >> H;
vector<int> A(N);
for (int i = 0; i < N; i++) {
cin >> A[i];
}
int left = 1;
int right = *max_element(A.begin(), A.end());
while (left < right) {
int mid = left + (right - left) / 2;
if (canRobAll(A, H, mid)) {
right = mid;
} else {
left = mid + 1;
}
}
cout << left << endl;
return 0;
}
//Richies World
Flipkartโ
#include <vector>
#include <algorithm>
using namespace std;
bool canRobAll(const vector<int>& houses, int H, int K) {
int hours_needed = 0;
for (int house_count : houses) {
hours_needed += (house_count + K - 1) / K; // Ceiling division
}
return hours_needed <= H;
}
int main() {
int N, H;
cin >> N >> H;
vector<int> A(N);
for (int i = 0; i < N; i++) {
cin >> A[i];
}
int left = 1;
int right = *max_element(A.begin(), A.end());
while (left < right) {
int mid = left + (right - left) / 2;
if (canRobAll(A, H, mid)) {
right = mid;
} else {
left = mid + 1;
}
}
cout << left << endl;
return 0;
}
//Richies World
Flipkartโ
#include <iostream>
#include <vector>
#include <cmath>
using namespace std;
bool isPrime(int n)
{
if (n <= 1)
return false;
for (int i = 2; i <= sqrt(n); i++)
{
if (n % i == 0)
return false;
}
return true;
}
int main()
{
int N, K;
cin >> N >> K;
if (N == 0)
{
cout << -1 << endl;
return 0;
}
vector<int> a(N);
for (int i = 0; i < N; i++)
{
cin >> a[i];
}
vector<int> b;
for (int i = 0; i < N; i++)
{
if (isPrime(i + 1) && a[i] >= K)
{
b.push_back(a[i]);
}
}
int required = ceil(N / 3.0);
if (b.size() < required)
{
cout << -1 << endl;
return 0;
}
int ans = 0, count = N / 2, t = 0;
for (int i = 1; i <= N; i++)
{
if (a[i - 1] >= K and isPrime(i))
{
ans += a[i - 1] / 2;
count--;
if (i == 2)
t = 1;
if (i == 3 and t == 1)
{
count++;
ans -= a[i - 1] / 2;
}
}
if (count == 0)
break;
}
cout << ans << endl;
return 0;
}
juice
flipkart โ
#include <vector>
#include <cmath>
using namespace std;
bool isPrime(int n)
{
if (n <= 1)
return false;
for (int i = 2; i <= sqrt(n); i++)
{
if (n % i == 0)
return false;
}
return true;
}
int main()
{
int N, K;
cin >> N >> K;
if (N == 0)
{
cout << -1 << endl;
return 0;
}
vector<int> a(N);
for (int i = 0; i < N; i++)
{
cin >> a[i];
}
vector<int> b;
for (int i = 0; i < N; i++)
{
if (isPrime(i + 1) && a[i] >= K)
{
b.push_back(a[i]);
}
}
int required = ceil(N / 3.0);
if (b.size() < required)
{
cout << -1 << endl;
return 0;
}
int ans = 0, count = N / 2, t = 0;
for (int i = 1; i <= N; i++)
{
if (a[i - 1] >= K and isPrime(i))
{
ans += a[i - 1] / 2;
count--;
if (i == 2)
t = 1;
if (i == 3 and t == 1)
{
count++;
ans -= a[i - 1] / 2;
}
}
if (count == 0)
break;
}
cout << ans << endl;
return 0;
}
juice
flipkart โ
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin >> n;
vector<int> a(n), b(n);
int sumA = 0, sumB = 0;
for (auto &i : a)
cin >> i, sumA += i;
for (auto &i : b)
cin >> i, sumB += i;
int ans = min(sumA, sumB), mask = (1 << n);
for (int i = 0; i < mask; ++i)
{
int curr = 0, currentB = 0;
for (int j = 0; j < n; ++j)
{
if (i & (1 << j))
{
curr += a[j];
}
else
{
currentB += b[j];
}
}
ans = max(ans, min(curr, currentB));
}
cout << ans << endl;
return 0;
}
// game
flipkart โ
using namespace std;
int main()
{
int n;
cin >> n;
vector<int> a(n), b(n);
int sumA = 0, sumB = 0;
for (auto &i : a)
cin >> i, sumA += i;
for (auto &i : b)
cin >> i, sumB += i;
int ans = min(sumA, sumB), mask = (1 << n);
for (int i = 0; i < mask; ++i)
{
int curr = 0, currentB = 0;
for (int j = 0; j < n; ++j)
{
if (i & (1 << j))
{
curr += a[j];
}
else
{
currentB += b[j];
}
}
ans = max(ans, min(curr, currentB));
}
cout << ans << endl;
return 0;
}
// game
flipkart โ
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Juspay Hiring Challenge 2024
Batch eligible: 2024 and 2025 grads
Round:
1) MCQ
2) Coding
3) Final Interview
CTC: 21-27 Lakh
Stipend: 40k per month
Apply: https://unstop.com/o/y9PvMOt?lb=Mgx4BsU&utm_medium=Share&utm_source=shortUrl
Batch eligible: 2024 and 2025 grads
Round:
1) MCQ
2) Coding
3) Final Interview
CTC: 21-27 Lakh
Stipend: 40k per month
Apply: https://unstop.com/o/y9PvMOt?lb=Mgx4BsU&utm_medium=Share&utm_source=shortUrl
Unstop
Participate in Juspay Hiring Challenge 2024 & win exciting prizes. | 1141948 // Unstop
Find out the best Juspay Hiring Challenge 2024 that match your interests. Prove your mettle and win exciting prizes like job opportunities and cash rewards f... | 2024 | 1141948
๐1
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Open Positions Available:
- Front-End Developers : Build intuitive and visually stunning web applications.
- Flutter Developers : Create cutting-edge mobile applications.
Interns : Also welcome to apply
Apply Here : https://docs.google.com/forms/d/e/1FAIpQLScxv1xGftiuF34-Z-2pXzEQWrNHP2echXw6mZnTL4O4MefZsA/viewform
- Front-End Developers : Build intuitive and visually stunning web applications.
- Flutter Developers : Create cutting-edge mobile applications.
Interns : Also welcome to apply
Apply Here : https://docs.google.com/forms/d/e/1FAIpQLScxv1xGftiuF34-Z-2pXzEQWrNHP2echXw6mZnTL4O4MefZsA/viewform
๐1
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Need SAP Certified Freshers for Quints Global | Location: Okhla, New Delhi* ๐ฅ๐ฅ๐ฅ
Positions available:
1. SAP SD Management Trainee.
2. SAP FICO Management Trainee.
3. SAP MM Management Trainee.
Qualification: BCA/ MCA/ B Tech.
Date of Interview: 5th & 6th September
Venue: Quints Global Pvt. Ltd., 3rd Floor, 12 A Pride Tower, Near Kotak Mahindra, Sector- 125, Noida, Nearest Metro: Okhla Bird Sanctuary.
Positions available:
1. SAP SD Management Trainee.
2. SAP FICO Management Trainee.
3. SAP MM Management Trainee.
Qualification: BCA/ MCA/ B Tech.
Date of Interview: 5th & 6th September
Venue: Quints Global Pvt. Ltd., 3rd Floor, 12 A Pride Tower, Near Kotak Mahindra, Sector- 125, Noida, Nearest Metro: Okhla Bird Sanctuary.
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Linkedin
๐ Internship Opportunity in ISRO ๐ | Steaphen Sigatapu | 541 comments
๐ Internship Opportunity in ISRO ๐
This is for all students who are looking for internship opportunities in ISRO - Indian Space Research Organization. This is an amazing opportunity to apply for internship in VSSC, ISRO.
The application for this internshipโฆ
This is for all students who are looking for internship opportunities in ISRO - Indian Space Research Organization. This is an amazing opportunity to apply for internship in VSSC, ISRO.
The application for this internshipโฆ
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Apply, if interested!!