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โ๏ธInvesco Off Campus Drive 2024 Hiring As Graduate Engineer Trainee | INR 9 LPA+โ๏ธ
๐จโ๐ปJob Role : Graduate Engineer Trainee
๐Qualification : BE/B.Tech
๐Experience : Freshers
๐ฐPackage : INR 9 LPA
โญ๏ธ Apply Fast :
https://invesco.wd1.myworkdayjobs.com/en-US/intelliflo/job/Hyderabad-Telangana/Graduate-Engineer-Trainee_R-5629
๐จโ๐ปJob Role : Graduate Engineer Trainee
๐Qualification : BE/B.Tech
๐Experience : Freshers
๐ฐPackage : INR 9 LPA
โญ๏ธ Apply Fast :
https://invesco.wd1.myworkdayjobs.com/en-US/intelliflo/job/Hyderabad-Telangana/Graduate-Engineer-Trainee_R-5629
Myworkdayjobs
Graduate Engineer Trainee
As one of the worldโs leading asset managers, Invesco is dedicated to helping investors worldwide achieve their financial objectives. By delivering the combined power of our distinctive investment management capabilities, we provide a wide range of investmentโฆ
๐1
#include <iostream>
#include <algorithm>
using namespace std;
#define ll long long
ll solve(int s1, int s2, int p) {
ll minT1 = p / s1;
ll rem1 = p % s1;
while (minT1 >= 0) {
if (rem1 % s2 == 0) {
break;
}
minT1--;
rem1 += s1;
}
ll minT2 = p / s2;
ll rem2 = p % s2;
while (minT2 >= 0) {
if (rem2 % s1 == 0) {
break;
}
minT2--;
rem2 += s2;
}
if (minT1 < 0 && minT2 < 0) {
return -1;
} else if (minT1 < 0) {
return minT2 + rem2 / s1;
} else if (minT2 < 0) {
return minT1 + rem1 / s2;
} else {
return min(minT1 + rem1 / s2, minT2 + rem2 / s1);
}
}
int main() {
int s1, s2, p;
cin >> s1 >> s2 >> p;
cout << solve(s1, s2, p) << endl;
return 0;
}
Track in Hackathon โ
#include <algorithm>
using namespace std;
#define ll long long
ll solve(int s1, int s2, int p) {
ll minT1 = p / s1;
ll rem1 = p % s1;
while (minT1 >= 0) {
if (rem1 % s2 == 0) {
break;
}
minT1--;
rem1 += s1;
}
ll minT2 = p / s2;
ll rem2 = p % s2;
while (minT2 >= 0) {
if (rem2 % s1 == 0) {
break;
}
minT2--;
rem2 += s2;
}
if (minT1 < 0 && minT2 < 0) {
return -1;
} else if (minT1 < 0) {
return minT2 + rem2 / s1;
} else if (minT2 < 0) {
return minT1 + rem1 / s2;
} else {
return min(minT1 + rem1 / s2, minT2 + rem2 / s1);
}
}
int main() {
int s1, s2, p;
cin >> s1 >> s2 >> p;
cout << solve(s1, s2, p) << endl;
return 0;
}
Track in Hackathon โ
โค1
Minimum Cost โ
#include <iostream>
#include <unordered_map>
#include <string>
#include <climits>
int getMinGroup(std::string str) {
std::unordered_map<char, int> mapSubjects;
int keysCount = 0;
const int len = str.length();
for (int i = 0; i < len; ++i) {
char subject = str[i];
if (subject == 'b'subject == 'm' subject == 'c' subject == 'p' subject == 'z') {
if (mapSubjects.find(subject) == mapSubjects.end()) {
++keysCount;
mapSubjects[subject] = 1;
} else {
++mapSubjects[subject];
}
}
}
if (keysCount != 5) {
return 0;
}
int min = INT_MAX;
for (const auto& entry : mapSubjects) {
if (entry.second < min) {
min = entry.second;
}
}
return min;
}
The Perfect Team โ
#include <unordered_map>
#include <string>
#include <climits>
int getMinGroup(std::string str) {
std::unordered_map<char, int> mapSubjects;
int keysCount = 0;
const int len = str.length();
for (int i = 0; i < len; ++i) {
char subject = str[i];
if (subject == 'b'
if (mapSubjects.find(subject) == mapSubjects.end()) {
++keysCount;
mapSubjects[subject] = 1;
} else {
++mapSubjects[subject];
}
}
}
if (keysCount != 5) {
return 0;
}
int min = INT_MAX;
for (const auto& entry : mapSubjects) {
if (entry.second < min) {
min = entry.second;
}
}
return min;
}
The Perfect Team โ
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int getMinimumTime(vector<int>& processSize, vector<int>& capacity) {
sort(processSize.rbegin(), processSize.rend());
sort(capacity.rbegin(), capacity.rend());
int ptr = 0;
int time = 1;
for (int process : processSize) {
if (ptr == capacity.size()) {
time++;
ptr = 0;
}
if (process > capacity[ptr]) {
if (process > capacity[0]) {
return -1;
}
time++;
ptr = 1;
} else {
ptr++;
}
}
return 2*time-1;
}
Process Allocation โ
#include <vector>
#include <algorithm>
using namespace std;
int getMinimumTime(vector<int>& processSize, vector<int>& capacity) {
sort(processSize.rbegin(), processSize.rend());
sort(capacity.rbegin(), capacity.rend());
int ptr = 0;
int time = 1;
for (int process : processSize) {
if (ptr == capacity.size()) {
time++;
ptr = 0;
}
if (process > capacity[ptr]) {
if (process > capacity[0]) {
return -1;
}
time++;
ptr = 1;
} else {
ptr++;
}
}
return 2*time-1;
}
Process Allocation โ
๐1
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
BharatX hiring summer interns! ๐ฅ
We are a team of young, ambitious, and bold people love to dedicate their lifeโs work towards something meaningful for India & the world. We love to have a shit ton of fun and cut the bullshit corporate culture! Here is your opportunity to build products that impact credit accessibility of 50M+ users. Apply below!!
Internship Details:
3-6 months
Final year of college
Onsite internship in Bangalore
What We Offer:
Stipend: 50k/month
PPO based on performance
How to Apply:
Fill out the form
๐data science intern - https://lnkd.in/g4qTQbQ6
๐frontend intern - https://lnkd.in/gdCtAH4M
We are a team of young, ambitious, and bold people love to dedicate their lifeโs work towards something meaningful for India & the world. We love to have a shit ton of fun and cut the bullshit corporate culture! Here is your opportunity to build products that impact credit accessibility of 50M+ users. Apply below!!
Internship Details:
3-6 months
Final year of college
Onsite internship in Bangalore
What We Offer:
Stipend: 50k/month
PPO based on performance
How to Apply:
Fill out the form
๐data science intern - https://lnkd.in/g4qTQbQ6
๐frontend intern - https://lnkd.in/gdCtAH4M
lnkd.in
LinkedIn
This link will take you to a page thatโs not on LinkedIn
def count_vowels(string):
count = 0
vowels = set('aeiou')
for char in string:
if char.lower() in vowels:
count += 1
return count
def determine_winner(strings):
winners = []
for string in strings:
if count_vowels(string) % 2 == 0:
winners.append("Chris")
else:
winners.append("Alex")
return winners
System and Strings โ
count = 0
vowels = set('aeiou')
for char in string:
if char.lower() in vowels:
count += 1
return count
def determine_winner(strings):
winners = []
for string in strings:
if count_vowels(string) % 2 == 0:
winners.append("Chris")
else:
winners.append("Alex")
return winners
System and Strings โ
๐5๐1
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
EY hiring voice process Analyst
https://forms.office.com/pages/responsepage.aspx?id=mT-XW99360uyfaoMcLhILOpi94FpHY5HvRlOlqDoYkNUQUlHMTJFRU1LNVFJRkxWUjBWNEgxNlVKOS4u&origin=lprLink
https://forms.office.com/pages/responsepage.aspx?id=mT-XW99360uyfaoMcLhILOpi94FpHY5HvRlOlqDoYkNUQUlHMTJFRU1LNVFJRkxWUjBWNEgxNlVKOS4u&origin=lprLink
Office
Fill | Virtual drive(teams) for International voice process
Experience - 2 months-12 months (no freshers)
Any graduate
Do not apply if already applied in last 3 month
Any graduate
Do not apply if already applied in last 3 month
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
โ๏ธQuadrant-Technologies Off Campus Drive 2024 Hiring As Software Engineer | INR 4-8 LPAโ๏ธ
๐จโ๐ปJob Role : Software Engineer
๐Qualification : B.E/B.Tech/M.E/M.Tech/MCA
๐Batch : 2023
๐ฐPackage : 4-8 LPA
โญ๏ธ Apply Fast :
https://www.quadranttechnologies.com/we-are-hiring-freshers
๐จโ๐ปJob Role : Software Engineer
๐Qualification : B.E/B.Tech/M.E/M.Tech/MCA
๐Batch : 2023
๐ฐPackage : 4-8 LPA
โญ๏ธ Apply Fast :
https://www.quadranttechnologies.com/we-are-hiring-freshers
Quadranttechnologies
We are hiring freshers | Quadrant Technologies
Applications are a great tool for businesses. They help in saving time as well as costs by automating several processes. We at Quadrant Technologies with years of expertise in application development can help you to create the perfect modernized and customโฆ
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
โค1
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
Company Name: Harness
๐ Job Title: Software Engineer (Backend)
โ๐ป YOE: 0-1 years
โก๏ธ Apply: https://www.instahyre.com/job-310707-software-engineer-at-harness-bangalore
Please do share in your college grps and in case you are applying please react on this post:) ๐โค๏ธ
๐ Job Title: Software Engineer (Backend)
โ๐ป YOE: 0-1 years
โก๏ธ Apply: https://www.instahyre.com/job-310707-software-engineer-at-harness-bangalore
Please do share in your college grps and in case you are applying please react on this post:) ๐โค๏ธ
Instahyre
Software Engineer job at Harness - Instahyre
Harness is looking for a Software Engineer in Bangalore with 0-1 years of experience in Backend Development, Golang, Java, etc. Apply today and get your dream job at Harness!
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
Company Name: Qualcomm
๐ Job Title: Software Engineer Intern (2024 grads) and Hardware Engineer Intern (2025 grads)
โ๐ป YOE: 2024 and 2025 grads
โก๏ธ Apply: https://careers.qualcomm.com/careers/job/446697880255?hl=en-US&domain=qualcomm.com&source=APPLICANT_SOURCE-6-2&source=APPLICANT_SOURCE-6-2
Please do share in your college grps and in case you are applying please react on this post:) ๐โค๏ธ
๐ Job Title: Software Engineer Intern (2024 grads) and Hardware Engineer Intern (2025 grads)
โ๐ป YOE: 2024 and 2025 grads
โก๏ธ Apply: https://careers.qualcomm.com/careers/job/446697880255?hl=en-US&domain=qualcomm.com&source=APPLICANT_SOURCE-6-2&source=APPLICANT_SOURCE-6-2
Please do share in your college grps and in case you are applying please react on this post:) ๐โค๏ธ
โค1
def min_remaining_length(seq):
stack = []
for char in seq:
if char == "A" or char == "B":
if stack and stack[-1] == "A" and char == "B":
stack.pop()
elif stack and stack[-1] == "B" and char == "B":
stack.pop()
else:
stack.append(char)
else:
stack.append(char)
return len(stack)
Substring Removal โ
JPMC code for good
stack = []
for char in seq:
if char == "A" or char == "B":
if stack and stack[-1] == "A" and char == "B":
stack.pop()
elif stack and stack[-1] == "B" and char == "B":
stack.pop()
else:
stack.append(char)
else:
stack.append(char)
return len(stack)
Substring Removal โ
JPMC code for good