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๐ŸšฉMain Group - @SuperExams
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๐Ÿ”ฐAuthentic Coding Solutions(with Outputs)
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I got many texts over Linkedin and telegram, that how to build logic? ๐Ÿฅบ๐Ÿฅบ ๐Ÿ’

Question: Whenever I was unable to solve a problem, I see the discussion forum, understand that and implement it. But after that also I stuck in new problems. โœ…

Answer: If you got the wrong answer to any problem, see discuss forum or YouTube and try to understand their solution after that The ๐ฆ๐จ๐ฌ๐ญ ๐ข๐ฆ๐ฉ๐จ๐ซ๐ญ๐š๐ง๐ญ step, check why your solution was not worked there, In which test case it failed, and why. This will give you better clarity of question and also help in the future to build logic. โค๏ธโœ…

๐„๐ฑ๐ฉ๐ž๐ซ๐ข๐ž๐ง๐œ๐ž๐ ๐Ÿ˜Š๐Ÿ˜Š Love to hear some more tips, this will definitely help juniors to understand better โค๏ธโœ…
๐Ÿ‘5โค3
Qualcomm is hiring for their Software test teams in Hyderabad.

Batch eligible: 2021 and 2022 passouts (BTech, Mtech, (Cs, IT, ECE or Embedded))

Skills required: Good knowledge on C/ C++/ Python Coding, OS, DSA.

If interested send your resume over aayushar@qti.qualcomm.com
๐Ÿ‘1
import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
sc.nextLine();

User xexamster[] = new User[n];
for (int i = 0; i < xexamster.length; i++) {
int id = sc.nextInt();
sc.nextLine();
String name = sc.nextLine();
String emil = sc.nextLine();
int age = sc.nextInt();
sc.nextLine();
xexamster[i] = new User(id, name, emil, age);
}


int fs1 = sc.nextInt();

int ans1 = xexamster2(xexamster);

if (ans1 != 0) {
System.out.println(ans1);

} else {
System.out.println("No Users found.");

}


User ans2 = xexamster1(xexamster, fs1);

if (ans2 != null) {
System.out.println(ans2.getName());
System.out.println(ans2.getEmil());

} else {
System.out.println("No User found with the given id.");

}

}


public static int xexamster2(User[] d) {
int p = 0;
for (int i = 0; i < d.length; i++) {
{
p += d[i].getAge();

}

}
return p;
}


public static User xexamster1(User[] d, int s) {

User p = null;
int a = 0;
for (int i = 0; i < d.length; i++) {
if (d[i].getId() == s) {
p = d[i];
}
}

return p;

}

}


class User {
private int id;
private String name;
private String emil;
private int age;

public User(int id, String name, String emil, int age) {
super();
this.id = id;
this.name = name;
this.emil = emil;
this.age = age;
}


public int getId() {
return id;
}

public void setId(int id) {
this.id = id;
}

public String getName() {
return name;
}


public void setName(String name) {
this.name = name;
}

public String getEmil() {
return emil;
}

public void setEmil(String emil) {
this.emil = emil;
}

public int getAge() {
return age;
}


public void setAge(int age) {
this.age = age;
}

}


//////////////////////// UNIX /////////////////
/*
* awk 'BEGIN{FS=";", count=0;} { if($4>10000) { count+=$3 } } END {
* if(count==0){ print "Total count: 0"; } else { print "Total count:", count; }
* }'
*
*
*/

TCS PRAโœ…
Infosys Interview Experience

Show me your ID
Tell me about urself
Tell me about ur final year project
Local and global variable
Oops concepts
Do you have ur own laptop
What is RAM/ROM of ur laptop
Do you have any questions
๐‘จ๐’๐’ ๐’•๐’‰๐’† ๐’•๐’“๐’๐’–๐’ƒ๐’๐’† ๐’š๐’๐’– ๐’‚๐’“๐’† ๐’ˆ๐’๐’Š๐’๐’ˆ ๐’•๐’‰๐’“๐’๐’–๐’ˆ๐’‰ ๐’“๐’Š๐’ˆ๐’‰๐’• ๐’๐’๐’˜, ๐’•๐’๐’Ž๐’๐’“๐’“๐’๐’˜ ๐’Š๐’•'๐’” ๐’ˆ๐’๐’Š๐’๐’ˆ ๐’•๐’ ๐’ƒ๐’† ๐’˜๐’๐’“๐’•๐’‰ ๐’Š๐’• ๐Ÿ˜Šโค๏ธ

Just trust the process and don't give upโœ…
โค3
Tcs wings Tech track t3 answers 8:30pm

1)print(sclar. Transform (data))
D
2)phyton functions
B
3)phyton - v
C
4)sk learn.model
A
6)a.
Histogram.
7)c
. det(n)
9)annual_review(1)
A
10)d. N
D
11)b
Barcharts
12) b
0-2
13)n+c
C
14)(14,44, 5
A
25)t test.
B
30)b
8
33)error
36)b
Norm. Cdf(1,0, 1,2,6, 5,9)
37)a
O to 19 ()
38)c
Tonikzer
39)b
Classfier. Fit(x_train
40)d
3 3 8 12 16
22)d
Tupple clients
26)a
Df1, df2, pandas.
8)c
Len(cities)
18)b
Pass
32)a
Index 0 1 2 3 4
๐Ÿ‘1
2017. Grid Game
You are given a 0-indexed 2D array grid of size 2 x n, where grid[r][c] represents the number of points at position (r, c) on the matrix. Two robots are playing a game on this matrix.
Both robots initially start at (0, 0) and want to reach (1, n-1). Each robot may only move to the right ((r, c) to (r, c + 1)) or down ((r, c) to (r + 1, c)).
At the start of the game, the first robot moves from (0, 0) to (1, n-1), collecting all the points from the cells on its path. For all cells (r, c) traversed on the path, grid[r][c] is set to 0. Then, the second robot moves from (0, 0) to (1, n-1), collecting the points on its path. Note that their paths may intersect with one another.
The first robot wants to minimize the number of points collected by the second robot. In contrast, the second robot wants to maximize the number of points it collects. If both robots play optimally, return the number of points collected by the second robot.

Input: grid = [[2,5,4],[1,5,1]]
Output: 4
Explanation: The optimal path taken by the first robot is shown in red, and the optimal path taken by the second robot is shown in blue.
The cells visited by the first robot are set to 0.
The second robot will collect 0 + 0 + 4 + 0 = 4 points.

class Solution {
public:
long long gridGame(vector<vector<int>>& grid) {
int n=grid[0].size();
long long f=0,s=0,res=LONG_MAX;
for(auto& i:grid[0])f+=i;
for(int i=0;i<n;i++){
f-=grid[0][i];
res=min(res,max(f,s));
s+=grid[1][i];
}
return res;
}
};

// TC O(N)
// SC O(1)


Amazon SDE1 (T1 interview question asked)
Transpose Matrix
Given a 2D integer array matrix, return the transpose of matrix.
The transpose of a matrix is the matrix flipped over its main diagonal, switching the matrix's row and column indices.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[1,4,7],[2,5,8],[3,6,9]]
Example 2:

Input: matrix = [[1,2,3],[4,5,6]]
Output: [[1,4],[2,5],[3,6]]
class Solution {
public:
vector<vector<int>> transpose(vector<vector<int>>& matrix) {
vector<vector<int>> ans;
for(int i=0;i<matrix[0].size();i++)
{
vector<int>temp;
for(int j=0;j<matrix.size();j++)
{
temp.push_back(matrix[j][i]);
}
ans.push_back(temp);
}
return ans;
}
};

// TC O(N*M)
// SC O(N*M)

Amazon SDE1 (T1 interview question asked)