Hi! Keep reading this message if you are looking for a job and would like to build the future of digital payments, here is a golden opportunity.

NPCI, India’s leading digital payments organisation is scouting for 250 Graduate Engineer Trainees (GET) who will join its team to build revolutionary digital payment products like UPI, RuPay, and FAStag.

It is a ‘Learn while you Earn’ opportunity where the GETs will pursue 1 year PG program from a reputed institution in addition to the salary package being offered to them. (*t&c apply)

Get ready to join this innovator's community and inspire the work. Have a great start to your career.

Last date to apply for this opportunity is April 28, 2022. Visit https://bit.ly/3Lc64AO.

Thank you.

Thoughtworks is hiring for Software Developer role.

CTC: 11 LPA

Batch eligible: 2020, 2021 and 2022 passouts(Female Only)

Apply Link: https://www.myamcat.com/jobs/description/software-developer-job-for-fresher-in-thoughtworks-in-bengaluru-gurgaon-pune/89875

Performing strange task code

Python 3✅

Maximise multiplication code
Python 3✅

Positive sum segment code python3✅

Good Subset code
Python 3✅

A lot of sum Code
Python 3✅

class GFG {


static int xorOfArray(int arr[], int n)
{

int xor_arr = 0;


for (int i = 0; i < n; i++) {


xor_arr = xor_arr ^ arr[i];
}


return xor_arr;
}


public static void main (String[] args)
{

int arr[] = { 3, 9, 12, 13, 15 };
int n = arr.length;


System.out.println(xorOfArray(arr, n));

}
}

XOR CODE

Emil's Function
Java 8

All Test Cases Passed

Removing a character
Python 3

LMPKA Code
Python3

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>
using namespace std;
char B[105];
int main(){
int n;
int ans=0;
scanf("%d", &n);
scanf("%s", B);
for(int i=2; B[i]; i++){
if(B[i-2] == '0' && B[i-1] == '1' && B[i] == '0') B[i] = '1', ans++;
}
printf("%d", ans);
return 0;
}

Beautiful string code

ArrayList<Integer> ar = new ArrayList<Integer>();
ArrayList<Integer> ar1 = new ArrayList<Integer>();
ArrayList<Integer> arr2= new ArrayList<Integer>();
ArrayList<Integer> sza= new ArrayList<Integer>();
ArrayList<Integer> p_n= new ArrayList<Integer>();

Scanner sc = new Scanner(System.in);

int a_size= sc.nextInt();
int m_size=sc.nextInt();
int[] a = new int[a_size];
for(int i=0;i<a_size;i++){
a[i]=sc.nextInt();
arr2.add(a[i]);
}
int[] p = new int[m_size];
for(int i=0;i<m_size;i++){
p[i]=sc.nextInt();
p_n.add(p[i]);
}
int[] sz=new int[m_size];
for(int i=0;i<m_size;i++){
sz[i]=sc.nextInt();
sza.add(sz[i]);
}

for(int i=0;i<a_size;i++)
{
for(int j=0;j<m_size;j++)
{
if(a[i]==p[j])
{
ar.add(p[j]);
}
}
}
int [] fr = new int [ar.size()];
int visited = -1;
for(int i = 0; i < ar.size(); i++){
int count = 1;
for(int j = i+1; j < ar.size(); j++){
if(ar.get(i).equals(ar.get(j))){
count++;
fr[j] = visited;
}
}
if(fr[i] != visited)
fr[i] = count;
}

for(int i = 0; i < fr.length; i++){
if(fr[i] != visited)
ar1.add(fr[i]);
}
ArrayList<Integer> pnew = new ArrayList<Integer>();
for(int l=0;l<sz.length;l++)
{
for(int h=0;h<sza.get(l);h++)
{
pnew.add(p_n.get(l));
}
}
int count=0;
for(int i = 0; i < pnew.size(); i++)
{
for(int j = i+1; j < pnew.size(); j++)
{
if(pnew.get(i).equals(pnew.get(j)))
{
count++;
}
}
}
System.out.println(count);
}
}


Sequences concatenation code

Xor Operation code

Rectangular operation Code ✅

Happy Hour
Python 3

MNC code
c++

String Updation code
Python 3✅

Book Distribution
C++