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Company Name : Uber
Role : SDE 1
Batch : 2024/2023/2022 passouts
Link : https://www.uber.com/global/en/careers/list/137776/
Role : SDE 1
Batch : 2024/2023/2022 passouts
Link : https://www.uber.com/global/en/careers/list/137776/
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Associate Software Engineer Role at iSign Tech
https://docs.google.com/forms/d/e/1FAIpQLSdtj-fmGQxITulW_qAYRYkugjCWH--NAZW0U9YxfolocQb3ZQ/viewform
https://docs.google.com/forms/d/e/1FAIpQLSdtj-fmGQxITulW_qAYRYkugjCWH--NAZW0U9YxfolocQb3ZQ/viewform
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Hiring freshers for the role of Back-end Developer Internship.
Role: Software Developer Intern (Back-end Developer)
Company: UXDLAB Software Pvt. Ltd.
Location: Sector 62, Noida (On-site)
Working Days: 5 (Mon-Fri)
Duration of Internship: 6 months
Requirements:
Technical Skills - NodeJs, HTML, CSS, Javascript etc.
Education - B.Tech with Computer Science or MCA
Joining Availability - Immediate Joiner
Interested candidates can share their resume at naina@uxdlab.us
Role: Software Developer Intern (Back-end Developer)
Company: UXDLAB Software Pvt. Ltd.
Location: Sector 62, Noida (On-site)
Working Days: 5 (Mon-Fri)
Duration of Internship: 6 months
Requirements:
Technical Skills - NodeJs, HTML, CSS, Javascript etc.
Education - B.Tech with Computer Science or MCA
Joining Availability - Immediate Joiner
Interested candidates can share their resume at naina@uxdlab.us
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
๐Are you ready to kickstart your career in the tech world?
We're actively looking for passionate and talented individuals to join our team in the following roles:
๐ป AI/ML ๐๐ฒ๐๐ฒ๐น๐ผ๐ฝ๐ฒ๐ฟ (0-6 months experience)
๐ฅ๏ธ Python ๐๐ฒ๐๐ฒ๐น๐ผ๐ฝ๐ฒ๐ฟ (0-6 months experience)
๐ ๐ช๐ผ๐ฟ๐ฑ๐ฃ๐ฟ๐ฒ๐๐ ๐๐ฒ๐๐ฒ๐น๐ผ๐ฝ๐ฒ๐ฟ (0-6 months experience)
๐จ ๐ช๐ฒ๐ฏ ๐๐ฒ๐๐ถ๐ด๐ป๐ฒ๐ฟ (0-6 months experience)
๐ ๐๐ผ๐ฐ๐ฎ๐๐ถ๐ผ๐ป: Indore
๐จ๐ป ๐๐น๐ถ๐ด๐ถ๐ฏ๐ถ๐น๐ถ๐๐: Freshers or candidates with up to 6 months of experience are welcome.
If you have the skills and enthusiasm to grow in a dynamic environment, weโd love to hear from you!
๐ฉ ๐๐ผ๐ ๐๐ผ ๐๐ฝ๐ฝ๐น๐: Send your resume to shikha.stevesai@gmail.com
We're actively looking for passionate and talented individuals to join our team in the following roles:
๐ป AI/ML ๐๐ฒ๐๐ฒ๐น๐ผ๐ฝ๐ฒ๐ฟ (0-6 months experience)
๐ฅ๏ธ Python ๐๐ฒ๐๐ฒ๐น๐ผ๐ฝ๐ฒ๐ฟ (0-6 months experience)
๐ ๐ช๐ผ๐ฟ๐ฑ๐ฃ๐ฟ๐ฒ๐๐ ๐๐ฒ๐๐ฒ๐น๐ผ๐ฝ๐ฒ๐ฟ (0-6 months experience)
๐จ ๐ช๐ฒ๐ฏ ๐๐ฒ๐๐ถ๐ด๐ป๐ฒ๐ฟ (0-6 months experience)
๐ ๐๐ผ๐ฐ๐ฎ๐๐ถ๐ผ๐ป: Indore
๐จ๐ป ๐๐น๐ถ๐ด๐ถ๐ฏ๐ถ๐น๐ถ๐๐: Freshers or candidates with up to 6 months of experience are welcome.
If you have the skills and enthusiasm to grow in a dynamic environment, weโd love to hear from you!
๐ฉ ๐๐ผ๐ ๐๐ผ ๐๐ฝ๐ฝ๐น๐: Send your resume to shikha.stevesai@gmail.com
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
๐HSBC Hiring
Role : Trainee Software Engineer
Eligibility : BE/B.Tech(2025) in CS / IT (with/without additional specialisation), CCE, AI ML, AI DS, Cybersecurity, Cloud
Salary : 6-10 LPA
Location : Pune
๐ปApply here : https://mycareer.hsbc.com/en_GB/external/PipelineDetail/Trainee-Software-Engineer/243852
Role : Trainee Software Engineer
Eligibility : BE/B.Tech(2025) in CS / IT (with/without additional specialisation), CCE, AI ML, AI DS, Cybersecurity, Cloud
Salary : 6-10 LPA
Location : Pune
๐ปApply here : https://mycareer.hsbc.com/en_GB/external/PipelineDetail/Trainee-Software-Engineer/243852
Hsbc
External Careers
typedef long long ll;
void solve() {
ll n = N;
vector<vector<ll>>arr(n, vector<ll>(3));
for (int i = 0; i < n; i++) {
arr[i] = {[0] = people[i] , [1] = starting[i] , [2] = ending[i]};
}
sort(arr.begin() , arr.end() , [&](vector<ll>& a , vector<ll>& b) {
if (a[1] == b[1]) return a[2] < b[2];
return a[1] < b[1];
});
ll sum = 0;
for (auto& x : arr) sum += x[0];
vector<ll>dp(n, -1);
auto recurr = [&](ll i , auto && recurr)->ll{
if (i >= n) return 0;
ll& ans = dp[i];
if (ans != -1) return ans; ans = 0;
ans = recurr(i + 1 , recurr);
ll low = i , high = n , val = arr[i][2];
while (high - low > 1) {
ll mid = (low + high) >> 1;
if (val >= arr[mid][1]) low = mid;
else high = mid;
}
ans = max(ans, arr[i][0] + recurr( low + 1 , recurr) );
return ans;
};
return sum - recurr(0, recurr);
}
Meeting Room โ
void solve() {
ll n = N;
vector<vector<ll>>arr(n, vector<ll>(3));
for (int i = 0; i < n; i++) {
arr[i] = {[0] = people[i] , [1] = starting[i] , [2] = ending[i]};
}
sort(arr.begin() , arr.end() , [&](vector<ll>& a , vector<ll>& b) {
if (a[1] == b[1]) return a[2] < b[2];
return a[1] < b[1];
});
ll sum = 0;
for (auto& x : arr) sum += x[0];
vector<ll>dp(n, -1);
auto recurr = [&](ll i , auto && recurr)->ll{
if (i >= n) return 0;
ll& ans = dp[i];
if (ans != -1) return ans; ans = 0;
ans = recurr(i + 1 , recurr);
ll low = i , high = n , val = arr[i][2];
while (high - low > 1) {
ll mid = (low + high) >> 1;
if (val >= arr[mid][1]) low = mid;
else high = mid;
}
ans = max(ans, arr[i][0] + recurr( low + 1 , recurr) );
return ans;
};
return sum - recurr(0, recurr);
}
Meeting Room โ
from collections import defaultdict, deque
def maxEqualGroups(a, b, c):
d = defaultdict(list)
for e, f in c:
e -= 1
f -= 1
d[e].append(f)
d[f].append(e)
g = [-1] * a
h = 0
def bfs(i):
j = deque([i])
g[i] = 0
k = [0, 0]
k[0] += 1
while j:
l = j.popleft()
m = g[l]
for n in d[l]:
if g[n] == -1:
g[n] = 1 - m
k[g[n]] += 1
j.append(n)
elif g[n] == m:
return None
return k
for o in range(a):
if g[o] == -1:
p = bfs(o)
if p is None:
return 0
h += min(p) * 2
return h // 2
Two groups โ
vector<int>freq(1000002,0);
int n = start.size();
for(int i=0; i<n; i++) {
freq[start[i]]++;
freq[end[i]+1]--;
}
for(int i=1; i<=1000001; i++) freq[i] += freq[i-1];
vector<int>temp;
for(int i=1; i<=1000000; i++) {
if(freq[i] >= k) temp.push_back(i);
}
vector<int>ans;
int p = q_start.size();
for(int i=0; i<p; i++) {
auto x = lower_bound(temp.begin(),temp.end(),q_start[i])-temp.begin();
auto y = upper_bound(temp.begin(),temp.end(),q_end[i])-temp.begin();
ans.push_back(y-x);
}
return ans;
Valid Number โ
int n = start.size();
for(int i=0; i<n; i++) {
freq[start[i]]++;
freq[end[i]+1]--;
}
for(int i=1; i<=1000001; i++) freq[i] += freq[i-1];
vector<int>temp;
for(int i=1; i<=1000000; i++) {
if(freq[i] >= k) temp.push_back(i);
}
vector<int>ans;
int p = q_start.size();
for(int i=0; i<p; i++) {
auto x = lower_bound(temp.begin(),temp.end(),q_start[i])-temp.begin();
auto y = upper_bound(temp.begin(),temp.end(),q_end[i])-temp.begin();
ans.push_back(y-x);
}
return ans;
Valid Number โ
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
int findLowestPrice(vector<vector<string>> products, vector<vector<string>> discounts) {
int cost = 0;
map<string, int> mp;
for (vector<string> &d : discounts) {
string id = d[0];
int gg = d[1][0] - '0';
int disc = stoi(d[2]);
if (gg == 0) {
if (mp[id].find(0) == mp[id].end()) {
mp[id][0] = disc;
}
}
else {
mp[id][0] = min(mp[id][0], disc);
}
else mp[id][gg]=max(mp[id][gg],disc);
}
for (vector<string> &p : products) {
int price = stoi(p[0]), no_gravity12 = price;
for (int i = 1; i < m; i++) {
if (p[i] != "EMPTY") {
string id = p[i];
int d1 = mp[id][1];
int d2 = mp[id][2];
int price0 = mp[id].find(0) != mp[id].end() ? mp[id][0] : 0;
int price1 = max(0, price - (d1 * price + 99)/100);
int price2 = max(0, price - d2);
gg = min(gg, price0, price1, price2);
}
}
cost += gg;
}
return cost;
}
Shopping Cart Billing โ
int cost = 0;
map<string, int> mp;
for (vector<string> &d : discounts) {
string id = d[0];
int gg = d[1][0] - '0';
int disc = stoi(d[2]);
if (gg == 0) {
if (mp[id].find(0) == mp[id].end()) {
mp[id][0] = disc;
}
}
else {
mp[id][0] = min(mp[id][0], disc);
}
else mp[id][gg]=max(mp[id][gg],disc);
}
for (vector<string> &p : products) {
int price = stoi(p[0]), no_gravity12 = price;
for (int i = 1; i < m; i++) {
if (p[i] != "EMPTY") {
string id = p[i];
int d1 = mp[id][1];
int d2 = mp[id][2];
int price0 = mp[id].find(0) != mp[id].end() ? mp[id][0] : 0;
int price1 = max(0, price - (d1 * price + 99)/100);
int price2 = max(0, price - d2);
gg = min(gg, price0, price1, price2);
}
}
cost += gg;
}
return cost;
}
Shopping Cart Billing โ
Distance between two points โ
Zscaler
Zscaler
SELECT ID, NAME
FROM CUSTOMER
ORDER BY NAME DESC, ID ASC;
Order management system โ
Zscaler
FROM CUSTOMER
ORDER BY NAME DESC, ID ASC;
Order management system โ
Zscaler
vector<string> processLogs(vector<string> logs, int threshold)
}
Suspicious activity from logs โ
{
unordered_map<string, int> transaction_cou
nt;
for (const string& log : logs
) {
istringstream iss(lo
g);
string sender, recipie
nt;
int amou
nt;
iss >> sender >> recipient >> amou
nt;
transaction_count[sender]
++;
if (sender != recipient
) {
transaction_count[recipient]
++;
}
}
vector<string> suspicious_use
rs;
for (const auto& entry : transaction_count
) {
if (entry.second >= threshold
) {
suspicious_users.push_back(entry.firs
t);
}
}
sort(suspicious_users.begin(), suspicious_users.end(
));
return suspicious_use
rs
;}
Suspicious activity from logs โ
#include <iostream>
#include <vector>
#include <queue>
using namespace std;
int findMinWeight(vector<int> weights, int d) {
priority_queue<int> maxHeap(weights.begin(), weights.end());
for (int i = 0; i < d; ++i) {
int maxWeight = maxHeap.top();
maxHeap.pop();
int remainingWeight = maxWeight / 2;
maxHeap.push(maxWeight - remainingWeight);
}
int totalWeight = 0;
while (!maxHeap.empty()) {
totalWeight += maxHeap.top();
maxHeap.pop();
}
return totalWeight;
}
Minimum total weight โ
#include <vector>
#include <queue>
using namespace std;
int findMinWeight(vector<int> weights, int d) {
priority_queue<int> maxHeap(weights.begin(), weights.end());
for (int i = 0; i < d; ++i) {
int maxWeight = maxHeap.top();
maxHeap.pop();
int remainingWeight = maxWeight / 2;
maxHeap.push(maxWeight - remainingWeight);
}
int totalWeight = 0;
while (!maxHeap.empty()) {
totalWeight += maxHeap.top();
maxHeap.pop();
}
return totalWeight;
}
Minimum total weight โ
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
class Solution {
public:
int maximumInvitations(vector<int>& favourite) {
int n = favourite.size();
vector<bool> duoNode(n, false);
vector<int> indegree(n, 0);
vector<int> maxPathAt(n, 1);
for (int i = 0; i < n; i++) {
indegree[favourite[i]]++;
if (favourite[favourite[i]] == i) {
duoNode[i] = true;
duoNode[favourite[i]] = true;
}
}
int ans = 0;
vector<bool> visited(n, false);
for (int i = 0; i < n; i++) {
if (!indegree[i]) {
int cur = i;
while (!duoNode[cur] && !visited[cur] && !indegree[cur]) {
visited[cur] = true;
maxPathAt[favourite[cur]] = max(maxPathAt[favourite[cur]], maxPathAt[cur] + 1);
cur = favourite[cur];
indegree[cur]--;
}
}
}
for (int i = 0; i < n; i++) {
if (duoNode[i]) {
ans += maxPathAt[i];
}
}
int offset = 1;
fill(maxPathAt.begin(), maxPathAt.end(), 0);
fill(visited.begin(), visited.end(), false);
for (int i = 0; i < n; i++) {
if (!visited[i]) {
int prev, cur = i;
while (!maxPathAt[cur]) {
maxPathAt[cur] = offset++;
prev = cur;
cur = favourite[cur];
}
if (!visited[cur]) {
ans = max(ans, maxPathAt[prev] - maxPathAt[cur] + 1);
}
cur = i;
while (!visited[cur]) {
visited[cur] = true;
cur = favourite[cur];
}
}
}
return ans;
}
};
int main() {
Solution solution;
int N;
cin >> N;
vector<int> favourite(N);
for (int i = 0; i < N; i++) {
cin >> favourite[i];
favourite[i]--;
}
int result = solution.maximumInvitations(favourite);
cout << result << endl;
return 0;
}
Barclays โ
#include <vector>
#include <algorithm>
using namespace std;
class Solution {
public:
int maximumInvitations(vector<int>& favourite) {
int n = favourite.size();
vector<bool> duoNode(n, false);
vector<int> indegree(n, 0);
vector<int> maxPathAt(n, 1);
for (int i = 0; i < n; i++) {
indegree[favourite[i]]++;
if (favourite[favourite[i]] == i) {
duoNode[i] = true;
duoNode[favourite[i]] = true;
}
}
int ans = 0;
vector<bool> visited(n, false);
for (int i = 0; i < n; i++) {
if (!indegree[i]) {
int cur = i;
while (!duoNode[cur] && !visited[cur] && !indegree[cur]) {
visited[cur] = true;
maxPathAt[favourite[cur]] = max(maxPathAt[favourite[cur]], maxPathAt[cur] + 1);
cur = favourite[cur];
indegree[cur]--;
}
}
}
for (int i = 0; i < n; i++) {
if (duoNode[i]) {
ans += maxPathAt[i];
}
}
int offset = 1;
fill(maxPathAt.begin(), maxPathAt.end(), 0);
fill(visited.begin(), visited.end(), false);
for (int i = 0; i < n; i++) {
if (!visited[i]) {
int prev, cur = i;
while (!maxPathAt[cur]) {
maxPathAt[cur] = offset++;
prev = cur;
cur = favourite[cur];
}
if (!visited[cur]) {
ans = max(ans, maxPathAt[prev] - maxPathAt[cur] + 1);
}
cur = i;
while (!visited[cur]) {
visited[cur] = true;
cur = favourite[cur];
}
}
}
return ans;
}
};
int main() {
Solution solution;
int N;
cin >> N;
vector<int> favourite(N);
for (int i = 0; i < N; i++) {
cin >> favourite[i];
favourite[i]--;
}
int result = solution.maximumInvitations(favourite);
cout << result << endl;
return 0;
}
Barclays โ