Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
https://surveys.infosysapps.com/r/a/SPCampusregistration_NATCOLLEGES25batch
Company:-Infosys
Package:- 9.5 lpa
Role:- SP
Good opportunity โ โ๏ธ
Apply assap โ โ๏ธ
Batches:-2023/2024/2025
Company:-Infosys
Package:- 9.5 lpa
Role:- SP
Good opportunity โ โ๏ธ
Apply assap โ โ๏ธ
Batches:-2023/2024/2025
Infosysapps
Infosys | Surveys
Create Surveys. Collect feedback through a computer assisted, Mobile friendly method. Design Surveys, Send Request , Analyze response and more ...
Forwarded from OffCampus Jobs | OnCampus Jobs | Daily Jobs Updates | Lastest Jobs | All Jobs | CSE Jobs | Fresher Jobs โฅ (Dushyant)
Instahyre
SDE 1 job at GreenStitch.io - Instahyre
GreenStitch.io is looking for a SDE 1 in Bangalore with 2-6 years of experience in Full-Stack Development, Node.js, React.js, etc. Apply today and get your dream job at GreenStitch.io!
Today anyone give exam Visa /Google just React
#include <vector>
#include <iostream>
using namespace std;
int countConnections(const vector<vector<int>>& matrix) {
int m = matrix.size();
int n = matrix[0].size();
int count = 0;
for (int i = 0; i < m; ++i) {
for (int j = 0; j < n; ++j) {
if (matrix[i][j] == 1) {
if (i - 1 >= 0 && j - 1 >= 0 && matrix[i - 1][j - 1] == 1) {
count++;
}
if (i - 1 >= 0 && matrix[i - 1][j] == 1) {
count++;
}
if (i - 1 >= 0 && j + 1 < n && matrix[i - 1][j + 1] == 1) {
count++;
}
if (j + 1 < n && matrix[i][j + 1] == 1) {
count++;
}
}
}
}
return count;
}
Counting Connections in matrix โ
def solve(transactions, userHistory):
preferredRegion, minValue, maxValue, minScore, maxScore, accountLimit = userHistory
scrutinized = []
for transaction in transactions:
_, region, value, score, _ = transaction
if value <= accountLimit:
match_score = 0
if region == preferredRegion:
match_score += 2
if minValue <= value < maxValue:
match_score += 3
if minScore <= score <= maxScore:
match_score += 2
scrutinized.append(match_score)
scrutinyScore = 0
n = len(scrutinized)
for i in range(n):
for j in range(i + 1, n):
scrutinyScore += abs(scrutinized[i] - scrutinized[j])
return scrutinyScore
Banking Management -I โ
UKG
def solve():
n = int(input())
a = list(map(int, input().split()))
from statistics import median as mm
pos = {}
for i, v in enumerate(a):
if v not in pos:
pos[v] = []
pos[v].append(i)
result = []
for v, indices in pos.items():
indices.sort()
m = len(indices)
mid_index = mm(indices)
s = sum(a[i] for i in indices)
result.append((mid_index, s))
result.sort()
print([x[1] for x in result])
solve()
Shrink the array โ
#include <iostream>
#include <vector>
#include <stack>
#include <algorithm>
using namespace std;
int largestSquareArea(vector<int>& cityLine) {
int n = cityLine.size();
stack<int> st;
int maxSquareArea = 0;
vector<int> left(n), right(n, n);
for (int i = 0; i < n; ++i) {
while (!st.empty() && cityLine[st.top()] >= cityLine[i]) {
st.pop();
}
left[i] = st.empty() ? -1 : st.top();
st.push(i);
}
while (!st.empty()) st.pop();
for (int i = n - 1; i >= 0; --i) {
while (!st.empty() && cityLine[st.top()] >= cityLine[i]) {
st.pop();
}
right[i] = st.empty() ? n : st.top();
st.push(i);
}
for (int i = 0; i < n; ++i) {
int height = cityLine[i];
int width = right[i] - left[i] - 1;
int side = min(height, width);
maxSquareArea = max(maxSquareArea, side * side);
}
return maxSquareArea;
}
Visa โ
#include <vector>
#include <stack>
#include <algorithm>
using namespace std;
int largestSquareArea(vector<int>& cityLine) {
int n = cityLine.size();
stack<int> st;
int maxSquareArea = 0;
vector<int> left(n), right(n, n);
for (int i = 0; i < n; ++i) {
while (!st.empty() && cityLine[st.top()] >= cityLine[i]) {
st.pop();
}
left[i] = st.empty() ? -1 : st.top();
st.push(i);
}
while (!st.empty()) st.pop();
for (int i = n - 1; i >= 0; --i) {
while (!st.empty() && cityLine[st.top()] >= cityLine[i]) {
st.pop();
}
right[i] = st.empty() ? n : st.top();
st.push(i);
}
for (int i = 0; i < n; ++i) {
int height = cityLine[i];
int width = right[i] - left[i] - 1;
int side = min(height, width);
maxSquareArea = max(maxSquareArea, side * side);
}
return maxSquareArea;
}
Visa โ
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int T = scanner.nextInt();
while (T-- > 0) {
int N = scanner.nextInt();
int M = scanner.nextInt();
int K = scanner.nextInt();
Map<String, Integer> rowCount = new HashMap<>();
for (int i = 0; i < N; i++) {
StringBuilder rowPattern = new StringBuilder();
for (int j = 0; j < M; j++) {
int val = scanner.nextInt();
rowPattern.append(val);
}
String pattern = rowPattern.toString();
rowCount.put(pattern, rowCount.getOrDefault(pattern, 0) + 1);
}
int maxEqualRows = 0;
Set<String> processedPatterns = new HashSet<>();
for (String pattern : rowCount.keySet()) {
if (processedPatterns.contains(pattern)) {
continue;
}
StringBuilder complementBuilder = new StringBuilder();
for (int i = 0; i < pattern.length(); i++) {
complementBuilder.append(pattern.charAt(i) == '0' ? '1' : '0');
}
String complement = complementBuilder.toString();
int countPattern = rowCount.get(pattern);
int countComplement = rowCount.getOrDefault(complement, 0);
int inversionsNeeded = Math.min(countPattern, countComplement);
if (inversionsNeeded <= K) {
int totalRows = countPattern + countComplement;
maxEqualRows = Math.max(maxEqualRows, totalRows);
}
processedPatterns.add(pattern);
processedPatterns.add(complement);
}
System.out.println(maxEqualRows);
}
scanner.close();
}
}
Equal Rows โ
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
import java.util.*; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int T = scanner.nextInt(); while (T-- > 0) { int N = scanner.nextInt(); int Mโฆ
from collections import defaultdict
def solve(N, M, K, mat):
rf, irf = defaultdict(int), defaultdict(int)
for i in range(N):
r = tuple(mat[i])
ir = tuple(1 - x for x in mat[i])
rf[r] += 1
irf[ir] += 1
res = 0
for r, c in rf.items():
res = max(res, c)
if K > 0:
res = max(res, c + min(K, irf[r]))
return res
Equal Rows โ
#include <vector>
#include <iostream>
using namespace std;
int longestDiagonalSegment(vector<vector<int>>& matrix) {
int rows = matrix.size();
int cols = matrix[0].size();
int longest = 0;
int dR[] = {-1, 1, -1, 1};
int dC[] = {1, 1, -1, -1};
for (int r = 0; r < rows; ++r) {
for (int c = 0; c < cols; ++c) {
for (int dir = 0; dir < 4; ++dir) {
int len = 0;
int rPos = r, cPos = c;
int pattern[] = {1, 2, 0, 2, 0, 2, 0};
int pIdx = 0;
while (rPos >= 0 && rPos < rows && cPos >= 0 && cPos < cols) {
if (matrix[rPos][cPos] == pattern[pIdx]) {
++len;
pIdx = (pIdx + 1) % 7;
} else {
break;
}
rPos += dR[dir];
cPos += dC[dir];
}
longest = max(longest, len);
}
}
}
return longest;
}
Visa โ
def canonical_form(s):
mapping = {}
form = []
next_index = 0
for char in s:
if char not in mapping:
mapping[char] = next_index
next_index += 1
form.append(mapping[char])
return tuple(form)
def solve(N, Q, S, K):
canonical_map = {}
for string in S:
form = canonical_form(string)
if form not in canonical_map:
canonical_map[form] = 0
canonical_map[form] += 1
result = []
for query in K:
query_form = canonical_form(query)
result.append(canonical_map.get(query_form, 0))
return result
Google โ
mapping = {}
form = []
next_index = 0
for char in s:
if char not in mapping:
mapping[char] = next_index
next_index += 1
form.append(mapping[char])
return tuple(form)
def solve(N, Q, S, K):
canonical_map = {}
for string in S:
form = canonical_form(string)
if form not in canonical_map:
canonical_map[form] = 0
canonical_map[form] += 1
result = []
for query in K:
query_form = canonical_form(query)
result.append(canonical_map.get(query_form, 0))
return result
Google โ
#include <vector>
using namespace std;
vector<int> solution(vector<int> forest, int bird) {
vector<int> pos;
int total_length = 0;
int direction = 1;
int n = forest.size();
while (total_length < 100) {
if (direction == 1) {
for (int i = bird + 1; i < n; i++) {
if (forest[i] > 0) {
pos.push_back(i);
total_length += forest[i];
forest[i] = 0;
break;
}
}
} else {
for (int i = bird - 1; i >= 0; i--) {
if (forest[i] > 0) {
pos.push_back(i);
total_length += forest[i];
forest[i] = 0;
break;
}
}
}
direction *= -1;
}
return pos;
}
Visa โ
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BharatPe is hiring SDE
For 2020, 2021, 2022, 2023 grads
https://www.linkedin.com/posts/bharatpe_join-bharatpe-activity-7265335537765363712-EXs7
Expected CTC -> 30-50LPA
For 2020, 2021, 2022, 2023 grads
https://www.linkedin.com/posts/bharatpe_join-bharatpe-activity-7265335537765363712-EXs7
Expected CTC -> 30-50LPA
Linkedin
Join BharatPe | BharatPe
๐ Join the BharatPe Tech Team!
Weโre on the lookout for passionate Software Development Engineers to build cutting-edge fintech solutions. If innovation, growth, and impact excite you, this is your chance to make a difference!
๐ป Apply now and be part ofโฆ
Weโre on the lookout for passionate Software Development Engineers to build cutting-edge fintech solutions. If innovation, growth, and impact excite you, this is your chance to make a difference!
๐ป Apply now and be part ofโฆ