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๐Minfy is hiring for Full stack Developer - MERN
Experience: 0 - 1 year's
Apply here: https://www.linkedin.com/jobs/view/4044807271/?alternateChannel=search
Experience: 0 - 1 year's
Apply here: https://www.linkedin.com/jobs/view/4044807271/?alternateChannel=search
Linkedin
Minfy hiring Full stack Developer - MERN in Hyderabad, Telangana, India | LinkedIn
Posted 9:45:02 AM. Job Description:We are looking for a talented Full Stack Developer proficient in the MERN (MongoDB,โฆSee this and similar jobs on LinkedIn.
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Genesis Ray is hiring for Backend Developer Intern
Apply here: https://docs.google.com/forms/d/e/1FAIpQLSeoHhBvNp2wKjDASV85cKKVS9OoBvkruXbGVosWgAcfda6Vig/viewform
Apply here: https://docs.google.com/forms/d/e/1FAIpQLSeoHhBvNp2wKjDASV85cKKVS9OoBvkruXbGVosWgAcfda6Vig/viewform
โค1
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Pixxel
Product Management Intern
Job Description
Role: Product Management Intern
Employment Type: Internship
Educational Qualification: B.tech
Work Experience: 0-6 months
Role Description: Function: Product Management
At Pixxel, Itโs not enough for us to just dump satellite images downโฆ
Role: Product Management Intern
Employment Type: Internship
Educational Qualification: B.tech
Work Experience: 0-6 months
Role Description: Function: Product Management
At Pixxel, Itโs not enough for us to just dump satellite images downโฆ
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Send your resume to hr@technogenesis.in
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
import java.util.*;
public class Main {
static int countMatches(List<String> grid1, List<String> grid2) {
int count = 0;
int m = grid1.size();
int n = grid1.get(0).length();
int[][] g1 = new int[m][n];
int[][] g2 = new int[m][n];
int[][] orMap = new int[m][n];
for(int i=0; i<m; i++){
char[] str1 = grid1.get(i).toCharArray();
char[] str2 = grid2.get(i).toCharArray();
for(int j=0; j<n; j++){
g1[i][j] = str1[j] - '0';
g2[i][j] = str2[j] - '0';
}
}
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
orMap[i][j] = g1[i][j] | g2[i][j];
}
}
for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
if(orMap[i][j] == 1 && dfs(g1, g2, orMap, i, j)) count++;
}
}
return count;
}
private static boolean dfs(int[][] g1, int[][] g2, int[][] orMap, int i, int j) {
int m = orMap.length;
int n = orMap[0].length;
orMap[i][j] = 0;
boolean up = true, down = true, left = true, right = true;
if(i > 0 && orMap[i-1][j] == 1) up = dfs(g1, g2, orMap, i-1, j);
if(i < m - 1 && orMap[i+1][j] == 1) down = dfs(g1, g2, orMap, i+1, j);
if(j > 0 && orMap[i][j-1] == 1) left = dfs(g1, g2, orMap, i, j-1);
if(j < n - 1 && orMap[i][j+1] == 1) right = dfs(g1, g2, orMap, i, j+1);
return g1[i][j] == 1 && g2[i][j] == 1 && up && down && left && right;
}
Pace Securities โ
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
#include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define all(x) x.begin(), x.end()
#define endl '\n'
#define int long long
#define MOD 1000000007
#define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
using namespace std;
int getMax(int i, int j, vector<vector<int>>& dp) {
int maxValue = dp[i][j];
if (j - 1 >= 0) maxValue = max(maxValue, dp[i][j - 1]);
if (j + 1 < dp[0].size()) maxValue = max(maxValue, dp[i][j + 1]);
return maxValue;
}
void calc(vector<vector<int>>& dp) {
for (int i = dp.size() - 2; i >= 1; i--) {
for (int j = 0; j < dp[0].size(); j++) {
dp[i][j] += getMax(i + 1, j, dp);
}
}
}
int32_t main() {
fastio
int m, n;
cin >> m >> n;
vector<vector<int>> dp(m, vector<int>(n, 0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
cin >> dp[i][j];
}
}
vector<vector<int>> opposite(m, vector<int>(n, 0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
opposite[i][j] = dp[m - i - 1][j];
}
}
calc(dp);
calc(opposite);
int p, q;
cin >> p >> q;
int ans = dp[0][p] + getMax(1, p, dp);
ans = max(ans, opposite[0][q] + getMax(1, q, opposite));
cout << ans << endl;
return 0;
}
#define ll long long
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define all(x) x.begin(), x.end()
#define endl '\n'
#define int long long
#define MOD 1000000007
#define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
using namespace std;
int getMax(int i, int j, vector<vector<int>>& dp) {
int maxValue = dp[i][j];
if (j - 1 >= 0) maxValue = max(maxValue, dp[i][j - 1]);
if (j + 1 < dp[0].size()) maxValue = max(maxValue, dp[i][j + 1]);
return maxValue;
}
void calc(vector<vector<int>>& dp) {
for (int i = dp.size() - 2; i >= 1; i--) {
for (int j = 0; j < dp[0].size(); j++) {
dp[i][j] += getMax(i + 1, j, dp);
}
}
}
int32_t main() {
fastio
int m, n;
cin >> m >> n;
vector<vector<int>> dp(m, vector<int>(n, 0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
cin >> dp[i][j];
}
}
vector<vector<int>> opposite(m, vector<int>(n, 0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
opposite[i][j] = dp[m - i - 1][j];
}
}
calc(dp);
calc(opposite);
int p, q;
cin >> p >> q;
int ans = dp[0][p] + getMax(1, p, dp);
ans = max(ans, opposite[0][q] + getMax(1, q, opposite));
cout << ans << endl;
return 0;
}
#include <iostream>
#include <vector>
using namespace std;
int fun(int n) {
int total = 0;
while (n > 0) {
total += n % 10;
n /= 10;
}
return total;
}
int solve(int N) {
int total_sum = 0;
vector<int> elements;
for (int i = 1; i <= N; ++i) {
elements.push_back(i);
}
fun(N);
while (elements.size() > 1) {
vector<int> new_elements;
for (size_t index = 0; index < elements.size(); ++index) {
int value = elements[index];
if (index % 2 == 1) {
new_elements.push_back(value);
} else {
total_sum += value;
}
}
elements = new_elements;
}
return total_sum;
}
Range Game โ
#include <vector>
using namespace std;
int fun(int n) {
int total = 0;
while (n > 0) {
total += n % 10;
n /= 10;
}
return total;
}
int solve(int N) {
int total_sum = 0;
vector<int> elements;
for (int i = 1; i <= N; ++i) {
elements.push_back(i);
}
fun(N);
while (elements.size() > 1) {
vector<int> new_elements;
for (size_t index = 0; index < elements.size(); ++index) {
int value = elements[index];
if (index % 2 == 1) {
new_elements.push_back(value);
} else {
total_sum += value;
}
}
elements = new_elements;
}
return total_sum;
}
Range Game โ
โค1
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Linkedin
Anil Kumar on LinkedIn: #hiring #datascience #internship #careeropportunity #joinus | 10 comments
๐ Exciting Opportunity Alert! Join Our Team as a Data Science Intern! ๐
We're thrilled to announce that we're expanding our team and looking for a passionateโฆ | 10 comments on LinkedIn
We're thrilled to announce that we're expanding our team and looking for a passionateโฆ | 10 comments on LinkedIn
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Linkedin
Sarath Chandar Sukumar on LinkedIn: Vaken Technologies Home - VAKEN TECHNOLOGIES
๐ Weโre Hiring! ๐
Join the #Vaken family and be a part of something transformative! ๐
Weโre looking for passionate individuals to join our team as weโฆ
Join the #Vaken family and be a part of something transformative! ๐
Weโre looking for passionate individuals to join our team as weโฆ
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MasterCard hiring Data Engineers
Freshers eligible
Apply Here : https://mastercard.wd1.myworkdayjobs.com/CorporateCareers/job/Pune-India/Data-Engineer-II_R-212415
Freshers eligible
Apply Here : https://mastercard.wd1.myworkdayjobs.com/CorporateCareers/job/Pune-India/Data-Engineer-II_R-212415
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Eurofins hiring Associate Software Engineer
0-1 year experience
6-12 LPA CTC
Apply Here : https://jobs.smartrecruiters.com/Eurofins/744000018924766-associate-software-engineer-sharepoint
0-1 year experience
6-12 LPA CTC
Apply Here : https://jobs.smartrecruiters.com/Eurofins/744000018924766-associate-software-engineer-sharepoint
Eurofins
Eurofins is looking for a Associate Software Engineer - Sharepoint in Bengaluru, Karnataka, India
POSITION TITLE: Associate Software Engineer:REPORTING TO: โCollaborative Platforms and IT Toolsโ ManagerWORKING LOCATION: Bangalore, IndiaOBJECTIVE: Eurofins Collaborative Platforms and IT Tools T...
๐๐ฆ ๐๐น๐ด๐ผ ๐ป ๐ ใ๐๐ผ๐บ๐ฝ๐ฒ๐๐ถ๐๐ถ๐๐ฒ ๐ฃ๐ฟ๐ผ๐ด๐ฟ๐ฎ๐บ๐บ๐ถ๐ป๐ดใ
Photo
#include <iostream>
#include <vector>
#include <queue>
using namespace std;
int n;
void dfs(int i, int j, vector<string>& highways, vector<vector<bool>>& visited) {
if (i < 0 || i > 1 || j < 0 || j >= n || highways[i][j] == 'x' || visited[i][j])
return;
visited[i][j] = true;
dfs(i, j + 1, highways, visited);
dfs(i, j - 1, highways, visited);
dfs(1 - i, j, highways, visited);
}
int countComponents(vector<string>& highways) {
vector<vector<bool>> visited(2, vector<bool>(n, false));
int components = 0;
for (int i = 0; i < 2; ++i) {
for (int j = 0; j < n; ++j) {
if (!visited[i][j] && highways[i][j] == 'o') {
components++;
dfs(i, j, highways, visited);
}
}
}
return components;
}
int main() {
cin >> n;
vector<string> highways(2);
cin >> highways[0] >> highways[1];
int initialComponents = countComponents(highways);
if (initialComponents >= 3) {
cout << 0 << endl;
return 0;
}
int criticalSegments = 0;
for (int i = 0; i < 2; ++i) {
for (int j = 0; j < n; ++j) {
if (highways[i][j] == 'o') {
highways[i][j] = 'x';
int newComponents = countComponents(highways);
if (newComponents == 3) {
criticalSegments++;
}
highways[i][j] = 'o';
}
}
}
cout << criticalSegments << endl;
return 0;
}
Road Network Breakdown โ
Juspay
๐1