Company Name: Caterpillar
Role: Associate Software Engineer

Batch eligible: 2023 and 2024 grads

Apply: https://careers.caterpillar.com/en/jobs/job/r0000257330-associate-software-engineer/

Company Name: NI
Role: Software Engineer

Batch eligible: 2023 and 2024 grads

Apply: https://pef.fa.us1.oraclecloud.com/hcmUI/CandidateExperience/en/sites/CX_1/job/9331

Awign is hiring for Product Intern

10 k per month stipend

Send resume to : anup.pohaney@awign.com

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Location: Gurugram
Type: Full-time position at Gurugram Office
Experience: 0-2 yrs of Experience (Freshers/Recent Graduates can also apply) (Flutter Experience Preferred but any mobile development experience will be good enough)
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Scalong AI is hiring for Postgres DBA role

2024/ 2023 batch passouts eligible

Noida location

Send resume at : kajalm@ibosstech-us.com
yashikas@ibosstech-us.com

int mincost(vector<int> &pods,vector<int> &cost){
  map<int,multiset<int>> mp;
  for(int i=0;i<pods.size();i++){
    mp[pods[i]].insert(cost[i]);
  }
  int ans = 0;
  int curr = (*mp.begin()).first,sm = 0;
  multiset<int> se;
  while(1){
    if(se.size()==0){
      if(mp.lower_bound(curr) == mp.end()) break;
      curr = (*mp.lower_bound(curr)).first;
    }

    if(mp.find(curr) != mp.end())
    for(auto &x:mp[curr]){
        se.insert(x);
        sm += x;
    }

    auto it = se.end();
    it--;
    sm -= *it;
    ans += sm;
    se.erase(it);
    curr++;
  }

  return ans;
}

Weird Pod Count ✅

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

bool canCoverAllHouses(const vector<int>& houses, int N, int K, int P) {
    int count = 0;
    int i = 0;
    while (i < N && count < K) {
        int location = houses[i] + P;
        count++;
        while (i < N && houses[i] <= location + P) {
            i++;
        }
    }
    return i == N;
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
   
    int N, K;
    cin >> N >> K;
   
    vector<int> houses(N);
    for (int i = 0; i < N; ++i) {
        cin >> houses[i];
    }
   
    sort(houses.begin(), houses.end());
   
    int left = 0;
    int right = houses[N-1] - houses[0];
    int result = right;
   
    while (left <= right) {
        int mid = left + (right - left) / 2;
        if (canCoverAllHouses(houses, N, K, mid)) {
            result = mid;
            right = mid - 1;
        } else {
            left = mid + 1;
        }
    }
   
    cout << result << '\n';
   
    return 0;
}

PhonePe ✅

#include <bits/stdc++.h>
#define ll long long  
using namespace std; 
vector<ll> solve(ll n,ll m,vector<ll>&txt,vector<ll>& pat) 
{
    vector<ll>mask(UCHAR_MAX+1,~0);
    for (ll i=0;i<m;i++) 
    {
        mask[pat[i]]&=~(1U<<i);
    }
    vector<ll>result;
    ll R=~1;
    vector<ll>Rm(2,~1);
    for (ll i=0;i<n;i++) 
    {
        ll old=R;
        R|=mask[txt[i]];
        R<<=1;
        ll tmp=Rm[1];
        Rm[1]=(old&(Rm[1]|mask[txt[i]]))<<1;
        old=tmp;
        if((Rm[1]&(1U<<m))==0) 
        {
            result.push_back(i-m+2);
        }
    }
    return result;
}
signed main() 
{
    ll n,m; cin>>n>>m;
    vector<ll>txt(n),pat(m);
    for(ll i=0;i<n;i++) cin>>txt[i];
    for(ll i=0;i<m;i++) cin>>pat[i];
    auto ans=solve(n,m,txt,pat);
    cout<<ans.size()<<endl;
    for(auto it:ans) cout<<it<<" ";
    return 0;
}

Phonepe ✅
Find my file

#include <iostream>
#include <vector>
#include <unordered_set>
#include <string>
using namespace std;


bool containsDislikedDigits(int number, const unordered_set<int>& dislikedDigits) {
    while (number > 0) {
        if (dislikedDigits.find(number % 10) != dislikedDigits.end()) {
            return true;
        }
        number /= 10;
    }
    return false;
}

int solve(int N, int k, vector<int>& d) {
    unordered_set<int> dislikedDigits(d.begin(), d.end());
   
    while (containsDislikedDigits(N, dislikedDigits)) {
        ++N;
    }
   
    return N;
}

int main() {
    int N, k;
    cin >> N >> k;

    vector<int> d(k);
    for (int i = 0; i < k; ++i) {
        cin >> d[i];
    }

    int result = solve(N, k, d);
    cout << result << endl;

    return 0;
}

//minimum amount
Increff✅

#include <iostream>
#include <vector>
#include <unordered_map>
#include <string>
#include <sstream>
#include <algorithm>
#include <stdexcept>

using namespace std;

struct U {
    int i;
    bool a;
};

struct C {
    unordered_map<int, U> u;
    unordered_map<int, int> m;

    void p(vector<vector<string>>& e) {
        for (const auto& ev : e) {
            string a = ev[0];
            int t = 0;
            try {
                t = stoi(ev[1]);
            } catch (const invalid_argument& ex) {
                cerr << "Invalid timestamp: " << ev[1] << endl;
                continue;
            }

            if (a == "MESSAGE") {
                string ml = ev[2];
                istringstream iss(ml);
                string tk;
                while (iss >> tk) {
                    if (tk == "ALL") {
                        for (auto& us : u) {
                            m[us.first]++;
                        }
                    } else if (tk == "HERE") {
                        for (auto& us : u) {
                            if (us.second.a) {
                                m[us.first]++;
                            }
                        }
                    } else if (tk.size() >= 3) {
                        try {
                            int id = stoi(tk.substr(2));
                            m[id]++;
                        } catch (const invalid_argument& ex) {
                            cerr << "Invalid user ID: " << tk.substr(2) << endl;
                        }
                    }
                }
            } else if (a == "OFFLINE" && ev.size() >= 3) {
                string idStr = ev[2].substr(2);
                if (!idStr.empty()) {
                    try {
                        int id = stoi(idStr);
                        if (u.find(id) != u.end()) {
                            u[id].a = false;
                            m[id]--;
                            m[-1]--;
                            if (u[id].a) {
                                m[-2]--;
                            }
                        }
                    } catch (const invalid_argument& ex) {
                        cerr << "Invalid user ID: " << idStr << endl;
                    }
                }
            }
        }
    }

    vector<string> g() {
        vector<string> r;
        for (const auto& me : m) {
            if (me.first >= 0) {
                r.push_back("id" + to_string(me.first) + " - " + to_string(me.second));
            }
        }
        sort(r.begin(), r.end());
        return r;
    }
};

int main() {
    vector<vector<string>> e = {
        {"MESSAGE", "0", "ALL id158 id42"},
        {"OFFLINE", "1", "id158"},
        {"MESSAGE", "2", "id158 id158"},
        {"OFFLINE", "3", "id23"},
        {"MESSAGE", "60", "HERE id158 id42 id23"},
        {"MESSAGE", "61", "HERE"}
    };

    C c;
    c.p(e);
    vector<string> r = c.g();
    for (const string& s : r) {
        cout << s << endl;
    }
    return 0;
}

def min_cost_to_make_strongly_connected(N, tracks):
    from collections import defaultdict, deque
    import heapq

    def kosaraju_scc(N, adj_list, rev_adj_list):
        def dfs(node, adj_list, visited, stack):
            visited[node] = True
            for neighbor, _ in adj_list[node]:
                if not visited[neighbor]:
                    dfs(neighbor, adj_list, visited, stack)
            stack.append(node)

        def reverse_dfs(node, rev_adj_list, visited, scc):
            visited[node] = True
            scc.append(node)
            for neighbor in rev_adj_list[node]:
                if not visited[neighbor]:
                    reverse_dfs(neighbor, rev_adj_list, visited, scc)

        stack = []
        visited = [False] * (N + 1)
        for i in range(1, N + 1):
            if not visited[i]:
                dfs(i, adj_list, visited, stack)

        visited = [False] * (N + 1)
        sccs = []
        while stack:
            node = stack.pop()
            if not visited[node]:
                scc = []
                reverse_dfs(node, rev_adj_list, visited, scc)
                sccs.append(scc)

        return sccs

    adj_list = defaultdict(list)
    rev_adj_list = defaultdict(list)
    for A, B, C in tracks:
        adj_list[A].append((B, C))
        rev_adj_list[B].append(A)

    sccs = kosaraju_scc(N, adj_list, rev_adj_list)

    node_to_scc = {}
    for i, scc in enumerate(sccs):
        for node in scc:
            node_to_scc[node] = i

    component_graph = defaultdict(list)
    component_cost = {}
    for A, B, C in tracks:
        compA = node_to_scc[A]
        compB = node_to_scc[B]
        if compA != compB:
            if (compA, compB) not in component_cost or component_cost[(compA, compB)] > C:
                component_cost[(compA, compB)] = C

    pq = []
    for (u, v), cost in component_cost.items():
        heapq.heappush(pq, (cost, u, v))

    parent = list(range(len(sccs)))
    rank = [0] * len(sccs)

    def find(u):
        if parent[u] != u:
            parent[u] = find(parent[u])
        return parent[u]

    def union(u, v):
        root_u = find(u)
        root_v = find(v)
        if root_u != root_v:
            if rank[root_u] > rank[root_v]:
                parent[root_v] = root_u
            elif rank[root_u] < rank[root_v]:
                parent[root_u] = root_v
            else:
                parent[root_v] = root_u
                rank[root_u] += 1

    min_cost = 0
    edges_used = 0

    while pq and edges_used < len(sccs) - 1:
        cost, u, v = heapq.heappop(pq)
        if find(u) != find(v):
            union(u, v)
            min_cost += cost
            edges_used += 1

    return min_cost//2

Phonepe ✅