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CODING SOLUTION - Placement Jobs & Materials pinned «🔥Problem Statement🔥 A robot is stuck in a maze represented by an NxN grid. The grid contains: 'S': Starting point 'E': Ending point '.': Empty cell (can move) '#': Wall (cannot move) 'P': Portal (teleports to the next portal clockwise) Rules: Robot…»
import heapq

def max_recipes_cooked(N, C, T):
    C.sort()  # Sort recipes by cooking time
    stove_heap = [0] * N  # Time occupied per stove (min-heap)

    for time in C:
        # Pop stove with least time
        earliest_free_time = heapq.heappop(stove_heap)
        if earliest_free_time + time <= T:
            # Assign recipe to this stove
            heapq.heappush(stove_heap, earliest_free_time + time)
        else:
            # Can't cook this recipe, push back the original time
            heapq.heappush(stove_heap, earliest_free_time)

    # Count stoves used for cooking (total recipes completed)
    return sum(t > 0 for t in stove_heap)

Example

N = 2
C = [2, 3, 4, 5, 9]
T = 10

print(max_recipes_cooked(N, C, T))  # Output will depend on input
Ini
Distance = a * (1 + 2 + 3 + ... + t) = a * t * (t + 1) / 2

Ini
t = int(S * 60)
Python
def distance_covered(N, A, X, S):
    # Convert minutes to seconds
    t = int(S * 60)
   
    # Acceleration of Xth car
    acceleration = A[X]
   
    # Total distance = a * t * (t + 1) // 2
    distance = acceleration * t * (t + 1) // 2
   
    return distance
Example
Python
N = 3
A = [1, 2, 3]
X = 1
S = 1.5

print(distance_covered(N, A, X, S))  # Output: 2 * 90 * 91 // 2 = 8190
input2: Array A (acceleration of each car)
input3: X (index of car to check distance)
input4: S (time in minutes, decimal allowed)

Speed increases like: a, 2a, 3a, ..., ta
Distance = a + 2a + 3a + ... + ta = a × (1 + 2 + 3 + ... + t) = a × (t × (t + 1)) / 2

def total_distance(N, A, X, S):
# Convert minutes to seconds
T = int(float(S) * 60)

# Get acceleration of X-th car (0-based index)
a = A[X]

# Use formula: distance = a × t(t+1)/2
distance = a * T * (T + 1) // 2
return distance

# Example usage
N = 3
A = [2, 4, 3]
X = 1
S = 0.5
print(total_distance(N, A, X, S)) # Output: Distance covered by car at index 1 in 30 sec
public class CarDistanceCalculator {

public static int totalDistance(int N, int[] A, int X, double S) {
// Minutes ko seconds me convert karo
int T = (int)(S * 60);

// X-th car ki acceleration le lo (0-based index)
int a = A[X];

// Distance = a × T × (T + 1) / 2
int distance = a * T * (T + 1) / 2;

return distance;
}

public static void main(String[] args) {
// Example inputs
int N = 3;
int[] A = {2, 4, 3};
int X = 1;
double S = 0.5;

int result = totalDistance(N, A, X, S);
System.out.println("Distance covered: " + result);
}
}

Input Explanation:
N = 3 cars
Accelerations: [2, 4, 3]
X = 1 means 2nd car (0-based indexing)
S = 0.5 minutes = 30 seconds
// Function to check if the array can be built using subarrays of prefix
public static boolean canBuild(int[] prefix, int[] arr) {
List<Integer> list = new ArrayList<>();
for (int num : prefix) list.add(num);

int i = prefix.length;
while (i < arr.length) {
boolean matched = false;
// Try all subarrays of prefix
for (int start = 0; start < prefix.length; start++) {
for (int end = start + 1; end <= prefix.length; end++) {
List<Integer> sub = list.subList(start, end);
if (i + sub.size() <= arr.length) {
boolean same = true;
for (int j = 0; j < sub.size(); j++) {
if (arr[i + j] != sub.get(j)) {
same = false;
break;
}
}
if (same) {
i += sub.size();
matched = true;
break;
}
}
}
if (matched) break;
}
if (!matched) return false;
}
return true;
}

public static int findMinOriginalLength(int[] arr) {
for (int len = 1; len <= arr.length; len++) {
int[] prefix = Arrays.copyOfRange(arr, 0, len);
if (canBuild(prefix, arr)) {
return len;
}
}
return arr.length;
}

public static void main(String[] args) {
int[] arr = {5, 4, 7, 2, 7, 4, 4, 7, 7, 2};
int result = findMinOriginalLength(arr);
System.out.println(result);
}
}

4
CODING SOLUTION - Placement Jobs & Materials pinned «// Function to check if the array can be built using subarrays of prefix public static boolean canBuild(int[] prefix, int[] arr) { List<Integer> list = new ArrayList<>(); for (int num : prefix) list.add(num); int i = prefix.length;…»
📌 Here is a Previous Year Coding Question asked in Wipro / Cognizant placement test:




### Question 1: Count Frequency of Words in a Sentence

Problem: 
Write a program that takes a sentence and prints the frequency of each word, sorted alphabetically.

Input: 
"the quick brown fox jumps over the lazy dog"

Expected Output:
brown: 1
dog: 1
fox: 1
jumps: 1
lazy: 1
over: 1
quick: 1
the: 2

Python Code:
def count_word_frequency(sentence):
    # Remove punctuation and convert to lowercase
    sentence = sentence.lower()
   
    # Split the sentence into words
    words = sentence.split()
   
    # Create a dictionary to store frequency
    frequency = {}
   
    for word in words:
        if word in frequency:
            frequency[word] += 1
        else:
            frequency[word] = 1
   
    # Sort dictionary by key (alphabetically)
    for word in sorted(frequency):
        print(f"{word}: {frequency[word]}")

# Example
input_sentence = "the quick brown fox jumps over the lazy dog the"
count_word_frequency(input_sentence)

---

### Question 2: Check if a Matrix is Symmetric

Problem: 
Write a program to check if a square matrix is symmetric (i.e., matrix[i][j] == matrix[j][i]).

Input:
[
[1, 2, 3],
[2, 4, 5],
[3, 5, 6]
]

Output:
The matrix is symmetric.
Python Code:
def is_symmetric(matrix):
    n = len(matrix)
    for i in range(n):
        for j in range(n):
            if matrix[i][j] != matrix[j][i]:
                return False
    return True

# Example matrix
matrix = [
    [1, 2, 3],
    [2, 4, 5],
    [3, 5, 6]
]

if is_symmetric(matrix):
    print("The matrix is symmetric.")
else:
    print("The matrix is not symmetric.")
CODING SOLUTION - Placement Jobs & Materials pinned «📌 Here is a Previous Year Coding Question asked in Wipro / Cognizant placement test: ### Question 1: Count Frequency of Words in a Sentence Problem:  Write a program that takes a sentence and prints the frequency of each word, sorted alphabetically.…»
from collections import deque

def heat_spread(grid):
    n = len(grid)
    m = len(grid[0])
    new_grid = [row[:] for row in grid]
    directions = [(-1,0), (1,0), (0,-1), (0,1)]

    for i in range(n):
        for j in range(m):
            if grid[i][j] == 'H':
                for dx, dy in directions:
                    ni, nj = i + dx, j + dy
                    if 0 <= ni < n and 0 <= nj < m and grid[ni][nj] == '.':
                        new_grid[ni][nj] = 'H'
    return new_grid

def simulate_heat(grid, start_x, start_y, end_x, end_y):
    n = len(grid)
    m = len(grid[0])
    queue = deque()
    visited = set()
    queue.append((start_x, start_y, 0, grid))
    visited.add((start_x, start_y))

    while queue:
        x, y, days, curr_grid = queue.popleft()
        if (x, y) == (end_x, end_y):
            return days

        next_grid = heat_spread(curr_grid)
        directions = [(-1,0), (1,0), (0,-1), (0,1)]

        for dx, dy in directions:
            nx, ny = x + dx, y + dy
            if 0 <= nx < n and 0 <= ny < m and next_grid[nx][ny] == '.' and (nx, ny) not in visited:
                visited.add((nx, ny))
                queue.append((nx, ny, days + 1, next_grid))
    return -1

# Input Format
n = int(input())
grid = []
for _ in range(n):
    grid.append(list(input().strip()))

start_x, start_y = map(int, input().split())
end_x, end_y = map(int, input().split())

print(simulate_heat(grid, start_x, start_y, end_x, end_y))




City Heatwave – Codevita
PYTHON
CODING SOLUTION - Placement Jobs & Materials pinned «from collections import deque def heat_spread(grid):     n = len(grid)     m = len(grid[0])     new_grid = [row[:] for row in grid]     directions = [(-1,0), (1,0), (0,-1), (0,1)]     for i in range(n):         for j in range(m):             if grid[i][j]…»
CGI_Coding_Questions_with_Answers (1).pdf
4.2 KB
CGI Interview Experience
Technical Round:

1. Write a program to check palindrome string.

2. Implement a binary search algorithm.

3. Write a code to find the factorial of a number.

4. Find the duplicate elements in an array.

5. Basic SQL queries like:

•Find second highest salary

•Count number of employees in each department
HCL C++ Interview Experience

1) Introduce Yourself
Brief intro with focus on your technical background, academic projects, and interest in C++.

2) What is the difference between C and C++?
C is procedural, C++ supports both procedural and object-oriented paradigms.

3) What are Classes and Objects in C++?
Class is a user-defined blueprint; Object is an instance of that class.

4) Explain OOPS Concepts with Real-life Examples
Encapsulation, Inheritance, Polymorphism, Abstraction explained with relatable examples like a car, employee hierarchy, etc.

5) What is Function Overloading and Operator Overloading?
Same function/operator behaves differently based on parameters.

6) What is the use of Pointers in C++?
Used for dynamic memory, arrays, and accessing objects directly.

7) Difference between Compile-time and Run-time Polymorphism?
Compile-time: Function Overloading; Run-time: Virtual Functions.

8) Code a Program for Palindrome Number in C++
Simple C++ code using loops and conditions.

9) Basic DSA Questions (Array, String, Sorting)
Reverse an array, Find missing number, Bubble Sort, etc.

10) HR Round: Strengths, Weaknesses, Why HCL, etc.
Prepare personal answers with examples; show enthusiasm for tech & learning.
WhatsApp: https://bit.ly/3tcjxV3
CODING SOLUTION - Placement Jobs & Materials pinned « HCL C++ Interview Experience 1) Introduce Yourself Brief intro with focus on your technical background, academic projects, and interest in C++. 2) What is the difference between C and C++? C is procedural, C++ supports both procedural and object-oriented…»