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string solve(string bs) {
    map<string, string> nb = {
        {"001", "C"},
        {"010", "G"},
        {"011", "A"},
        {"101", "T"},
        {"110", "U"},
        {"000", "DNA"},
        {"111", "RNA"}
    };

    string ds = "";
    string t = nb[bs.substr(0, 3)];
    for(int i = 3; i < bs.length(); i += 3) {
        string b = bs.substr(i, 3);
        if(nb.find(b) != nb.end()) {
            string x = nb[b];
            if(t == "DNA" && x == "U") {
                x = "T";
            }
            ds += x;
        } else {
            ds += "Error";
        }
    }

    return ds;
}

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