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For coding answers & Sql 🏃🏃🏃🏃
For coding answers & Sql 🏃🏃🏃🏃
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SELECT
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Jobs' AS source,
COUNT(*) AS total_number
FROM
jobs
GROUP BY
month_year
UNION ALL
SELECT
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM
freelancers
GROUP BY
month_year
ORDER BY
month_year ASC,
source ASC;
Freelancer code✅ @coding_000❤️
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Jobs' AS source,
COUNT(*) AS total_number
FROM
jobs
GROUP BY
month_year
UNION ALL
SELECT
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM
freelancers
GROUP BY
month_year
ORDER BY
month_year ASC,
source ASC;
Freelancer code✅ @coding_000❤️
👍6
Give reactions...check mark/type it carefully..✅
Share our channel..to get more ans..😅✅
Share our channel..to get more ans..😅✅
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Q - E-commerce website admin
SELECT c.title AS category_title, p.title, SUM(p.stock_number) AS total_stock
FROM categories c
JOIN products p ON c.id = p.category_id
GROUP BY c.title, p.title
HAVING SUM(p.stock_number) > 10
ORDER BY category_title ASC, p.title ASC, total_stock DESC;
SELECT c.title AS category_title, p.title, SUM(p.stock_number) AS total_stock
FROM categories c
JOIN products p ON c.id = p.category_id
GROUP BY c.title, p.title
HAVING SUM(p.stock_number) > 10
ORDER BY category_title ASC, p.title ASC, total_stock DESC;
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VIEW IN TELEGRAM
SELECT
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Jobs' AS source,
COUNT(*) AS total_number
FROM
jobs
GROUP BY
month_year
UNION ALL
SELECT
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM
freelancers
GROUP BY
month_year
ORDER BY
month_year ASC,
source ASC;
✅✅ share @coding_000✅
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Jobs' AS source,
COUNT(*) AS total_number
FROM
jobs
GROUP BY
month_year
UNION ALL
SELECT
DATE_FORMAT(date_field, '%Y-%m') AS month_year,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM
freelancers
GROUP BY
month_year
ORDER BY
month_year ASC,
source ASC;
✅✅ share @coding_000✅
👍3🔥1🥰1
I am checking pls wait...
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VIEW IN TELEGRAM
Freelancer code
SELECT
DATE_FORMAT(DATE, '%Y-%m') AS month_year,
source,
SUM(total_number) AS total_number
FROM (
SELECT
DATE(created_at) AS DATE,
'jobs' AS source,
COUNT(*) AS total_number
FROM JobPosts
WHERE YEAR(created_at) = 2022
GROUP BY DATE(created_at)
UNION ALL
SELECT
DATE(created_at) AS DATE,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM Freelancers
WHERE YEAR(created_at) = 2022
GROUP BY DATE(created_at)
) AS t
GROUP BY
DATE_FORMAT(DATE, '%Y-%m'),
source
ORDER BY
DATE_FORMAT(DATE, '%Y-%m'),
source;
Freelancer code 👆👆👆👆
Share @coding_000❤️
SELECT
DATE_FORMAT(DATE, '%Y-%m') AS month_year,
source,
SUM(total_number) AS total_number
FROM (
SELECT
DATE(created_at) AS DATE,
'jobs' AS source,
COUNT(*) AS total_number
FROM JobPosts
WHERE YEAR(created_at) = 2022
GROUP BY DATE(created_at)
UNION ALL
SELECT
DATE(created_at) AS DATE,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM Freelancers
WHERE YEAR(created_at) = 2022
GROUP BY DATE(created_at)
) AS t
GROUP BY
DATE_FORMAT(DATE, '%Y-%m'),
source
ORDER BY
DATE_FORMAT(DATE, '%Y-%m'),
source;
Freelancer code 👆👆👆👆
Share @coding_000❤️
❤2🔥1
🥰1
SELECT
DATE_FORMAT(dt, '%Y-%m') AS month_year,
'Jobs' AS source,
COUNT(*) AS total_number
FROM jobs
WHERE YEAR(dt) = 2022
GROUP BY month_year
UNION ALL
-- For freelancer registrations
SELECT
DATE_FORMAT(dt, '%Y-%m') AS month_year,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM freelancers
WHERE YEAR(dt) = 2022
GROUP BY month_year
ORDER BY month_year, source;
leading freelancer code ✅
DATE_FORMAT(dt, '%Y-%m') AS month_year,
'Jobs' AS source,
COUNT(*) AS total_number
FROM jobs
WHERE YEAR(dt) = 2022
GROUP BY month_year
UNION ALL
-- For freelancer registrations
SELECT
DATE_FORMAT(dt, '%Y-%m') AS month_year,
'Freelancers' AS source,
COUNT(*) AS total_number
FROM freelancers
WHERE YEAR(dt) = 2022
GROUP BY month_year
ORDER BY month_year, source;
leading freelancer code ✅
🔥2