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Directed Soldier


int directedSoldiers(int n, vector<int> &a) {
    // Write your code here.
    int d=0;
    vector<int> p, p1;
    vector<int> b = a;
    reverse(b.begin(), b.end());
    int k=0;
    for (int i = 0; i < n; i++) {
        if (b[i]==0) {
            k++;
        }
        p1.push_back(k);
    }
    for (int i = 0; i < n; i++) {
        if (a[i] == 1) {
            d += 1;
        }
        p.push_back(d);
    }
    reverse(p1.begin(), p1.end());
    p1.push_back(0);
    int res = count(a.begin(), a.end(), 0);
    for (int i = 0; i < n; i++) {
        int x = p[i] + p1[i + 1];
        res = min(res, x);
    }
    return res;
    
}

int terminalDefence(int n, int m, const vector<int>& a, const vector<int>& h, const vector<int>& b, int k) {
    vector<pair<int, int>> monsters;
    for (int i = 0; i < m; i++) {
        monsters.push_back({a[i], h[i]});
    }
    sort(monsters.begin(), monsters.end());

    for (int i = 0; i < n; i++) {
        int sentinelPos = b[i];
        auto it = lower_bound(monsters.begin(), monsters.end(), make_pair(sentinelPos, 0));

        if (it == monsters.end())
            return 0;

        int monsterPos = it->first;
        int monsterHealth = it->second;
        if (monsterPos == sentinelPos) {
            if (monsterHealth <= k)
                monsters.erase(it);
            else
                it->second -= k;
        } else {
            if (it == monsters.begin())
                return 0;

            it--;
            monsterPos = it->first;
            monsterHealth = it->second;
            if (monsterHealth <= k)
                monsters.erase(it);
            else
                it->second -= k;
        }
    }

    return monsters.empty() ? 1 : 0;
}

def calculate_xor(nums):
    xor_val = 0
    for num in nums:
        xor_val ^= num
    return xor_val


def maximum_beauty(A, D, N, M):
    blocks = {}
    parent = list(range(N))
    rank = [1] * N
    beauty = []

    for i in range(N):
        blocks[i] = [A[i]]

    def find_parent(x):
        if parent[x] != x:
            parent[x] = find_parent(parent[x])
        return parent[x]

    def merge_blocks(x, y):
        px = find_parent(x)
        py = find_parent(y)
        if px == py:
            return

        if rank[px] > rank[py]:
            parent[py] = px
            blocks[px].extend(blocks[py])
            rank[px] += rank[py]
        else:
            parent[px] = py
            blocks[py].extend(blocks[px])
            rank[py] += rank[px]

    for i in range(M):
        obj1 = i * 2
        obj2 = i * 2 + 1
        merge_blocks(obj1, obj2)

    for decay_obj in D:
        beauty.append(calculate_xor(blocks[find_parent(decay_obj)]))

        parent_block = find_parent(decay_obj)
        parent_block_objs = blocks[parent_block]
        parent_block_objs.remove(A[decay_obj])

        if not parent_block_objs:
            del blocks[parent_block]

    return beauty


N = int(input("Enter the number of objects (N): "))
M = int(input("Enter the number of object links (M): "))

print("Enter the values of the objects:")
A = [int(input()) for _ in range(N)]

K = int(input("Enter the order of object decay (K): "))

print("Enter the indices of the objects in the order of decay:")
D = [int(input()) for _ in range(K)]

result = maximum_beauty(A, D, N, M)

print("Maximum beauty of blocks before object decay:", *result)


building block