Day-9 (Solution)
Partition List
#86
Algorithm: LinkedList, Two Pointer
Solution: https://gist.github.com/lavakush-m-tiwari/02fceae370cbbb8701671ac7ded27fcd
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#techdose #28DaysOfArray #interviewpreparation #arrays #dsa #MaxFreqLast6Months #amazon2 #microsoft2 #apple2
Partition List
#86
Algorithm: LinkedList, Two Pointer
Solution: https://gist.github.com/lavakush-m-tiwari/02fceae370cbbb8701671ac7ded27fcd
Subscribe our Channel : https://www.youtube.com/c/TECHDOSE4u
Follow on Linkedin: https://www.linkedin.com/company/tech-dose
Please try the problem yourself and watch the video to learn the Algorithm 🙂
Please SHARE this initiative with your friends as well 😀
#techdose #28DaysOfArray #interviewpreparation #arrays #dsa #MaxFreqLast6Months #amazon2 #microsoft2 #apple2
LeetCode
Partition List - LeetCode
Can you solve this real interview question? Partition List - Given the head of a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.
You should preserve the original relative order of the…
You should preserve the original relative order of the…
Day-10
Linked List Cycle
#141
Algorithm: LinkedList, Two Pointer , HashTable
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Follow on Linkedin: https://www.linkedin.com/company/tech-dose
Please try the problem yourself and watch the video to learn the Algorithm 🙂
Please SHARE this initiative with your friends as well 😀
#techdose #28DaysOfArray #interviewpreparation #arrays #dsa #MaxFreqLast6Months #amazon11 #microsoft6 #google2 #apple2
Linked List Cycle
#141
Algorithm: LinkedList, Two Pointer , HashTable
Subscribe our Channel : https://www.youtube.com/c/TECHDOSE4u
Follow on Linkedin: https://www.linkedin.com/company/tech-dose
Please try the problem yourself and watch the video to learn the Algorithm 🙂
Please SHARE this initiative with your friends as well 😀
#techdose #28DaysOfArray #interviewpreparation #arrays #dsa #MaxFreqLast6Months #amazon11 #microsoft6 #google2 #apple2
LeetCode
Linked List Cycle - LeetCode
Can you solve this real interview question? Linked List Cycle - Given head, the head of a linked list, determine if the linked list has a cycle in it.
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously…
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously…