E solution
Find the smallest element index and if the array is sorted from there then print its index otherwise if not sorted print -1
Find the smallest element index and if the array is sorted from there then print its index otherwise if not sorted print -1
void code()
{
int n;
cin >> n;
vector<int> arr(n);
for (int &i : arr)
cin >> i;
int minIndex = 0;
for (int i = 0; i < n; i++)
if (arr[i] < arr[minIndex])
minIndex = i;
int res = minIndex;
for (int i = minIndex; i < n - 1; i++)
if (arr[i] > arr[i + 1])
res = -1;
cout << res << endl;
}
// E
// Enjoy ❤️
{
int n;
cin >> n;
vector<int> arr(n);
for (int &i : arr)
cin >> i;
int minIndex = 0;
for (int i = 0; i < n; i++)
if (arr[i] < arr[minIndex])
minIndex = i;
int res = minIndex;
for (int i = minIndex; i < n - 1; i++)
if (arr[i] > arr[i + 1])
res = -1;
cout << res << endl;
}
// E
// Enjoy ❤️
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