COGNIZANT EXAM HELP GROUP
3.55K subscribers
5.3K photos
21 videos
10 files
3.22K links
πŸš€ Placement Preparation Hub

πŸŽ“ From Preparation to Placement

⚑ OA Support β€’ Coding β€’ Aptitude β€’ Technical β€’ HR

🌟 Trusted by Hundreds of Students

πŸ† 372+ Placement Successes βœ…

πŸ“© DM: @Mrtrueliving_ix

πŸ’™ Turning Aspirations into Offer Letters.
Download Telegram
Wayfair β–ΆοΈπŸ“£

Test accomplished ❀️

All 3/3 codes are done
πŸ“±

-
@mrtrueliving_ix

-@mrtrueliving_ix

#Wayfair #ONCAMPUS
Please open Telegram to view this post
VIEW IN TELEGRAM
Please open Telegram to view this post
VIEW IN TELEGRAM
Accenture slot-7pm slot

90-90 MCQ βœ…πŸ§‘β€πŸ’»
2-2 coding -Pythonβœ…πŸ§‘β€πŸ’»

Using remote access ❀️

Mission accomplished πŸ‘¨β€πŸ’»πŸ’«πŸ†

#Team_Alpha♾️

-
@mrtrueliving_ix β˜ΊοΈβ–ΆοΈ

-
@mrtrueliving_ix β˜ΊοΈβ–ΆοΈ

#Accenture #PADA #offcampus #shortlisted
Please open Telegram to view this post
VIEW IN TELEGRAM
Channel name was changed to Β«MAQ || Accenture ON // OFF campus </> || infoedge || Cognizant || Amazon || Walmart || L & T || IBM EXAM HELPΒ»
Successfully cleared πŸ’―β˜ΊοΈ

Using 3 remote access tools for 3 different timings πŸ‘Œ
βš™οΈπŸ“±
Prev :
https://t.me/code_alphix/3757?single

https://t.me/code_alphix/3766

https://t.me/code_alphix/3791?single

#Hiring_Vision #Remote access πŸ“±
Please open Telegram to view this post
VIEW IN TELEGRAM
πŸ”ΈNet core

πŸ”ΈAmazon

πŸ”ΈMAQ

πŸ”ΈThroughtworks

πŸ”ΈIbm

πŸ”ΈAsian paints {igniTe}

πŸ”ΈAccenture ON campus

πŸ”ΈOracle

πŸ”Έ Infosys

πŸ”Έ Cognizant aptitude & Technical

🟨All placement help available🟨

🟫Remote access { πŸ’―} Success rate { πŸ’―}🟫

-
@mrtrueliving_ix πŸŸ₯

-
@mrtrueliving_ix πŸŸ₯

-
@mrtrueliving_ix πŸŸ₯

All OA help { ON campus or Off campus}
Please open Telegram to view this post
VIEW IN TELEGRAM
Accenture 11 am slot{ On campus}▢️

90-90 MCQ βœ…πŸ§‘β€πŸ’»
2-2 coding -Pythonβœ…πŸ§‘β€πŸ’»

Using remote access ❀️

Mission accomplished πŸ‘¨β€πŸ’»πŸ’«πŸ†

#Team_Alpha♾️

-
@mrtrueliving_ix ▢️

-
@mrtrueliving_ix ▢️

#Accenture #PADA #ONCampus #shortlisted
Please open Telegram to view this post
VIEW IN TELEGRAM
πŸ”ΈNet core

πŸ”ΈAmazon

πŸ”ΈMAQ

πŸ”ΈThroughtworks

πŸ”ΈIbm

πŸ”ΈAsian paints {igniTe}

πŸ”ΈAccenture ON campus

πŸ”ΈOracle

πŸ”Έ Infosys

πŸ”Έ Cognizant aptitude & Technical

🟨All placement help available🟨

🟫Remote access { πŸ’―} Success rate { πŸ’―}🟫

All OA help { ON campus or Off campus}


DM -@mrtrueliving_ixβ˜„οΈ

DM  -@mrtrueliving_ixβ˜„οΈ
Please open Telegram to view this post
VIEW IN TELEGRAM
MAQ Hiring for Developer role
Exp : 0 year

Apply Link : https://forms.office.com/r/eaWWtnuMx7

Join Telegram : https://t.me/code_alphix
❀1
#include <iostream>
#include <vector>
using namespace std;

const int MOD = 1e9 + 7;

class SegmentTree {
    int n;
    vector<long long> t;
    bool isSum;

public:
    SegmentTree(const vector<int>& v, bool sum) : n(v.size()), isSum(sum) {
        t.resize(2 * n, sum ? 0 : 1);
        for (int i = 0; i < n; ++i) {
            t[i + n] = v[i];
        }
        for (int i = n - 1; i > 0; --i) {
            t[i] = isSum ? (t[2 * i] + t[2 * i + 1]) % MOD : (t[2 * i] * t[2 * i + 1]) % MOD;
        }
    }

    long long query(int l, int r) {
        long long res = isSum ? 0 : 1;
        l += n;
        r += n;
        while (l < r) {
            if (l & 1) {
                res = isSum ? (res + t[l]) % MOD : (res * t[l]) % MOD;
                ++l;
            }
            if (r & 1) {
                --r;
                res = isSum ? (res + t[r]) % MOD : (res * t[r]) % MOD;
            }
            l /= 2;
            r /= 2;
        }
        return res;
    }
};

vector<long long> HardQueries(int n, const vector<int>& v, int q, const vector<vector<int>>& queries) {
    vector<long long> ans;
    SegmentTree sumTree(v, true);
    SegmentTree prodTree(v, false);

    for (const auto& x : queries) {
        int type = x[0], a = x[1] - 1, b = x[2];
        vector<int> indices;
        for (int i = a; i < n; i += b) {
            indices.push_back(i);
        }

        if (type == 0) {
            long long res = 0;
            for (int idx : indices) {
                res = (res + sumTree.query(idx, idx + 1)) % MOD;
            }
            ans.push_back(res);
        } else if (type == 1) {
            long long res = 1;
            for (int idx : indices) {
                res = (res * prodTree.query(idx, idx + 1)) % MOD;
            }
            ans.push_back(res);
        }
    }

    return ans;
}


Queries and fruits // OYOπŸ‘
Please open Telegram to view this post
VIEW IN TELEGRAM
def solve(n, m, arr):
    mod = 10**9 + 7
    fact = [1] * (n + 1)
    for i in range(2, n + 1):
        fact[i] = fact[i - 1] * i % mod

    arr.sort()
    if n == 1:
        return 1

    val = arr.pop()
    arr[-1] += val

    def mod_inverse(a, mod):
        return pow(a, mod - 2, mod)
   
    ans = fact[n]
    temp = 1
    for count in arr:
        temp = (temp * fact[count]) % mod
   
    temp = mod_inverse(temp, mod)
    return (ans * temp) % mod

minimum arrangements // Oyo
#include <iostream>
#include <vector>
#include <algorithm>

const int MOD = 1e9 + 7;

using namespace std;

long long solve(const vector<int>& a, int b) {
    int c = a.size();
    long long d = 0;
    for (int i = 0; i < c; i++) {
        d += a[i];
    }

    vector<long long> e(b + 1, 0);
    e[0] = 1;

    for (int i = 0; i < c; i++) {
        for (int j = b; j >= a[i]; j--) {
            e[j] = (e[j] + e[j - a[i]]) % MOD;
        }
    }
    long long f = 1;
    for (int i = 0; i < c; i++) {
        f = (f * 2) % MOD;
    }

    long long g = 0;
    for (int i = 0; i <= b; i++) {
        g = (g + e[i]) % MOD;
    }

    long long h = (f - 2 * g + MOD) % MOD;
    return h;
}

Sum of the elements // OYO
Company Name: Optum
Role: Software Engineer
Batch eligible: 2023 and 2024 grads

Apply: https://careers.unitedhealthgroup.com/job/21243748/software-engineer-hyderabad-in
IBM

Both Coding
πŸ“±

Test accomplished
πŸ“£

DM for any placement help

-
@mrtrueliving_ix

-
@mrtrueliving_ix

-
@mrtrueliving_ix

All placement help available
#IBM #coding  #Done
Please open Telegram to view this post
VIEW IN TELEGRAM
❀1
Swiggy BACKEND ASDE  βœ…

Test accomplished βœ…

Coding+ SQL + all MCQs ▢️

All placement help available

OA HELP: @mrtrueliving_ixπŸ’―

#Swiggy #BE #ASDE #ALL-DONE ☺️
Please open Telegram to view this post
VIEW IN TELEGRAM
Please open Telegram to view this post
VIEW IN TELEGRAM