Chemistry booster series
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Question 1 (Concept + Limiting Reagent):

A mixture contains 4 g Hโ‚‚ and 32 g Oโ‚‚.
They react according to:
2H2+O2= 2H2O
Find:
(i) Limiting reagent
(ii) Mass of water formed
(iii) Mass of excess reactant left

Question 2 (Gas + Stoichiometry + Trick)

At STP, 11.2 L of a gaseous hydrocarbon reacts completely with excess Oโ‚‚ to produce 44 g COโ‚‚.
Identify the hydrocarbon.

Question 3 (Equivalent + Redox + Stoichiometry )

A 10 g mixture of Naโ‚‚COโ‚ƒ and NaHCOโ‚ƒ is completely neutralised by 200 mL of 1 N HCl.
Find the mass percentage of Naโ‚‚COโ‚ƒ in the mixture.

#SIGNIFICANTFIGURES

Question :1 Evaluate the result with correct significant figures:
(2.36+0.040) +1.2

Question 2
The mass of a cube is measured as 2.50 g and each edge is measured as 1.20 cm.
Calculate the density of the cube with correct significant figures.

๏ปฟ
โคโ€๐Ÿ”ฅ6โค3๐Ÿ‘1
๐Ÿ†6๐Ÿฅฐ5๐Ÿ‘1๐Ÿ”ฅ1
โค3๐Ÿณ3๐Ÿ˜˜1
#STOICHIOMETRY Topic 2

๐ŸŒฑ Definition
Quantitative relationship between reactants and p products in a chemical reaction.

โญ Steps in Stoichiometric Calculations
โœ”๏ธ Write balanced chemical equation
โœ”๏ธ Convert given data into moles
โœ”๏ธ Use mole ratio from equation
โœ”๏ธ Calculate required moles
โœ”๏ธ Convert final answer into required unit
๐Ÿงช Mole Ratio
Ratio of coefficients of substances in a balanced equation.
๐Ÿ“Œ Example:
2Hโ‚‚ + Oโ‚‚ โ†’ 2Hโ‚‚O
Mole ratio: Hโ‚‚ : Oโ‚‚ : Hโ‚‚O = 2 : 1 : 2
๐Ÿ”น Types of Stoichiometric Problems

โญ 1๏ธโƒฃ Massโ€“Mass Relationship
โœ”๏ธ Given mass of one reactant โ†’ find mass of product
โœ”๏ธ Use moles as bridge
๐Ÿ“Œ Steps:
mass โ†’ moles โ†’ mole ratio โ†’ moles โ†’ mass

โญ 2๏ธโƒฃ Massโ€“Volume Relationship (Gas)
โœ”๏ธ Use 22.4 L at STP
๐Ÿ“Œ Formula:
Number of moles = Volume / 22.4

โญ 3๏ธโƒฃ Volumeโ€“Volume Relationship (Gases)
โœ”๏ธ Volumes are in same ratio as moles
โœ”๏ธ Valid only for gases at same T & P

โญ 4๏ธโƒฃ Limiting Reagent
โœ”๏ธ Reactant consumed first
โœ”๏ธ Decides amount of product formed
๐Ÿ“Œ Method:
Given moles / stoichiometric coefficient
โ†’ Smaller value = limiting reagent
Percent Yield
โœ”๏ธ Theoretical yield โ†’ from calculation
โœ”๏ธ Actual yield โ†’ given in question
๐Ÿ“Œ Formula:
Percent yield = (Actual yield / Theoretical yield) ร— 100

Percentage Composition
โœ”๏ธ Used to find composition of compound
๐Ÿ“Œ Formula:
Percentage of element = (Mass of element / Molar mass of compound) ร— 100

#NEETHOTPOINTS
โœ”๏ธ Stoichiometry always uses balanced equation
โœ”๏ธ All calculations done in moles first
โœ”๏ธ Limiting reagent decides product
โœ”๏ธ Volume ratio applies only to gases

@Ayano1me @Neetugpoll @Neetugquiz
โค7๐ŸŽ‰2๐Ÿ˜1๐Ÿณ1
Question :1 Identify the correct set of statements:
Reaction: 2Al+ fe2o3 =Al2O3+ 2Fe
A. 54 g Al reacts completely with 160 g Feโ‚‚Oโ‚ƒ
B. 27 g Al produces 56 g Fe
C. If Al is excess, Feโ‚‚Oโ‚ƒ is the limiting reagent
D. Mole ratio Al : Fe = 2 : 3
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A, B and C
2๏ธโƒฃ A and B only
3๏ธโƒฃ B and C only
4๏ธโƒฃ A, C and D


Question 2 (Limiting Reagent )
A mixture of 4 g Hโ‚‚ and 16 g Oโ‚‚ reacts to form water.
A. Hโ‚‚ is the limiting reagent
B. Oโ‚‚ is the limiting reagent
C. 18 g Hโ‚‚O is formed
D. Some Hโ‚‚ remains unreacted
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A and C
2๏ธโƒฃ B and D
3๏ธโƒฃ A and D
4๏ธโƒฃ B and C
โค5๐Ÿ”ฅ4๐Ÿ˜1๐Ÿ†1
Extra P block grp number 13 afternoon
โค7๐Ÿณ3๐Ÿ™1
P-BLOCK ELEMENTS
โญ Group 13 โ€“ Boron Family
Elements of Group 13
โœ”๏ธ Boron (B)
โœ”๏ธ Aluminium (Al)
โœ”๏ธ Gallium (Ga)
โœ”๏ธ Indium (In)
โœ”๏ธ Thallium (Tl)
โš›๏ธ Electronic Configuration
๐Ÿ“Œ General configuration: nsยฒ npยน
โœ”๏ธ B โ†’ 1sยฒ 2sยฒ 2pยน
โœ”๏ธ Al โ†’ [Ne] 3sยฒ 3pยน
โœ”๏ธ Ga โ†’ [Ar] 3dยนโฐ 4sยฒ 4pยน
โœ”๏ธ In โ†’ [Kr] 4dยนโฐ 5sยฒ 5pยน
โœ”๏ธ Tl โ†’ [Xe] 4fยนโด 5dยนโฐ 6sยฒ 6pยน
๐Ÿ”ข Oxidation States
โœ”๏ธ Common oxidation state โ†’ +3
โœ”๏ธ +1 oxidation state increases down the group
๐Ÿ“Œ Reason โ†’ Inert pair effect
โญ Stability of +1 state:
Tl > In > Ga > Al > B

#PhysicalProperties (Trends)
โœ”๏ธ Atomic size โ†‘ down the group Al, GA interchange
โœ”๏ธ Boron โ†’ Non-metal
โœ”๏ธ Al, Ga, In, Tl โ†’ Metals
๐Ÿ“Œ Melting point:
โœ”๏ธ Boron โ†’ very high
โœ”๏ธ Gallium โ†’ melts near room temperature โœ‹

#ChemicalProperties
Reaction with Oxygen
โœ”๏ธ Boron โ†’ Bโ‚‚Oโ‚ƒ
โœ”๏ธ Aluminium โ†’ Alโ‚‚Oโ‚ƒ (protective oxide layer)
๐Ÿ“Œ Nature of oxides:
โœ”๏ธ Bโ‚‚Oโ‚ƒ โ†’ Acidic
โœ”๏ธ Alโ‚‚Oโ‚ƒ โ†’ Amphoteric
โœ”๏ธ Gaโ‚‚Oโ‚ƒ, Inโ‚‚Oโ‚ƒ โ†’ Amphoteric
โœ”๏ธ Tlโ‚‚Oโ‚ƒ โ†’ Basic

ReactionwithAcids
โœ”๏ธ Boron โ†’ does NOT react directly
โœ”๏ธ Aluminium โ†’ reacts but shows passivation due to oxide layer

@Ayano1me @Neetugpoll @Neetugquiz
โค4๐Ÿค4๐Ÿ”ฅ2๐Ÿ‘1
#SpecialPointsaboutBoron
โœ”๏ธ Forms only covalent compounds
โœ”๏ธ Does NOT follow octet rule
โœ”๏ธ Shows diagonal relationship with silicon
โœ”๏ธ Does NOT form Bยณโบ ion easily
โœ”๏ธ Boric acid is weak monobasic acid
โœ”๏ธ Acts as Lewis acid
Aluminium โ€“ NCERT Highlights
โœ”๏ธ Most abundant metal in earthโ€™s crust
โœ”๏ธ Extracted by Hallโ€“Hรฉroult process
โœ”๏ธ Alโ‚‚Oโ‚ƒ โ†’ amphoteric
โœ”๏ธ Used in thermite reaction
๐Ÿ“Œ Thermite reaction:
Feโ‚‚Oโ‚ƒ + 2Al โ†’ Alโ‚‚Oโ‚ƒ + 2Fe + heat

#ImportantCompounds
โญ Borax (Naโ‚‚Bโ‚„Oโ‚‡ยท10Hโ‚‚O)
โœ”๏ธ Used in glass industry
โœ”๏ธ Borax bead test
โœ”๏ธ On heating โ†’ glassy bead

โญ Boric Acid (Hโ‚ƒBOโ‚ƒ)
โœ”๏ธ Weak acid
โœ”๏ธ Lewis acid
โœ”๏ธ Used as antiseptic

โญ Aluminium Chloride (AlClโ‚ƒ)
โœ”๏ธ Covalent compound
โœ”๏ธ Lewis acid
โœ”๏ธ Exists as Alโ‚‚Clโ‚† (dimer)

โญ #NEETHOTPOINTS
โœ”๏ธ Boron โ†’ non-metal, others metals
โœ”๏ธ Inert pair effect โ†’ +1 oxidation state
โœ”๏ธ AlClโ‚ƒ โ†’ Lewis acid
โœ”๏ธ Bโ‚‚Oโ‚ƒ acidic, Alโ‚‚Oโ‚ƒ amphoteric
โœ”๏ธ Gallium melts in hand โœ‹

@Ayano1me @Neetugpoll @Neetugquiz
โค9๐Ÿ˜Ž6๐Ÿ”ฅ1๐Ÿ†1๐Ÿค1
Question 1
Identify the correct set of statements related to Group 13 elements:
A. Boron shows anomalous behaviour in its group
B. Aluminium forms Alยณโบ ion easily in aqueous solution
C. Gallium has lower melting point than aluminium
D. Inert pair effect increases from B to Tl
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A, C and D
2๏ธโƒฃ A and B
3๏ธโƒฃ B and C
4๏ธโƒฃ A, B, C and D


Question:2
Identify the correctly matched pairs:
A. Boron trichloride โ€“ strong Lewis acid
B. Aluminium chloride โ€“ exists as AlClโ‚ƒ in vapour phase
C. Diborane โ€“ electron deficient compound
D. Boric acid โ€“ monobasic acid
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A and C
2๏ธโƒฃ A, C and D
3๏ธโƒฃ B and D
4๏ธโƒฃ A, B, C and D

Question:3
Identify the correct statements:
A. +3 oxidation state stability decreases from B to Tl
B. +1 oxidation state stability increases from B to Tl
C. Tlยณโบ is a strong oxidising agent
D. Boron forms stable Bยณโบ ion
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A, B and C
2๏ธโƒฃ A and D
3๏ธโƒฃ B and C
4๏ธโƒฃ A, C and D
โค9๐Ÿคฉ4
A. Diborane has two 3-centre-2-electron bonds
B. All Bโ€“H bonds in diborane are equivalent
C. Boranes are electron-deficient compounds
D. Terminal Bโ€“H bonds are longer than bridge Bโ€“H bonds
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A and C
2๏ธโƒฃ A, B and C
3๏ธโƒฃ B and D
4๏ธโƒฃ A, C and D


Identify the correct set regarding trihalides of Group 13:
A. Lewis acidity of BXโ‚ƒ decreases from BFโ‚ƒ to BIโ‚ƒ
B. BFโ‚ƒ is a weaker Lewis acid than BClโ‚ƒ
C. AlClโ‚ƒ acts as a Lewis acid
D. Boron trihalides undergo hydrolysis except BFโ‚ƒ
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A and C
2๏ธโƒฃ B, C and D
3๏ธโƒฃ A, B and D
4๏ธโƒฃ B and C only

Identify the correct statements:
A. Bโ‚‚Oโ‚ƒ is acidic in nature
B. Alโ‚‚Oโ‚ƒ is amphoteric
C. Tlโ‚‚Oโ‚ƒ is basic in nature
D. Basic character of oxides decreases down the group
๐Ÿ‘‰ Correct option(s):
1๏ธโƒฃ A and B
2๏ธโƒฃ A, B and C
3๏ธโƒฃ B and D
4๏ธโƒฃ A, C and D
๐Ÿ˜7โค5๐Ÿ’ฏ2๐Ÿ•Š1
thermodynamics.aac
1.6 MB
Topic cover thermodynamics system surrounding boundaries
Intensive extensive property & sign uses
โค9โคโ€๐Ÿ”ฅ5๐Ÿ˜1
Chemistry booster series
Question 1 Identify the correct set of statements related to Group 13 elements: A. Boron shows anomalous behaviour in its group B. Aluminium forms Alยณโบ ion easily in aqueous solution C. Gallium has lower melting point than aluminium D. Inert pair effect increasesโ€ฆ
โœ… Answer: Option 1 (A, C and D)
Boron anomalous โœ”
Alยณโบ strongly hydrated โ†’ aqueous me stable nahi โŒ
Ga ka m.p. Al se kam โœ”
Inert pair effect down the group increase โœ”

โœ… Answer: Option 2 (A, C and D)
BClโ‚ƒ = strong Lewis acid โœ”
AlClโ‚ƒ vapour phase me dimer (Alโ‚‚Clโ‚†) โŒ
Diborane = electron deficient โœ”
Boric acid monobasic โœ”


โœ… Answer: Option 1 (A, B and C)
+3 down the group unstable โœ”
+1 stable due to inert pair โœ”
Tlยณโบ easily reduce hota โ‡’ strong oxidiser โœ”
Boron Bยณโบ ion nahi banata โŒ
๏ปฟ
โค8๐Ÿฅฐ2๐Ÿณ1๐Ÿ†1
Chemistry booster series
A. Diborane has two 3-centre-2-electron bonds B. All Bโ€“H bonds in diborane are equivalent C. Boranes are electron-deficient compounds D. Terminal Bโ€“H bonds are longer than bridge Bโ€“H bonds ๐Ÿ‘‰ Correct option(s): 1๏ธโƒฃ A and C 2๏ธโƒฃ A, B and C 3๏ธโƒฃ B and D 4๏ธโƒฃ A,โ€ฆ
โœ… Answer: Option 1 (A and C)
Diborane me 2 banana bonds โœ”
Terminal & bridge bonds same nahi โŒ
Boranes electron-deficient โœ”
Bridge bonds longer hote hain โŒ

โœ… Answer: Option 2 (B, C and D)
Lewis acidity: BFโ‚ƒ < BClโ‚ƒ < BBrโ‚ƒ < BIโ‚ƒ โœ”
AlClโ‚ƒ = Lewis acid โœ”
BFโ‚ƒ hydrolysis nahi karta โŒ (others karte)
A statement ulta likha โŒ

โœ… Answer: Option 2 (A, B and C)
Bโ‚‚Oโ‚ƒ acidic โœ”
Alโ‚‚Oโ‚ƒ amphoteric โœ”
Tlโ‚‚Oโ‚ƒ basic โœ”
Basic character increase hota hai down the group โŒ
๐Ÿ˜Ž4๐Ÿ˜3๐Ÿ‘Œ1
#ELECTROMAGNETICRADIATION
Electromagnetic radiation is a form of energy propagated as waves with electric and magnetic fields oscillating perpendicular to each other.

#๏ธโƒฃ 1๏ธโƒฃ Characteristics of EM Radiation

โญ Wave Nature
โœ”๏ธ Travels in space as waves
โœ”๏ธ Characterized by wavelength (ฮป), frequency (ฮฝ), speed (c)
โœ”๏ธ Relationship: c = ฮปฮฝ

โญ Particle Nature
โœ”๏ธ Light also behaves as particles (photons)
โœ”๏ธ Energy of photon: E = hฮฝ
โœ”๏ธ Momentum of photon: p = h/ฮป
๐Ÿ“Œ Constants
โœ”๏ธ h = Planckโ€™s constant = 6.626 ร— 10โปยณโด Jยทs
โœ”๏ธ c = speed of light = 3 ร— 10โธ m/s

๐Ÿ“Œ Constants
โœ”๏ธ h = Planckโ€™s constant = 6.626 ร— 10โปยณโด Jยทs
โœ”๏ธ c = speed of light = 3 ร— 10โธ m/s

2#TypesofElectromagneticRadiation (NCERT)
๐Ÿ“Œ Order of increasing wavelength / decreasing frequency:
ฮณ-rays < X-rays < UV < Visible < IR < Microwaves < Radio waves
โœ”๏ธ UV, Visible, IR โ†’ Important in Atomic Spectra

3๏ธโƒฃ #ImportantRelations (Atom Chapter)
โœ”๏ธ Energy of photon: E = hฮฝ = hc/ฮป
โœ”๏ธ Frequency & wavelength inversely proportional: ฮฝ = c/ฮป

4๏ธโƒฃ #NEETIMPORTANTPOINTS โญ
โœ”๏ธ EM radiation has dual nature โ†’ wave + particle
โœ”๏ธ Wave nature โ†’ explains interference, diffraction, refraction
โœ”๏ธ Particle nature โ†’ explains photoelectric effect, Compton effect
โœ”๏ธ Photon energy proportional to frequency (E โˆ ฮฝ)

@Ayano1me @Neetugpoll @Neetugquiz
โค5๐Ÿ‘3๐Ÿ†1
#PBLOCK ELEMENTSGROUP 14 (CARBON FAMILY)
Elements: C, Si, Ge, Sn, Pb
โœ”๏ธ General electronic configuration: nsยฒ npยฒ
โœ”๏ธ Valency: 4
โœ”๏ธ Oxidation states: +4, +2
๐Ÿ“Œ Stability of +2 state increases down the group (inert pair effect)


1๏ธโƒฃ #PHYSICALPROPERTIES
โญ Atomic & Ionic Radii
โœ”๏ธ Increases down the group (C < Si < Ge < Sn < Pb)
โญ Ionisation Enthalpy
โœ”๏ธ Decreases down the group
๐Ÿ“Œ Carbon has very high IE โ†’ strong covalent bonding
โญ Electronegativity
โœ”๏ธ Decreases down the group
๐Ÿ“Œ C highest, Pb lowest
โญ Catenation (NEET HOT ๐Ÿ”ฅ)
โœ”๏ธ Ability to form long chains
๐Ÿ“Œ Order: C >> Si > Ge > Sn > Pb
๐Ÿ“Œ Strong Cโ€“C bond + small size


2๏ธโƒฃ #ALLOTROPY
โญ Carbon Allotropes
โœ”๏ธ Crystalline โ†’ Diamond, Graphite, Fullerene
โœ”๏ธ Amorphous โ†’ Coal, Coke, Charcoal
๐Ÿ“Œ Diamond
โœ”๏ธ spยณ hybridised
โœ”๏ธ Hardest substance
โœ”๏ธ Electrical insulator
๐Ÿ“Œ Graphite
โœ”๏ธ spยฒ hybridised
โœ”๏ธ Good conductor of electricity
โœ”๏ธ Layered structure


3๏ธโƒฃ #CHEMICALPROPERTIES
โญ Oxidation States
โœ”๏ธ C, Si โ†’ mainly +4
โœ”๏ธ Ge, Sn, Pb โ†’ +2 & +4
๐Ÿ“Œ +2 becomes more stable down the group (inert pair effect)
โญ Inert Pair Effect
โœ”๏ธ nsยฒ electrons do not participate in bonding
๐Ÿ“Œ Maximum in Pb โ†’ Pbยฒโบ more stable than Pbโดโบ


4๏ธโƒฃ #HYDRIDES (EHโ‚„)
โœ”๏ธ CHโ‚„, SiHโ‚„, GeHโ‚„, SnHโ‚„
๐Ÿ“Œ Trend:
โœ”๏ธ Thermal stability โ†“ down the group
โœ”๏ธ Reducing character โ†‘ down the group

5๏ธโƒฃ #HALIDES (MXโ‚„ / MXโ‚‚)
โญ Tetrahalides (MXโ‚„)
โœ”๏ธ CClโ‚„, SiClโ‚„ โ†’ covalent
โœ”๏ธ Stability โ†“ down the group
โญ Dihalides (MXโ‚‚)
โœ”๏ธ SnClโ‚‚, PbClโ‚‚ โ†’ more stable down the group
๐Ÿ“Œ Due to inert pair effect
๐Ÿ“Œ PbClโ‚„ unstable, PbClโ‚‚ stable


6๏ธโƒฃ #OXIDES (IMPORTANT ๐Ÿ”ฅ)
โœ”๏ธ COโ‚‚, SiOโ‚‚ โ†’ Acidic
โœ”๏ธ GeOโ‚‚ โ†’ Weakly acidic
โœ”๏ธ SnOโ‚‚ โ†’ Amphoteric
โœ”๏ธ PbO โ†’ Amphoteric / basic

๐Ÿ“Œ Acidity decreases down the group

7๏ธโƒฃ #CARBONSPECIALCASE
โญ Shows maximum catenation
โญ Forms multiple bonds (C=C, Cโ‰กC)
โญ Large number of organic compounds
โญ No d-orbitals โ†’ strong ฯ€ bonding

8๏ธโƒฃ #COMPARISON ( NEET MCQ)
Property :Carbon :Lead
Catenation :Maximum :Negligible
Oxidation state :+4 :+2 more stable
Nature of oxide :Acidic :Amphoteric
Inert pair effect :Absent :Maximum

โš ๏ธ #NCERTLINES
โŒ Pbโดโบ more stable than Pbยฒโบ โ†’ WRONG
โœ”๏ธ CClโ‚„ does NOT hydrolyse
โœ”๏ธ SiClโ‚„ hydrolyses easily
โœ”๏ธ Graphite conducts electricity, diamond does not

@Ayano1me @Neetugpoll @Neetugquiz
โค4๐Ÿ˜2๐Ÿ™1๐Ÿณ1
Chemistry booster series pinned ยซ๐—ง๐—ข๐—ฃ ๐Ÿฎ๐Ÿฌ ๐—›๐—œ๐—š๐—› ๐—ช๐—˜๐—œ๐—š๐—›๐—ง๐—”๐—š๐—˜ ๐—ง๐—ข๐—ฃ๐—œ๐—–๐—ฆ โ€” ๐—–๐—›๐—˜๐— ๐—œ๐—ฆ๐—ง๐—ฅ๐—ฌ โญ #๐—ฃ๐—›๐—ฌ๐—ฆ๐—œ๐—–๐—”๐—Ÿ๐—–๐—›๐—˜๐— ๐—œ๐—ฆ๐—ง๐—ฅ๐—ฌ ๐—–๐—›๐—”๐—ฃ๐—ง๐—˜๐—ฅ ๐Ÿญ: ๐—ฆ๐—ข๐—Ÿ๐—จ๐—ง๐—œ๐—ข๐—ก โญ ๐—œ๐——๐—˜๐—”๐—Ÿ ๐—ฆ๐—ข๐—Ÿ๐—จ๐—ง๐—œ๐—ข๐—ก โญ ๐—–๐—ข๐—Ÿ๐—Ÿ๐—œ๐—š๐—”๐—ง๐—œ๐—ฉ๐—˜ ๐—ฃ๐—ฅ๐—ข๐—ฃ๐—˜๐—ฅ๐—ง๐—œ๐—˜๐—ฆ ๐—–๐—›๐—”๐—ฃ๐—ง๐—˜๐—ฅ ๐Ÿฎ๐—˜๐—Ÿ๐—˜๐—–๐—ง๐—ฅ๐—ข๐—–๐—›๐—˜๐— ๐—œ๐—ฆ๐—ง๐—ฅ๐—ฌ โญ ๐—ก๐—˜๐—ฅ๐—ก๐—ฆ๐—ง ๐—˜๐—ค๐—จ๐—”๐—ง๐—œ๐—ข๐—ก โญ ๐—–๐—ข๐—ก๐——๐—จ๐—–๐—ง๐—œ๐—ฉ๐—œ๐—ง๐—ฌ ๐—–๐—›๐—”๐—ฃ๐—ง๐—˜๐—ฅ ๐Ÿฏ: ๐—–๐—›๐—˜๐— ๐—œ๐—–๐—”๐—Ÿ ๐—ž๐—œ๐—ก๐—˜๐—ง๐—œ๐—–๐—ฆ โญ ๐—™๐—œ๐—ฅ๐—ฆ๐—ง ๐—ข๐—ฅ๐——๐—˜๐—ฅ ๐—ฅ๐—˜๐—”๐—–๐—ง๐—œ๐—ข๐—ก๐—ฆ โญ ๐—”๐—ฅ๐—ฅ๐—›๐—˜๐—ก๐—œ๐—จ๐—ฆโ€ฆยป
Chemistry booster series
๐—ง๐—ข๐—ฃ ๐Ÿฎ๐Ÿฌ ๐—›๐—œ๐—š๐—› ๐—ช๐—˜๐—œ๐—š๐—›๐—ง๐—”๐—š๐—˜ ๐—ง๐—ข๐—ฃ๐—œ๐—–๐—ฆ โ€” ๐—–๐—›๐—˜๐— ๐—œ๐—ฆ๐—ง๐—ฅ๐—ฌ โญ #๐—ฃ๐—›๐—ฌ๐—ฆ๐—œ๐—–๐—”๐—Ÿ๐—–๐—›๐—˜๐— ๐—œ๐—ฆ๐—ง๐—ฅ๐—ฌ ๐—–๐—›๐—”๐—ฃ๐—ง๐—˜๐—ฅ ๐Ÿญ: ๐—ฆ๐—ข๐—Ÿ๐—จ๐—ง๐—œ๐—ข๐—ก โญ ๐—œ๐——๐—˜๐—”๐—Ÿ ๐—ฆ๐—ข๐—Ÿ๐—จ๐—ง๐—œ๐—ข๐—ก โญ ๐—–๐—ข๐—Ÿ๐—Ÿ๐—œ๐—š๐—”๐—ง๐—œ๐—ฉ๐—˜ ๐—ฃ๐—ฅ๐—ข๐—ฃ๐—˜๐—ฅ๐—ง๐—œ๐—˜๐—ฆ ๐—–๐—›๐—”๐—ฃ๐—ง๐—˜๐—ฅ ๐Ÿฎ๐—˜๐—Ÿ๐—˜๐—–๐—ง๐—ฅ๐—ข๐—–๐—›๐—˜๐— ๐—œ๐—ฆ๐—ง๐—ฅ๐—ฌ โญ ๐—ก๐—˜๐—ฅ๐—ก๐—ฆ๐—ง ๐—˜๐—ค๐—จ๐—”๐—ง๐—œ๐—ข๐—ก โญ ๐—–๐—ข๐—ก๐——๐—จ๐—–๐—ง๐—œ๐—ฉ๐—œ๐—ง๐—ฌ ๐—–๐—›๐—”๐—ฃ๐—ง๐—˜๐—ฅ ๐Ÿฏ: ๐—–๐—›๐—˜๐— ๐—œ๐—–๐—”๐—Ÿ ๐—ž๐—œ๐—ก๐—˜๐—ง๐—œ๐—–๐—ฆ โญ ๐—™๐—œ๐—ฅ๐—ฆ๐—ง ๐—ข๐—ฅ๐——๐—˜๐—ฅ ๐—ฅ๐—˜๐—”๐—–๐—ง๐—œ๐—ข๐—ก๐—ฆ โญ ๐—”๐—ฅ๐—ฅ๐—›๐—˜๐—ก๐—œ๐—จ๐—ฆโ€ฆ
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๐Ÿฅฐ4๐Ÿ‘4โคโ€๐Ÿ”ฅ1๐Ÿ’ฏ1
โค5๐ŸŽ‰2๐Ÿ†1
#BOHRMODELOFHYDROGENATOM
Proposed by Niels Bohr (1913) to explain the line spectrum of hydrogen.

1. #POSTULATES OF BOHR MODEL
โœ”๏ธ Atom has a small, positively charged nucleus at the centre
โœ”๏ธ Electron revolves around nucleus in fixed circular orbits (stationary states)
โœ”๏ธ Each orbit has a definite energy
โœ”๏ธ Electron does not radiate energy while revolving in a permitted orbit
๐Ÿ“Œ Allowed orbits โ†’ n = 1, 2, 3, 4โ€ฆ
โœ”๏ธ Angular momentum of electron is quantised:
๐Ÿ“Œ mvr = n(h / 2ฯ€)


2. #ENERGYOFELECTRON IN HYDROGEN ATOM
โœ”๏ธ Energy of electron in nth orbit:
๐Ÿ“Œ Eโ‚™ = โˆ’13.6 / nยฒ eV
โœ”๏ธ Negative sign โ†’ electron is bound to nucleus
๐Ÿ“Œ Ground state (n = 1):
Eโ‚ = โˆ’13.6 eV
๐Ÿ“Œ Excited state (n > 1):
Energy becomes less negative

3. #RADIUSOFBOHRORBIT
โœ”๏ธ Radius of nth orbit:
๐Ÿ“Œ rโ‚™ = 0.529 ร— nยฒ ร…
๐Ÿ“Œ For ground state (n = 1):
rโ‚ = 0.529 ร…
โœ”๏ธ Radius increases as nยฒ

4. #SPECTRALLINES (EMISSION & ABSORPTION)
โœ”๏ธ Electron jumps from higher to lower orbit โ†’ emission of energy
โœ”๏ธ Electron jumps from lower to higher orbit โ†’ absorption of energy
๐Ÿ“Œ Energy difference:
๐Ÿ“Œ ฮ”E = Eโ‚‚ โˆ’ Eโ‚ = hฮฝ


5 #HYDROGENEMISSION SPECTRUM (IMPORTANT )
โœ”๏ธ Spectrum consists of discrete lines
๐Ÿ“Œ Series based on final orbit:
Slines :Final n :Region
Lyman: 1 :UV
Balmer :2 :Visible
Paschen :3 :IR
Brackett :4 :IR
Pfund :5 :IR

๐Ÿ“Œ Balmer series โ†’ only visible series


6. #RYDBERGEQUATION
โœ”๏ธ Explains wavelength of spectral lines:
๐Ÿ“Œ 1/ฮป = R (1/nโ‚ยฒ โˆ’ 1/nโ‚‚ยฒ)
โœ”๏ธ nโ‚‚ > nโ‚
๐Ÿ“Œ R = 1.097 ร— 10โท mโปยน

7. #SUCCESSOFBOHRMODEL
โœ”๏ธ Explains hydrogen line spectrum
โœ”๏ธ Explains stability of hydrogen atom
โœ”๏ธ Gives correct values of energy & radius for H atom


8. #LIMITATIONSOFBOHRMODEL (VERY IMP โš ๏ธ)
โŒ Cannot explain spectra of multi-electron atoms
โŒ Cannot explain Zeeman effect
โŒ Cannot explain Stark effect
โŒ Violates Heisenberg uncertainty principle

9. #NCERT ONELINEFACTS (NEET DIRECT)
โœ”๏ธ Valid only for one-electron systems (H, Heโบ, Liยฒโบ)
โœ”๏ธ Energy levels are quantised
โœ”๏ธ Lower n โ†’ more stability
โœ”๏ธ Higher n โ†’ larger orbit, higher energy

#IMP
Electron radiates energy in stationary orbit โ†’ WRONG
โœ”๏ธ Ground state has minimum energy
โœ”๏ธ Transition n=3 โ†’ n=2 โ†’ Balmer series

@Ayano1me @Neetugpoll @Neetugquiz
โค5โคโ€๐Ÿ”ฅ3๐ŸŽ‰1๐Ÿ’ฏ1๐Ÿ˜Ž1