2๏ธโฃ Basic Nature of Amines
๐ #ReasonofBasicity
Due to lone pair on N
Electron donating groups โ basicity
Electron withdrawing groups โ basicity
๐ Basic Strength Order (NCERT)
โญGas phase:
3ยฐ>2ยฐ>1ยฐ>NH3
โญAqueous solution:
2ยฐ>1ยฐ>3ยฐ>NH3
๐ Due to solvation + steric hindrance
โญAromatic ๐ Aliphatic
โญAliphatic amines > NHโ > Aromatic amines
โญAniline less basic due to resonance (lone pair delocalisation)
โ ๏ธ #ImportantNCERTPoints
โญAniline reacts with HNOโ at low temp
โญBasicity increases with +I effect
โญOrtho substituted aniline โ less basic (steric + H-bonding)
#NEETTrapLines
โญCarbylamine test โ only 1ยฐ amine
โญGabriel synthesis โ only 1ยฐ aliphatic amine
โญAromatic amines form diazonium salts
@Ayano1me @Neetugpoll @Neetugquiz
๐ #ReasonofBasicity
Due to lone pair on N
Electron donating groups โ basicity
Electron withdrawing groups โ basicity
๐ Basic Strength Order (NCERT)
โญGas phase:
3ยฐ>2ยฐ>1ยฐ>NH3
โญAqueous solution:
2ยฐ>1ยฐ>3ยฐ>NH3
๐ Due to solvation + steric hindrance
โญAromatic ๐ Aliphatic
โญAliphatic amines > NHโ > Aromatic amines
โญAniline less basic due to resonance (lone pair delocalisation)
โ ๏ธ #ImportantNCERTPoints
โญAniline reacts with HNOโ at low temp
โญBasicity increases with +I effect
โญOrtho substituted aniline โ less basic (steric + H-bonding)
#NEETTrapLines
โญCarbylamine test โ only 1ยฐ amine
โญGabriel synthesis โ only 1ยฐ aliphatic amine
โญAromatic amines form diazonium salts
@Ayano1me @Neetugpoll @Neetugquiz
๐ฅ2๐2๐1
#BIOMOLECULES
โญ1๏ธโฃ CARBOHYDRATES
Definition
Polyhydroxy aldehydes or ketones or substances which give them on hydrolysis
๐ General formula: Cโ(HโO)โ
โญ Classification of Carbohydrates
โญ 1๏ธโฃ Monosaccharides
โ๏ธ Cannot be hydrolysed further
โ๏ธ Sweet, crystalline
๐ Examples:
Glucose (Aldohexose)
Fructose (Ketohexose)
Ribose
โญ 2๏ธโฃ Oligosaccharides
โ๏ธ 2โ10 monosaccharide units
๐ Examples:
Sucrose (Glucose + Fructose) โ reducing
Maltose (Glucose + Glucose) โ๏ธ reducing
Lactose (Glucose + Galactose) โ๏ธ reducing
โญ3๏ธโฃ Polysaccharides
โ๏ธ High molecular weight
โ๏ธ Non-sweet
๐ Examples:
Starch โ plant storage
Glycogen โ animal storage
Cellulose โ structural (
Reducing ๐ Non-Reducing Sugars
โ๏ธ Free aldehyde / ketone group โ Reducing
๐ Reducing: Glucose, Fructose, Maltose, Lactose
๐ Non-reducing: Sucrose
#ImportantNCERTConcepts
โญ D & L Configuration
Based on position of โOH on penultimate carbon
Glucose โ D-glucose
โญ Anomers
Differ at anomeric carbon (C-1 in glucose)
ฮฑ-glucose & ฮฒ-glucose
โญ Epimers
Differ at one carbon (except anomeric)
Glucose & Galactose (C-4)
โญ Glycosidic Bond
Link between two monosaccharides
In sucrose โ ฮฑ-1,ฮฒ-2
#RemeberGuys
Tollenโs / Fehlingโs โ reducing sugars
Iodine test โ starch (blue-black)
@Ayano1me @Neetugpoll @Neetugquiz
โญ1๏ธโฃ CARBOHYDRATES
Definition
Polyhydroxy aldehydes or ketones or substances which give them on hydrolysis
๐ General formula: Cโ(HโO)โ
โญ Classification of Carbohydrates
โญ 1๏ธโฃ Monosaccharides
โ๏ธ Cannot be hydrolysed further
โ๏ธ Sweet, crystalline
๐ Examples:
Glucose (Aldohexose)
Fructose (Ketohexose)
Ribose
โญ 2๏ธโฃ Oligosaccharides
โ๏ธ 2โ10 monosaccharide units
๐ Examples:
Sucrose (Glucose + Fructose) โ reducing
Maltose (Glucose + Glucose) โ๏ธ reducing
Lactose (Glucose + Galactose) โ๏ธ reducing
โญ3๏ธโฃ Polysaccharides
โ๏ธ High molecular weight
โ๏ธ Non-sweet
๐ Examples:
Starch โ plant storage
Glycogen โ animal storage
Cellulose โ structural (
Reducing ๐ Non-Reducing Sugars
โ๏ธ Free aldehyde / ketone group โ Reducing
๐ Reducing: Glucose, Fructose, Maltose, Lactose
๐ Non-reducing: Sucrose
#ImportantNCERTConcepts
โญ D & L Configuration
Based on position of โOH on penultimate carbon
Glucose โ D-glucose
โญ Anomers
Differ at anomeric carbon (C-1 in glucose)
ฮฑ-glucose & ฮฒ-glucose
โญ Epimers
Differ at one carbon (except anomeric)
Glucose & Galactose (C-4)
โญ Glycosidic Bond
Link between two monosaccharides
In sucrose โ ฮฑ-1,ฮฒ-2
#RemeberGuys
Tollenโs / Fehlingโs โ reducing sugars
Iodine test โ starch (blue-black)
@Ayano1me @Neetugpoll @Neetugquiz
๐ฅ2๐ฅฐ2๐1
#PROTEINS
โญ Definition
Polymers of ฮฑ-amino acids joined by peptide bonds
๐ Peptide bond: โCOโNHโ
โญ Amino Acids
๐ General formula:
NHโโCH(R)โCOOH
โ๏ธ Zwitterion in aqueous solution
โ๏ธ 20 standard amino acids
#Classificationof AminoAcids
โญ Based on Nutrition
Essential โ Diet required
Non-essential โ Synthesised in body
โญBased on Charge
Acidic: Aspartic, Glutamic
Basic: Lysine, Arginine
Neutral: Glycine, Alanine
#ProteinStructureLevels
โญ 1๏ธโฃ Primary
โ๏ธ Sequence of amino acids
โ๏ธ Most specific
โญ 2๏ธโฃ Secondary
โ๏ธ ฮฑ-helix
โ๏ธ ฮฒ-pleated sheet
๐ Stabilised by H-bonds
โญ 3๏ธโฃ Tertiary
โ๏ธ 3D folding
โ๏ธ Stabilised by:
Disulfide bonds
Ionic bonds
H-bonds
โญ 4๏ธโฃ Quaternary
โ๏ธ More than one polypeptide chain
๐ Example: Haemoglobin
#TypesofProteins
โญFibrous โ Structural (Keratin, Collagen)
โญGlobular โ Functional (Enzymes)
โญDenaturation
โ๏ธ Loss of biological activity
โ Primary structure unchanged
๐ Causes:
Heat
pH change
๐ Example:
Boiled egg white
#NEETHOTPOINTS
โ๏ธ Disulfide bond โ Cysteine
โ๏ธ Enzymes โ globular proteins
โ๏ธ Sucrose โ non-reducing
โ๏ธ Cellulose โ ฮฒ-glucose polymer
@Ayano1me @Neetugpoll @Neetugquiz
โญ Definition
Polymers of ฮฑ-amino acids joined by peptide bonds
๐ Peptide bond: โCOโNHโ
โญ Amino Acids
๐ General formula:
NHโโCH(R)โCOOH
โ๏ธ Zwitterion in aqueous solution
โ๏ธ 20 standard amino acids
#Classificationof AminoAcids
โญ Based on Nutrition
Essential โ Diet required
Non-essential โ Synthesised in body
โญBased on Charge
Acidic: Aspartic, Glutamic
Basic: Lysine, Arginine
Neutral: Glycine, Alanine
#ProteinStructureLevels
โญ 1๏ธโฃ Primary
โ๏ธ Sequence of amino acids
โ๏ธ Most specific
โญ 2๏ธโฃ Secondary
โ๏ธ ฮฑ-helix
โ๏ธ ฮฒ-pleated sheet
๐ Stabilised by H-bonds
โญ 3๏ธโฃ Tertiary
โ๏ธ 3D folding
โ๏ธ Stabilised by:
Disulfide bonds
Ionic bonds
H-bonds
โญ 4๏ธโฃ Quaternary
โ๏ธ More than one polypeptide chain
๐ Example: Haemoglobin
#TypesofProteins
โญFibrous โ Structural (Keratin, Collagen)
โญGlobular โ Functional (Enzymes)
โญDenaturation
โ๏ธ Loss of biological activity
โ Primary structure unchanged
๐ Causes:
Heat
pH change
๐ Example:
Boiled egg white
#NEETHOTPOINTS
โ๏ธ Disulfide bond โ Cysteine
โ๏ธ Enzymes โ globular proteins
โ๏ธ Sucrose โ non-reducing
โ๏ธ Cellulose โ ฮฒ-glucose polymer
@Ayano1me @Neetugpoll @Neetugquiz
๐3๐ฏ1
๐ง๐ข๐ฃ ๐ฎ๐ฌ ๐๐๐๐ ๐ช๐๐๐๐๐ง๐๐๐ ๐ง๐ข๐ฃ๐๐๐ฆ โ ๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
โญ #๐ฃ๐๐ฌ๐ฆ๐๐๐๐๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ญ: ๐ฆ๐ข๐๐จ๐ง๐๐ข๐ก
โญ ๐๐๐๐๐ ๐ฆ๐ข๐๐จ๐ง๐๐ข๐ก
โญ ๐๐ข๐๐๐๐๐๐ง๐๐ฉ๐ ๐ฃ๐ฅ๐ข๐ฃ๐๐ฅ๐ง๐๐๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฎ๐๐๐๐๐ง๐ฅ๐ข๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
โญ ๐ก๐๐ฅ๐ก๐ฆ๐ง ๐๐ค๐จ๐๐ง๐๐ข๐ก
โญ ๐๐ข๐ก๐๐จ๐๐ง๐๐ฉ๐๐ง๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฏ: ๐๐๐๐ ๐๐๐๐ ๐๐๐ก๐๐ง๐๐๐ฆ
โญ ๐๐๐ฅ๐ฆ๐ง ๐ข๐ฅ๐๐๐ฅ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ
โญ ๐๐ฅ๐ฅ๐๐๐ก๐๐จ๐ฆ ๐๐ค๐จ๐๐ง๐๐ข๐ก
โญ #๐๐ก๐ข๐ฅ๐๐๐ก๐๐ ๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฐ: ๐ & ๐ ๐๐๐ข๐๐ ๐๐๐๐ ๐๐ก๐ง๐ฆ
โญ ๐ฃ๐๐ฌ๐ฆ๐๐๐๐ ๐ฃ๐ฅ๐ข๐ฃ๐๐ฅ๐ง๐๐๐ฆ & ๐ฅ๐๐๐ฆ๐ข๐ก๐๐ก๐
โญ ๐๐๐ก๐ง๐๐๐ก๐ข๐๐ ๐๐ข๐ก๐ง๐ฅ๐๐๐ง๐๐ข๐ก
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฑ: ๐๐ข๐ข๐ฅ๐๐๐ก๐๐ง๐๐ข๐ก ๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
โญ ๐ฉ๐๐๐๐ก๐๐ ๐๐ข๐ก๐ ๐ง๐๐๐ข๐ฅ๐ฌ (๐ฉ๐๐ง)
โญ ๐๐ฆ๐ข๐ ๐๐ฅ๐๐ฆ๐
โญ #๐ข๐ฅ๐๐๐ก๐๐ ๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฒ: ๐๐๐๐ข๐๐๐๐๐ก๐๐ฆ & ๐๐๐๐ข๐๐ฅ๐๐ก๐๐ฆ
โญ ๐ฆ๐ก๐ญ & ๐ฆ๐ก๐ฎ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ
โญ ๐ฃ๐ฅ๐๐ฃ๐๐ฅ๐๐ง๐๐ข๐ก ๐ข๐ ๐๐๐๐ข๐๐๐๐๐ก๐๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ณ: ๐๐๐๐ข๐๐ข๐๐ฆ, ๐ฃ๐๐๐ก๐ข๐๐ฆ & ๐๐ง๐๐๐ฅ๐ฆ
โญ ๐ฃ๐ฅ๐๐ฃ๐๐ฅ๐๐ง๐๐ข๐ก ๐ข๐ ๐๐๐๐ข๐๐ข๐๐ฆ
โญ ๐ช๐๐๐๐๐๐ ๐ฆ๐ข๐ก ๐๐ง๐๐๐ฅ ๐ฆ๐ฌ๐ก๐ง๐๐๐ฆ๐๐ฆ
๐๐ ๐ฅ๐๐๐๐ง๐๐ข๐ก
๐๐๐๐ฃ๐ง๐๐ฅ ๐ด: ๐๐๐๐๐๐ฌ๐๐๐ฆ, ๐๐๐ง๐ข๐ก๐๐ฆ & ๐๐๐ฅ๐๐ข๐ซ๐ฌ๐๐๐ ๐๐๐๐๐ฆ
โญ ๐ก๐๐ ๐ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ / ๐ง๐๐ฆ๐ง๐ฆ
โญ ๐ก๐จ๐๐๐๐ข๐ฃ๐๐๐๐๐ ๐๐๐๐๐ง๐๐ข๐ก ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ต: ๐๐ ๐๐ก๐๐ฆ
โญ ๐ก๐๐ ๐ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ / ๐ง๐๐ฆ๐ง๐ฆ
โญ ๐๐๐ฆ๐๐ ๐ก๐๐ง๐จ๐ฅ๐ ๐ข๐ ๐๐ ๐๐ก๐๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ญ๐ฌ: ๐๐๐ข๐ ๐ข๐๐๐๐จ๐๐๐ฆ
โญ ๐๐๐ฅ๐๐ข๐๐ฌ๐๐ฅ๐๐ง๐๐ฆ
โญ ๐ฃ๐ฅ๐ข๐ง๐๐๐ก๐ฆ
@Ayano1me @Neetugpoll @Neetugquiz
โญ #๐ฃ๐๐ฌ๐ฆ๐๐๐๐๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ญ: ๐ฆ๐ข๐๐จ๐ง๐๐ข๐ก
โญ ๐๐๐๐๐ ๐ฆ๐ข๐๐จ๐ง๐๐ข๐ก
โญ ๐๐ข๐๐๐๐๐๐ง๐๐ฉ๐ ๐ฃ๐ฅ๐ข๐ฃ๐๐ฅ๐ง๐๐๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฎ๐๐๐๐๐ง๐ฅ๐ข๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
โญ ๐ก๐๐ฅ๐ก๐ฆ๐ง ๐๐ค๐จ๐๐ง๐๐ข๐ก
โญ ๐๐ข๐ก๐๐จ๐๐ง๐๐ฉ๐๐ง๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฏ: ๐๐๐๐ ๐๐๐๐ ๐๐๐ก๐๐ง๐๐๐ฆ
โญ ๐๐๐ฅ๐ฆ๐ง ๐ข๐ฅ๐๐๐ฅ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ
โญ ๐๐ฅ๐ฅ๐๐๐ก๐๐จ๐ฆ ๐๐ค๐จ๐๐ง๐๐ข๐ก
โญ #๐๐ก๐ข๐ฅ๐๐๐ก๐๐ ๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฐ: ๐ & ๐ ๐๐๐ข๐๐ ๐๐๐๐ ๐๐ก๐ง๐ฆ
โญ ๐ฃ๐๐ฌ๐ฆ๐๐๐๐ ๐ฃ๐ฅ๐ข๐ฃ๐๐ฅ๐ง๐๐๐ฆ & ๐ฅ๐๐๐ฆ๐ข๐ก๐๐ก๐
โญ ๐๐๐ก๐ง๐๐๐ก๐ข๐๐ ๐๐ข๐ก๐ง๐ฅ๐๐๐ง๐๐ข๐ก
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฑ: ๐๐ข๐ข๐ฅ๐๐๐ก๐๐ง๐๐ข๐ก ๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
โญ ๐ฉ๐๐๐๐ก๐๐ ๐๐ข๐ก๐ ๐ง๐๐๐ข๐ฅ๐ฌ (๐ฉ๐๐ง)
โญ ๐๐ฆ๐ข๐ ๐๐ฅ๐๐ฆ๐
โญ #๐ข๐ฅ๐๐๐ก๐๐ ๐๐๐๐ ๐๐ฆ๐ง๐ฅ๐ฌ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ฒ: ๐๐๐๐ข๐๐๐๐๐ก๐๐ฆ & ๐๐๐๐ข๐๐ฅ๐๐ก๐๐ฆ
โญ ๐ฆ๐ก๐ญ & ๐ฆ๐ก๐ฎ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ
โญ ๐ฃ๐ฅ๐๐ฃ๐๐ฅ๐๐ง๐๐ข๐ก ๐ข๐ ๐๐๐๐ข๐๐๐๐๐ก๐๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ณ: ๐๐๐๐ข๐๐ข๐๐ฆ, ๐ฃ๐๐๐ก๐ข๐๐ฆ & ๐๐ง๐๐๐ฅ๐ฆ
โญ ๐ฃ๐ฅ๐๐ฃ๐๐ฅ๐๐ง๐๐ข๐ก ๐ข๐ ๐๐๐๐ข๐๐ข๐๐ฆ
โญ ๐ช๐๐๐๐๐๐ ๐ฆ๐ข๐ก ๐๐ง๐๐๐ฅ ๐ฆ๐ฌ๐ก๐ง๐๐๐ฆ๐๐ฆ
๐๐ ๐ฅ๐๐๐๐ง๐๐ข๐ก
๐๐๐๐ฃ๐ง๐๐ฅ ๐ด: ๐๐๐๐๐๐ฌ๐๐๐ฆ, ๐๐๐ง๐ข๐ก๐๐ฆ & ๐๐๐ฅ๐๐ข๐ซ๐ฌ๐๐๐ ๐๐๐๐๐ฆ
โญ ๐ก๐๐ ๐ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ / ๐ง๐๐ฆ๐ง๐ฆ
โญ ๐ก๐จ๐๐๐๐ข๐ฃ๐๐๐๐๐ ๐๐๐๐๐ง๐๐ข๐ก ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ต: ๐๐ ๐๐ก๐๐ฆ
โญ ๐ก๐๐ ๐ ๐ฅ๐๐๐๐ง๐๐ข๐ก๐ฆ / ๐ง๐๐ฆ๐ง๐ฆ
โญ ๐๐๐ฆ๐๐ ๐ก๐๐ง๐จ๐ฅ๐ ๐ข๐ ๐๐ ๐๐ก๐๐ฆ
๐๐๐๐ฃ๐ง๐๐ฅ ๐ญ๐ฌ: ๐๐๐ข๐ ๐ข๐๐๐๐จ๐๐๐ฆ
โญ ๐๐๐ฅ๐๐ข๐๐ฌ๐๐ฅ๐๐ง๐๐ฆ
โญ ๐ฃ๐ฅ๐ข๐ง๐๐๐ก๐ฆ
@Ayano1me @Neetugpoll @Neetugquiz
โค5โคโ๐ฅ2๐ฏ2๐ฅฐ1๐1
#Day 1
#MOLECONCEPTALLIMPORTANTFORMULAE (NEET)
#BasicRelations
โญNumber of moles (n) = mass (m) / molar mass (M)
โญMass (m) = number of moles (n) ร molar mass (M)
โญNumber of particles (N) = n ร NA
โญNumber of moles (n) = N / NA
โญAvogadro number (NA) = 6.022 ร 10^23
#Gases
โญNumber of moles at STP (n) = volume (V in litres) / 22.4
โญIdeal gas equation
P ร V = n ร R ร T
โญDensity of gas (d) = (P ร M) / (R ร T)
โญMolar mass of gas (M) = (d ร R ร T) / P
#Solutions
โญMolarity (M) = number of moles of solute / volume of solution (in litre)
โญMolality (m) = number of moles of solute / mass of solvent (in kg)
โญNormality (N) = number of equivalents / volume of solution (in litre)
โญStrength of solution (g/L) = molarity ร molar mass
โญDilution Formula
M1 ร V1 = M2 ร V2
โญEquivalent Concept
Equivalent mass = molar mass / n-factor
โญNumber of equivalents = mass / equivalent mass
โญMole Fraction
Mole fraction of A (XA) = moles of A / (moles of A + moles of B)
XA + XB = 1
โญLimitingReagent
Required moles = given moles / stoichiometric coefficient
The reactant with least required moles is the limiting reagent
Percentage Composition
โญPercentage of element = (mass of element / molar mass of compound) ร 100
โญEmpirical and Molecular Formula
Empirical formula mass = sum of atomic masses in empirical formula
n = molecular mass / empirical formula mass
โญMolecular formula = empirical formula ร n
โญGas Mixture (Daltonโs Law)
Total pressure = P1 + P2 + P3 + โฆ
โญPartial pressure of gas A
PA = XA ร Ptotal
Redox Reactions
โญNormality ร Volume = constant
N1 ร V1 = N2 ร V2
n-factor = number of electrons lost or gained
#ImportantConstants
STP = 273 K and 1 atm
Gas constant
R = 0.0821 L atm molโปยน Kโปยน
R = 8.314 J molโปยน Kโปยน
#MOLECONCEPTALLIMPORTANTFORMULAE (NEET)
#BasicRelations
โญNumber of moles (n) = mass (m) / molar mass (M)
โญMass (m) = number of moles (n) ร molar mass (M)
โญNumber of particles (N) = n ร NA
โญNumber of moles (n) = N / NA
โญAvogadro number (NA) = 6.022 ร 10^23
#Gases
โญNumber of moles at STP (n) = volume (V in litres) / 22.4
โญIdeal gas equation
P ร V = n ร R ร T
โญDensity of gas (d) = (P ร M) / (R ร T)
โญMolar mass of gas (M) = (d ร R ร T) / P
#Solutions
โญMolarity (M) = number of moles of solute / volume of solution (in litre)
โญMolality (m) = number of moles of solute / mass of solvent (in kg)
โญNormality (N) = number of equivalents / volume of solution (in litre)
โญStrength of solution (g/L) = molarity ร molar mass
โญDilution Formula
M1 ร V1 = M2 ร V2
โญEquivalent Concept
Equivalent mass = molar mass / n-factor
โญNumber of equivalents = mass / equivalent mass
โญMole Fraction
Mole fraction of A (XA) = moles of A / (moles of A + moles of B)
XA + XB = 1
โญLimitingReagent
Required moles = given moles / stoichiometric coefficient
The reactant with least required moles is the limiting reagent
Percentage Composition
โญPercentage of element = (mass of element / molar mass of compound) ร 100
โญEmpirical and Molecular Formula
Empirical formula mass = sum of atomic masses in empirical formula
n = molecular mass / empirical formula mass
โญMolecular formula = empirical formula ร n
โญGas Mixture (Daltonโs Law)
Total pressure = P1 + P2 + P3 + โฆ
โญPartial pressure of gas A
PA = XA ร Ptotal
Redox Reactions
โญNormality ร Volume = constant
N1 ร V1 = N2 ร V2
n-factor = number of electrons lost or gained
#ImportantConstants
STP = 273 K and 1 atm
Gas constant
R = 0.0821 L atm molโปยน Kโปยน
R = 8.314 J molโปยน Kโปยน
โคโ๐ฅ6
#SIGNIFICANTFIGURES
๐ฑ Definition
Digits which convey certainty + one uncertain digit
โญ Rules to Count Significant Figures
โ๏ธ All non-zero digits โ significant
โ๏ธ Zeros between non-zero โ significant
โ๏ธ Leading zeros โ โ not significant
โ๏ธ Trailing zeros โ significant only with decimal
๐ Examples:
0.0045 โ 2 SF
2.300 โ 4 SF
1500 โ 2 SF (without decimal)
โโ Addition / Subtraction
Result โ least decimal places
๐ Example:
12.11 + 0.2 = 12.3
โ๏ธโ Multiplication / Division
Result โ least significant figures
๐ Example:
2.5 ร 1.23 = 3.1 (2 SF)
๐ข Rounding Off Rules
Next digit < 5 โ same
Next digit โฅ 5 โ +1
๐ 2.34 โ 2.3
๐ 2.36 โ 2.4
#NEETHOTPOINTS
โ๏ธ Exact numbers โ infinite SF
โ๏ธ Unit conversion โ SF maintained
โ๏ธ Final answer rounding last step
@Ayano1me @Neetugpoll @Neetugquiz
๐ฑ Definition
Digits which convey certainty + one uncertain digit
โญ Rules to Count Significant Figures
โ๏ธ All non-zero digits โ significant
โ๏ธ Zeros between non-zero โ significant
โ๏ธ Leading zeros โ โ not significant
โ๏ธ Trailing zeros โ significant only with decimal
๐ Examples:
0.0045 โ 2 SF
2.300 โ 4 SF
1500 โ 2 SF (without decimal)
โโ Addition / Subtraction
Result โ least decimal places
๐ Example:
12.11 + 0.2 = 12.3
โ๏ธโ Multiplication / Division
Result โ least significant figures
๐ Example:
2.5 ร 1.23 = 3.1 (2 SF)
๐ข Rounding Off Rules
Next digit < 5 โ same
Next digit โฅ 5 โ +1
๐ 2.34 โ 2.3
๐ 2.36 โ 2.4
#NEETHOTPOINTS
โ๏ธ Exact numbers โ infinite SF
โ๏ธ Unit conversion โ SF maintained
โ๏ธ Final answer rounding last step
@Ayano1me @Neetugpoll @Neetugquiz
โค6๐2
Ans eve m upload hoga sb try krna
Question 1 (Concept + Limiting Reagent):
A mixture contains 4 g Hโ and 32 g Oโ.
They react according to:
2H2+O2= 2H2O
Find:
(i) Limiting reagent
(ii) Mass of water formed
(iii) Mass of excess reactant left
Question 2 (Gas + Stoichiometry + Trick)
At STP, 11.2 L of a gaseous hydrocarbon reacts completely with excess Oโ to produce 44 g COโ.
Identify the hydrocarbon.
Question 3 (Equivalent + Redox + Stoichiometry )
A 10 g mixture of NaโCOโ and NaHCOโ is completely neutralised by 200 mL of 1 N HCl.
Find the mass percentage of NaโCOโ in the mixture.
#SIGNIFICANTFIGURES
Question :1 Evaluate the result with correct significant figures:
(2.36+0.040) +1.2
Question 2
The mass of a cube is measured as 2.50 g and each edge is measured as 1.20 cm.
Calculate the density of the cube with correct significant figures.
๏ปฟ
โคโ๐ฅ6โค3๐1
๐6๐ฅฐ5๐1๐ฅ1
#STOICHIOMETRY Topic 2
๐ฑ Definition
Quantitative relationship between reactants and p products in a chemical reaction.
โญ Steps in Stoichiometric Calculations
โ๏ธ Write balanced chemical equation
โ๏ธ Convert given data into moles
โ๏ธ Use mole ratio from equation
โ๏ธ Calculate required moles
โ๏ธ Convert final answer into required unit
๐งช Mole Ratio
Ratio of coefficients of substances in a balanced equation.
๐ Example:
2Hโ + Oโ โ 2HโO
Mole ratio: Hโ : Oโ : HโO = 2 : 1 : 2
๐น Types of Stoichiometric Problems
โญ 1๏ธโฃ MassโMass Relationship
โ๏ธ Given mass of one reactant โ find mass of product
โ๏ธ Use moles as bridge
๐ Steps:
mass โ moles โ mole ratio โ moles โ mass
โญ 2๏ธโฃ MassโVolume Relationship (Gas)
โ๏ธ Use 22.4 L at STP
๐ Formula:
Number of moles = Volume / 22.4
โญ 3๏ธโฃ VolumeโVolume Relationship (Gases)
โ๏ธ Volumes are in same ratio as moles
โ๏ธ Valid only for gases at same T & P
โญ 4๏ธโฃ Limiting Reagent
โ๏ธ Reactant consumed first
โ๏ธ Decides amount of product formed
๐ Method:
Given moles / stoichiometric coefficient
โ Smaller value = limiting reagent
Percent Yield
โ๏ธ Theoretical yield โ from calculation
โ๏ธ Actual yield โ given in question
๐ Formula:
Percent yield = (Actual yield / Theoretical yield) ร 100
Percentage Composition
โ๏ธ Used to find composition of compound
๐ Formula:
Percentage of element = (Mass of element / Molar mass of compound) ร 100
#NEETHOTPOINTS
โ๏ธ Stoichiometry always uses balanced equation
โ๏ธ All calculations done in moles first
โ๏ธ Limiting reagent decides product
โ๏ธ Volume ratio applies only to gases
@Ayano1me @Neetugpoll @Neetugquiz
๐ฑ Definition
Quantitative relationship between reactants and p products in a chemical reaction.
โญ Steps in Stoichiometric Calculations
โ๏ธ Write balanced chemical equation
โ๏ธ Convert given data into moles
โ๏ธ Use mole ratio from equation
โ๏ธ Calculate required moles
โ๏ธ Convert final answer into required unit
๐งช Mole Ratio
Ratio of coefficients of substances in a balanced equation.
๐ Example:
2Hโ + Oโ โ 2HโO
Mole ratio: Hโ : Oโ : HโO = 2 : 1 : 2
๐น Types of Stoichiometric Problems
โญ 1๏ธโฃ MassโMass Relationship
โ๏ธ Given mass of one reactant โ find mass of product
โ๏ธ Use moles as bridge
๐ Steps:
mass โ moles โ mole ratio โ moles โ mass
โญ 2๏ธโฃ MassโVolume Relationship (Gas)
โ๏ธ Use 22.4 L at STP
๐ Formula:
Number of moles = Volume / 22.4
โญ 3๏ธโฃ VolumeโVolume Relationship (Gases)
โ๏ธ Volumes are in same ratio as moles
โ๏ธ Valid only for gases at same T & P
โญ 4๏ธโฃ Limiting Reagent
โ๏ธ Reactant consumed first
โ๏ธ Decides amount of product formed
๐ Method:
Given moles / stoichiometric coefficient
โ Smaller value = limiting reagent
Percent Yield
โ๏ธ Theoretical yield โ from calculation
โ๏ธ Actual yield โ given in question
๐ Formula:
Percent yield = (Actual yield / Theoretical yield) ร 100
Percentage Composition
โ๏ธ Used to find composition of compound
๐ Formula:
Percentage of element = (Mass of element / Molar mass of compound) ร 100
#NEETHOTPOINTS
โ๏ธ Stoichiometry always uses balanced equation
โ๏ธ All calculations done in moles first
โ๏ธ Limiting reagent decides product
โ๏ธ Volume ratio applies only to gases
@Ayano1me @Neetugpoll @Neetugquiz
โค7๐2๐1๐ณ1
Question :1 Identify the correct set of statements:
Reaction: 2Al+ fe2o3 =Al2O3+ 2Fe
A. 54 g Al reacts completely with 160 g FeโOโ
B. 27 g Al produces 56 g Fe
C. If Al is excess, FeโOโ is the limiting reagent
D. Mole ratio Al : Fe = 2 : 3
๐ Correct option(s):
1๏ธโฃ A, B and C
2๏ธโฃ A and B only
3๏ธโฃ B and C only
4๏ธโฃ A, C and D
Question 2 (Limiting Reagent )
A mixture of 4 g Hโ and 16 g Oโ reacts to form water.
A. Hโ is the limiting reagent
B. Oโ is the limiting reagent
C. 18 g HโO is formed
D. Some Hโ remains unreacted
๐ Correct option(s):
1๏ธโฃ A and C
2๏ธโฃ B and D
3๏ธโฃ A and D
4๏ธโฃ B and C
โค5๐ฅ4๐1๐1
Extra P block grp number 13 afternoon
โค7๐ณ3๐1
P-BLOCK ELEMENTS
โญ Group 13 โ Boron Family
Elements of Group 13
โ๏ธ Boron (B)
โ๏ธ Aluminium (Al)
โ๏ธ Gallium (Ga)
โ๏ธ Indium (In)
โ๏ธ Thallium (Tl)
โ๏ธ Electronic Configuration
๐ General configuration: nsยฒ npยน
โ๏ธ B โ 1sยฒ 2sยฒ 2pยน
โ๏ธ Al โ [Ne] 3sยฒ 3pยน
โ๏ธ Ga โ [Ar] 3dยนโฐ 4sยฒ 4pยน
โ๏ธ In โ [Kr] 4dยนโฐ 5sยฒ 5pยน
โ๏ธ Tl โ [Xe] 4fยนโด 5dยนโฐ 6sยฒ 6pยน
๐ข Oxidation States
โ๏ธ Common oxidation state โ +3
โ๏ธ +1 oxidation state increases down the group
๐ Reason โ Inert pair effect
โญ Stability of +1 state:
Tl > In > Ga > Al > B
#PhysicalProperties (Trends)
โ๏ธ Atomic size โ down the group Al, GA interchange
โ๏ธ Boron โ Non-metal
โ๏ธ Al, Ga, In, Tl โ Metals
๐ Melting point:
โ๏ธ Boron โ very high
โ๏ธ Gallium โ melts near room temperature โ
#ChemicalProperties
Reaction with Oxygen
โ๏ธ Boron โ BโOโ
โ๏ธ Aluminium โ AlโOโ (protective oxide layer)
๐ Nature of oxides:
โ๏ธ BโOโ โ Acidic
โ๏ธ AlโOโ โ Amphoteric
โ๏ธ GaโOโ, InโOโ โ Amphoteric
โ๏ธ TlโOโ โ Basic
ReactionwithAcids
โ๏ธ Boron โ does NOT react directly
โ๏ธ Aluminium โ reacts but shows passivation due to oxide layer
@Ayano1me @Neetugpoll @Neetugquiz
โญ Group 13 โ Boron Family
Elements of Group 13
โ๏ธ Boron (B)
โ๏ธ Aluminium (Al)
โ๏ธ Gallium (Ga)
โ๏ธ Indium (In)
โ๏ธ Thallium (Tl)
โ๏ธ Electronic Configuration
๐ General configuration: nsยฒ npยน
โ๏ธ B โ 1sยฒ 2sยฒ 2pยน
โ๏ธ Al โ [Ne] 3sยฒ 3pยน
โ๏ธ Ga โ [Ar] 3dยนโฐ 4sยฒ 4pยน
โ๏ธ In โ [Kr] 4dยนโฐ 5sยฒ 5pยน
โ๏ธ Tl โ [Xe] 4fยนโด 5dยนโฐ 6sยฒ 6pยน
๐ข Oxidation States
โ๏ธ Common oxidation state โ +3
โ๏ธ +1 oxidation state increases down the group
๐ Reason โ Inert pair effect
โญ Stability of +1 state:
Tl > In > Ga > Al > B
#PhysicalProperties (Trends)
โ๏ธ Atomic size โ down the group Al, GA interchange
โ๏ธ Boron โ Non-metal
โ๏ธ Al, Ga, In, Tl โ Metals
๐ Melting point:
โ๏ธ Boron โ very high
โ๏ธ Gallium โ melts near room temperature โ
#ChemicalProperties
Reaction with Oxygen
โ๏ธ Boron โ BโOโ
โ๏ธ Aluminium โ AlโOโ (protective oxide layer)
๐ Nature of oxides:
โ๏ธ BโOโ โ Acidic
โ๏ธ AlโOโ โ Amphoteric
โ๏ธ GaโOโ, InโOโ โ Amphoteric
โ๏ธ TlโOโ โ Basic
ReactionwithAcids
โ๏ธ Boron โ does NOT react directly
โ๏ธ Aluminium โ reacts but shows passivation due to oxide layer
@Ayano1me @Neetugpoll @Neetugquiz
โค4๐ค4๐ฅ2๐1
#SpecialPointsaboutBoron
โ๏ธ Forms only covalent compounds
โ๏ธ Does NOT follow octet rule
โ๏ธ Shows diagonal relationship with silicon
โ๏ธ Does NOT form Bยณโบ ion easily
โ๏ธ Boric acid is weak monobasic acid
โ๏ธ Acts as Lewis acid
Aluminium โ NCERT Highlights
โ๏ธ Most abundant metal in earthโs crust
โ๏ธ Extracted by HallโHรฉroult process
โ๏ธ AlโOโ โ amphoteric
โ๏ธ Used in thermite reaction
๐ Thermite reaction:
FeโOโ + 2Al โ AlโOโ + 2Fe + heat
#ImportantCompounds
โญ Borax (NaโBโOโยท10HโO)
โ๏ธ Used in glass industry
โ๏ธ Borax bead test
โ๏ธ On heating โ glassy bead
โญ Boric Acid (HโBOโ)
โ๏ธ Weak acid
โ๏ธ Lewis acid
โ๏ธ Used as antiseptic
โญ Aluminium Chloride (AlClโ)
โ๏ธ Covalent compound
โ๏ธ Lewis acid
โ๏ธ Exists as AlโClโ (dimer)
โญ #NEETHOTPOINTS
โ๏ธ Boron โ non-metal, others metals
โ๏ธ Inert pair effect โ +1 oxidation state
โ๏ธ AlClโ โ Lewis acid
โ๏ธ BโOโ acidic, AlโOโ amphoteric
โ๏ธ Gallium melts in hand โ
@Ayano1me @Neetugpoll @Neetugquiz
โ๏ธ Forms only covalent compounds
โ๏ธ Does NOT follow octet rule
โ๏ธ Shows diagonal relationship with silicon
โ๏ธ Does NOT form Bยณโบ ion easily
โ๏ธ Boric acid is weak monobasic acid
โ๏ธ Acts as Lewis acid
Aluminium โ NCERT Highlights
โ๏ธ Most abundant metal in earthโs crust
โ๏ธ Extracted by HallโHรฉroult process
โ๏ธ AlโOโ โ amphoteric
โ๏ธ Used in thermite reaction
๐ Thermite reaction:
FeโOโ + 2Al โ AlโOโ + 2Fe + heat
#ImportantCompounds
โญ Borax (NaโBโOโยท10HโO)
โ๏ธ Used in glass industry
โ๏ธ Borax bead test
โ๏ธ On heating โ glassy bead
โญ Boric Acid (HโBOโ)
โ๏ธ Weak acid
โ๏ธ Lewis acid
โ๏ธ Used as antiseptic
โญ Aluminium Chloride (AlClโ)
โ๏ธ Covalent compound
โ๏ธ Lewis acid
โ๏ธ Exists as AlโClโ (dimer)
โญ #NEETHOTPOINTS
โ๏ธ Boron โ non-metal, others metals
โ๏ธ Inert pair effect โ +1 oxidation state
โ๏ธ AlClโ โ Lewis acid
โ๏ธ BโOโ acidic, AlโOโ amphoteric
โ๏ธ Gallium melts in hand โ
@Ayano1me @Neetugpoll @Neetugquiz
โค9๐6๐ฅ1๐1๐ค1
Chemistry booster series
P-BLOCK ELEMENTS โญ Group 13 โ Boron Family Elements of Group 13 โ๏ธ Boron (B) โ๏ธ Aluminium (Al) โ๏ธ Gallium (Ga) โ๏ธ Indium (In) โ๏ธ Thallium (Tl) โ๏ธ Electronic Configuration ๐ General configuration: nsยฒ npยน โ๏ธ B โ 1sยฒ 2sยฒ 2pยน โ๏ธ Al โ [Ne] 3sยฒ 3pยน โ๏ธ Ga โ [Ar]โฆ
Accha lga to like krdo guy's so motivation bna rhega upload ka & i will upload 10+ question on p block too
10+ reaction target ๐ฏ
10+ reaction target ๐ฏ
๐14๐ฅ8๐1๐1๐1๐ค1
Question 1
Identify the correct set of statements related to Group 13 elements:
A. Boron shows anomalous behaviour in its group
B. Aluminium forms Alยณโบ ion easily in aqueous solution
C. Gallium has lower melting point than aluminium
D. Inert pair effect increases from B to Tl
๐ Correct option(s):
1๏ธโฃ A, C and D
2๏ธโฃ A and B
3๏ธโฃ B and C
4๏ธโฃ A, B, C and D
Question:2
Identify the correctly matched pairs:
A. Boron trichloride โ strong Lewis acid
B. Aluminium chloride โ exists as AlClโ in vapour phase
C. Diborane โ electron deficient compound
D. Boric acid โ monobasic acid
๐ Correct option(s):
1๏ธโฃ A and C
2๏ธโฃ A, C and D
3๏ธโฃ B and D
4๏ธโฃ A, B, C and D
Question:3
Identify the correct statements:
A. +3 oxidation state stability decreases from B to Tl
B. +1 oxidation state stability increases from B to Tl
C. Tlยณโบ is a strong oxidising agent
D. Boron forms stable Bยณโบ ion
๐ Correct option(s):
1๏ธโฃ A, B and C
2๏ธโฃ A and D
3๏ธโฃ B and C
4๏ธโฃ A, C and D
โค9๐คฉ4
A. Diborane has two 3-centre-2-electron bonds
B. All BโH bonds in diborane are equivalent
C. Boranes are electron-deficient compounds
D. Terminal BโH bonds are longer than bridge BโH bonds
๐ Correct option(s):
1๏ธโฃ A and C
2๏ธโฃ A, B and C
3๏ธโฃ B and D
4๏ธโฃ A, C and D
Identify the correct set regarding trihalides of Group 13:
A. Lewis acidity of BXโ decreases from BFโ to BIโ
B. BFโ is a weaker Lewis acid than BClโ
C. AlClโ acts as a Lewis acid
D. Boron trihalides undergo hydrolysis except BFโ
๐ Correct option(s):
1๏ธโฃ A and C
2๏ธโฃ B, C and D
3๏ธโฃ A, B and D
4๏ธโฃ B and C only
Identify the correct statements:
A. BโOโ is acidic in nature
B. AlโOโ is amphoteric
C. TlโOโ is basic in nature
D. Basic character of oxides decreases down the group
๐ Correct option(s):
1๏ธโฃ A and B
2๏ธโฃ A, B and C
3๏ธโฃ B and D
4๏ธโฃ A, C and D
๐7โค5๐ฏ2๐1
thermodynamics.aac
1.6 MB
Topic cover thermodynamics system surrounding boundaries
Intensive extensive property & sign uses
Intensive extensive property & sign uses
โค9โคโ๐ฅ5๐1
Chemistry booster series
Question 1 Identify the correct set of statements related to Group 13 elements: A. Boron shows anomalous behaviour in its group B. Aluminium forms Alยณโบ ion easily in aqueous solution C. Gallium has lower melting point than aluminium D. Inert pair effect increasesโฆ
โ Answer: Option 1 (A, C and D)๏ปฟ
Boron anomalous โ
Alยณโบ strongly hydrated โ aqueous me stable nahi โ
Ga ka m.p. Al se kam โ
Inert pair effect down the group increase โ
โ Answer: Option 2 (A, C and D)
BClโ = strong Lewis acid โ
AlClโ vapour phase me dimer (AlโClโ) โ
Diborane = electron deficient โ
Boric acid monobasic โ
โ Answer: Option 1 (A, B and C)
+3 down the group unstable โ
+1 stable due to inert pair โ
Tlยณโบ easily reduce hota โ strong oxidiser โ
Boron Bยณโบ ion nahi banata โ
โค8๐ฅฐ2๐ณ1๐1
Chemistry booster series
A. Diborane has two 3-centre-2-electron bonds B. All BโH bonds in diborane are equivalent C. Boranes are electron-deficient compounds D. Terminal BโH bonds are longer than bridge BโH bonds ๐ Correct option(s): 1๏ธโฃ A and C 2๏ธโฃ A, B and C 3๏ธโฃ B and D 4๏ธโฃ A,โฆ
โ Answer: Option 1 (A and C)
Diborane me 2 banana bonds โ
Terminal & bridge bonds same nahi โ
Boranes electron-deficient โ
Bridge bonds longer hote hain โ
โ Answer: Option 2 (B, C and D)
Lewis acidity: BFโ < BClโ < BBrโ < BIโ โ
AlClโ = Lewis acid โ
BFโ hydrolysis nahi karta โ (others karte)
A statement ulta likha โ
โ Answer: Option 2 (A, B and C)
BโOโ acidic โ
AlโOโ amphoteric โ
TlโOโ basic โ
Basic character increase hota hai down the group โ
๐4๐3๐1