99. Menu driven program to find number of vowels, constants, digits and special symbols in a given string.

#include <stdio.h>

int isVowel(int n,char line[]){
int vowels =0 ;
for(int i=0; i<n; i++){
if(line[i] == 97 line[i] == 101 line[i] == 105 line[i] == 111 line[i] == 117){
vowels++;
}
}
return vowels;
}

int isConstant(int n,char line[]){
int constant = 0;
for(int i=0; i<n; i++){
if(line[i] >= 65 && line[i] <= 91 || line[i] >= 97 && line[i] <= 122){
constant++;
}
}
return constant;
}
int isDigit(int n,char line[]){
int digit = 0;
for(int i=0; i<n; i++){
if(line[i] >= 48 && line[i] <= 57){
digit++;
}
}
return digit;
}
int isSpecial_symbol(int n,char line[]){
int special_symbol = 0;
for(int i=0; i<n; i++){
if(line[i] >= 33 && line[i] <= 46 line[i] >= 58 && line[i] <= 64 line[i] >= 92 && line[i] <= 96) {
special_symbol++;
}
}
return special_symbol;
}

int main(){
char line[500];
int choice,n;
int vowels;
int constant;
int special_symbol;
int digit;
char repeat;

printf("Enter an string: ");
scanf("%[^\n]%*c",&line);

n=strlen(line);

printf("1.vowels \n");
printf("2.consonant\n");
printf("3.special_symbol\n");
printf("4.digit\n");

do{
printf("Enter your choice: \n");
scanf("%d",&choice);

switch(choice){
case 1:
vowels = isVowel(n,line);
if(vowels)
printf("vowels: %d\n", vowels);
else
printf("vowel is not found!");
break;
case 2:
constant = isConstant(n,line);
if(constant)
printf("constants: %d\n", constant);
else
printf("constant is not found!");
break;
case 3:
special_symbol = isSpecial_symbol(n,line);
if(special_symbol)
printf("special symbols: %d\n", special_symbol);
else
printf("special symbol is not found!");
break;
case 4:
digit = isDigit(n,line);
if(digit)
printf("digit: %d\n",digit);
else
printf("digit is not found!");
break;
default:
printf("\ninvalid choice....!");
}
printf("\n\nDo you want to choose again?(Y/N)\n");
scanf(" %c", &repeat);
}while(repeat=='Y');

return 0;
}

C practice questions

C practice questions, only for Beginners...Happy Coding :D

Data Structure Using C by Reema Thareja | second edition

I am sharing '5_6242193455259321326' with you

For revision only.

100. C program to generate the above pattern.

#include <stdio.h>

int main() {
int i,j,f,k;
char str[80];
printf("Enter a string: ");
scanf("%s",str);
for(i=0;str[i]!='\0';i++){
for(j=0;j<=i;j++){
printf("%c",str[j]);
}
printf("\n");
}

for(k=i-1;k > 0; k--){
for(j=0;j<k;j++){
printf("%c",str[j]);
}
printf("\n");
}
return 0;
}

101. C program to generate the above pattern.

#include <stdio.h>

int main() {
int i,j,k,n=5;
for(i=0;i<n;i++){
for(j=0;j<=i;j++){

printf("%d",j+1);

for(k=j+1; k<= i; k+=4)
printf("*");
}
printf("\n");
}
return 0;
}

Hello everyone, I hope we all are doing good. I apologize for not being active these days. I'll start uploading new programs as soon as possible. Thanks for your patience.

Happy Coding!