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does the end justify the means?
For Competitive Programming
CList
You can count the number of combinations in "take or not take" situation that have repeating elements by using the formula: (pi + 1)*(pj+1)*(pk+1)....
where p is the number of occurrences of each specific element
#YIL
YIL -> Yesterday I Learned
Binlogs pinned «YIL -> Yesterday I Learned»
If you could build a machine that can travel at 16,000,000 km/s, you can reach the newly found planet in approximately 2 years.