V&V Automation Off Campus Capgemini Exceller 2024

Job Function(s) Engineering
CTC INR 300,000.00 per Annum
Salary Break-up / Additional Info
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Wipro exam questions send

import java.util.Scanner;

public class NegativeSum {
public static void main(String[] args) {

int[] numbers = {2, -3, -14, 7};


int negativeSum = findNegativeSum(numbers);


}


public static int findNegativeSum(int[] arr) {
int sum = 0;
for (int num : arr) {
if (num < 0) {
sum += num;
}
}
return sum;
}
}

Wipro exam ans
19/1/2025

Java

@itjobsservices

import java.util.Scanner;

public class MidIndexProblem {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);

// Read the number of elements
System.out.println("Enter the number of elements:");
int n = scanner.nextInt();

// Read the array elements
int[] arr = new int[n];
System.out.println("Enter the elements:");
for (int i = 0; i < n; i++) {
arr[i] = scanner.nextInt();
}

// Find the mid-index
int midIndex = n / 2;

// Output the middle element
System.out.println("Middle element: " + arr[midIndex]);

scanner.close();
}
}
wipro
19/1/25
2. ans , mid-index problem
Java

@itjobsservices

import java.util.Scanner;

public class RotateNumberArray {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);

// Input the number
System.out.println("Enter the number:");
String input = scanner.next();
int n = input.length();

// Convert the number into an array of digits
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = Character.getNumericValue(input.charAt(i));
}

// Input the number of rotations
System.out.println("Enter the number of rotations:");
int rotations = scanner.nextInt();

// Perform the rotation
int[] rotatedArray = rotateArray(arr, rotations);

// Print the rotated array as a number
System.out.println("Rotated Number:");
for (int digit : rotatedArray) {
System.out.print(digit);
}
scanner.close();
}

public static int[] rotateArray(int[] arr, int rotations) {
int n = arr.length;

// Normalize the rotations
rotations = rotations % n;

// Create a new array to hold the rotated result
int[] result = new int[n];

// Copy the last 'rotations' elements to the beginning
for (int i = 0; i < rotations; i++) {
result[i] = arr[n - rotations + i];
}

// Copy the remaining elements
for (int i = rotations; i < n; i++) {
result[i] = arr[i - rotations];
}

return result;
}
}

Sample input

123456

2

Sample Output

561234
Java

19/1/25

Wipro exam