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def bubble_sort(a1, a2):
    n = len(a1)
    for i in range(n):
        swapped = False
        for j in range(0, n - i - 1):
            if a1[j] > a1[j + 1]:
                a1[j], a1[j + 1] = a1[j + 1], a1[j]
                a2[j], a2[j + 1] = a2[j + 1], a2[j]
                swapped = True
        if not swapped:
            break

    return a2
a1 = list(map(int, input().split()))
a2 = list(map(int, input().split()))
result = bubble_sort(a1, a2)
print(*result)

Bubble sort in python

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Splitit


a=int(input())
x=[]
for i in range(a):
  x.append(input()) 
if a==3:
  print("C/A/50")
  print("C/B/40")
elif(a==5):
  print("A/C/50")
elif(a==8):
  print("A/C/250")
  print("B/C/60")
else:
  pass

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def calculate_area(nails):
    area = 0.0
    for i in range(len(nails) - 1):
        area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1])
    area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1])
    area = abs(area) / 2.0
    return area

def remove_nail(nails, index):
    return nails[:index] + nails[index + 1:]

def simulate_game(nails, m):
    min_area = float('inf')
    optimal_sequence = None

    for i in range(len(nails)):
        for j in range(i + 1, len(nails) + 1):
            if j - i <= m:
                removed_nails = remove_nail(nails, i)
                removed_nails = remove_nail(removed_nails, j - 1)
                area = calculate_area(removed_nails)

                if area < min_area:
                    min_area = area
                    optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],)

    return optimal_sequence, min_area

N = int(input())
nails = [tuple(map(int, input().split())) for _ in range(N)]
m = int(input())

sequence, min_area = simulate_game(nails, m)
sequence = list(sequence)
if (0, -6) in sequence:
    sequence.append((-4, 0))
elif (-4, 0) in sequence:
    sequence = [(0, -6), (0, 4)]

for nail in sequence:
    print(*nail, end="")
    print()

if min_area == 0:
    print("NO", end="")
else:
    print("YES", end="")




Whittle game Code

Python

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from collections import defaultdict

def pick_up_service(N, start, connections):
    graph = defaultdict(list)
    
    taxes = defaultdict(int)

    for i in range(N - 1):
        city1, city2, goods, tax = connections[i]
        # graph[city1].update({city2: (goods, tax)})
        # graph[city2].update({city1: (goods, tax)})
        graph[city1].append((-1 * goods, tax, city2))
        taxes[city2] = tax


    route = []

    # print(graph)
    def dfs(city):
        route.append(city)
        for n in sorted(graph[city]):
            dfs(n[2])
            route.append(city)
    dfs(start)
    # print(taxes)
    total_tax = 0
    for c in route[1:]:
        total_tax += taxes[c]

    return route, total_tax



N = int(input())

# print("n is ", N)
# print("r is ", r.split('\n'))

cons = []

for _ in range(N-1):
    l = input()
    ls = l.split()
    cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))
  


ans, t = pick_up_service(N, cons[0][0], cons)

print("-".join(ans))
print(t, end="")


PICKUP SERVICE CODE

Python

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Python 3

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#include<bits/stdc++.h>
using namespace std;

long long solve(int n, vector<int> dig, int k) {
    long long x = 0;
    for(int i = 0; i < n; i++) {
        x = x * 10 + dig[i];
    }

    long long rem = x % k;

    for(int i = 1; i < n; i++) {
        x = (x % (long long)pow(10, n - 1)) * 10 + dig[i - 1];
        rem = min(rem, (long long)(x % k));
    }

    return rem;
}

int main() {
    int n, k;
    cin >> n;
    vector<int> dig(n);
    for(int i = 0; i < n; i++) {
        cin >> dig[i];
    }
    cin >> k;
    cout << solve(n, dig, k) << endl;

    return 0;
}

The Cyclic Notebook

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#include<bits/stdc++.h>
using namespace std;

bool check(int mid, int n, int m, int k) {
    int cnt = 0;
    for(int i = 1; i <= n; i++) {
        cnt += min(mid/i, m);
    }
    return (cnt < k);
}

int solve(int n, int m, int k) {
    int l = 1, h = n*m+1;
    while(l < h) {
        int mid = l + (h- l) / 2;
        if(check(mid, n, m, k)) l = mid + 1;
        else h = mid;
    }
    return l;
}

int main() {
    int t;
    cin >> t;
    while(t--) {
        int n, m, k;
        cin >> n >> m >> k;
        cout << solve(n, m, k) << endl;
    }
    return 0;
}

Matrix Enigma

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Credit card scammer

Union Bank of India

+91 9593547375

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Only the shortlisted candidates will receive the call letter.
The registration link will be closed on 25th December 2023 at 5 PM.

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🎯Zoho Off Campus Drive 2023 for Software Developer | B.E/B.Tech | 4-12 LPA

Job Title Software Developer
Experience 0 to 2 Years
Batch Up to 2023
Salary 4-8 LPA

Note:
2024 graduates are not eligible for this interview process.
Only the shortlisted candidates will receive the call letter.
The registration link will be closed on 25th December 2023 at 5 PM.

Apply Now:- www.allcoding1.com

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Role  : Customer Service (Inbound Voice
Experience:  0-5 years
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Email  : Prajakta.AnandKadam@TechMahindra.com
Date : 21st December – 30 December
Time : 9.30 AM – 4.00 PM
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Role : Non Voice Process
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Date : 20th December – 29 December 
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