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networking security and clouds

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int LetteredNumberSum(char* str, int len) {
    if (str == nullptr) {
        return 0;
    }

    int sum = 0;
    for (int i = 0; i < len; i++) {
        char letter = str[i];
        int ans = 0;
//@allcoding1
        switch (letter) {
            case 'A':
                ans = 1;
                break;
            case 'B':
                ans = 10;
                break;
            case 'C':
                ans = 100;
                break;
            case 'D':
                ans = 1000;
                break;
            case 'E':
                ans = 10000;
                break;
            case 'F':
                ans = 100000;
                break;
            case 'G':
                ans = 1000000;
                break;
            default:
                ans = 0;
                break;
        }

        sum += ans;
    }

    return sum;
}

C++

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Merge String code
def MergeStrings(str1, str2):
    if str1 is None and str2 is None:
        return None
    if str1 is None:
        return str2
    if str2 is None:
        return str1
   
    len1 = len(str1)
    len2 = len(str2)
    merged = [''] * (len1 + len2)
   
    for i in range(min(len1, len2)):
        if str1[i] <= str2[i]:
            merged[i] = str1[i]
            merged[-(i+1)] = str2[i]
        else:
            merged[i] = str2[i]
            merged[-(i+1)] = str1[i]
   
    if len1 > len2:
        for i in range(len2, len1):
            merged[i] = str1[i]
    elif len2 > len1:
        for i in range(len1, len2):
            merged[i] = str2[i]
   
    return ''.join(merged)

Python

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Today accenture exam Ans

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