1. In order to open a new window in incognito mode of Chrome, you should use:
- Answer: B. Ctrl + Shift + N

2. Q05. While configuring your email ID in MS Outlook, which of the following protocols should be used for sending emails?
- Answer: D. SMTP

3. Q06. Which of the following network devices operates at the physical layer of the OSI model?
- Answer: D. Hub

4. Q07. Which of the following is an example of a lossy compression file?
- Answer: A. JPEG

5. Q08. Wireless mouse and keyboard communicate through which of the following?
- Answer: A. Electromagnetic signals

6. Q09. MS Outlook will alert you if you forget to:
- Answer: B. Attach a file after writing the word "attached" in the email body

7. Q10. If you are receiving all the emails of a client in the SPAM folder, which of the following actions should you take to receive them in the INBOX?
- Answer: A. All of the mentioned options

8. Q11. In order to change the slideshow view to normal view in PowerPoint, which of the following can be used?
- Answer: B. ESC

9. Q12. In MS Excel, Alt+= is used for which of the following purposes?
- Answer: B. AutoSum

10. Q13. Performance information of which of the following is shown in the task manager?
- Answer: C. All 1, 2 & 3 (CPU, Memory, GPU)

11. Q14. Ping (command line utility) is used to check which of the following?
- Answer: A. Only 1 & 2 (Connectivity between host and server/host, The round-trip time of the packet)

12. Q15. Which of the following memory types in a computer is static as well as non-volatile?
- Answer: A. ROM

Telegram:- @allcoding1

import java.util.Scanner;

public class ChangeCase {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
char c = scanner.next().charAt(0);

if (Character.isLowerCase(c)) {
System.out.println(Character.toUpperCase(c));
} else {
System.out.println(Character.toLowerCase(c));
}

scanner.close();
}
}

Telegram:- @allcoding1

#include<stdio.h>

int main() {
int n;
scanf("%d", &n);

char str[n + 1];
scanf("%s", str);

int count = 0;
char thirdLastConsonant;

for(int i = n - 1; i >= 0; i--) {
if (str[i] != 'a' && str[i] != 'e' && str[i] != 'i' && str[i] != 'o' && str[i] != 'u' &&
str[i] != 'A' && str[i] != 'E' && str[i] != 'I' && str[i] != 'O' && str[i] != 'U') {
count++;
if (count == 3) {
thirdLastConsonant = str[i];
break;
}
}
}

printf("%c\n", thirdLastConsonant);
return 0;
}

n = int(input())
s = input()
consonants = 0
for i in range(n-1,-1,-1):
if s[i] not in 'aeiouAEIOU':
consonants += 1
if consonants == 3:
print(s[i])
break

22

39

10

3

5.B
6.D
7.C

Wipro

20

DVI

A

A

6

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import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);


int L1 = scanner.nextInt();
int R1 = scanner.nextInt();
int L2 = scanner.nextInt();
int R2 = scanner.nextInt();


int maxProduct = Integer.MIN_VALUE;

for (int a = L1; a <= R1; a++) {
for (int b = L2; b <= R2; b++) {
maxProduct = Math.max(maxProduct, a * b);
}
}


System.out.println(maxProduct);
}
}

def sum_of_divisors(n):
sum_div = 0
for i in range(1, int(n**0.5) + 1):
if n % i == 0:
sum_div += i
if i != n // i:
sum_div += n // i
return sum_div

# Read the input integer
n = int(input())

# Calculate and print the sum of divisors
print(sum_of_divisors(n))

Python

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p = int(input())
r = int(input())
n = int(input())

compounded_amount = p * ((100 + r) n) // (100 n)

print(compounded_amount)

Python