allcoding1
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🎯Atos Is Hiring

Degree:- Any Graduate
Batch:- 2019, 2020, 2021, 2022, 2023 & 2024

Apply Now:-  https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html


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🎯SAS Off Campus Drive 2024 – Associate Software Engineer – Freshers | Rs 4-8 LPA

Job Role : Associate Software Developer
Qualification : B.E/B/Tech/M.E. / M.Tech
Experience : Freshers
Job Location : Pune
Package : Rs 4-8 LPA

Apply Now:- https://www.allcoding1.com/2024/02/sas-off-campus-drive-2024-associate_9.html?m=1

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Minimum moves
Wissen

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BST code
IBM
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Virtual Machine
Wissen

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Minimum Moves
IBM

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Circle code
IBM

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Forwarded from allcoding1
🎯Atos Is Hiring

Degree:- Any Graduate
Batch:- 2019, 2020, 2021, 2022, 2023 & 2024

Apply Now:-  https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html


Telegram:- @allcoding1
Forwarded from allcoding1
🎯SAS Off Campus Drive 2024 – Associate Software Engineer – Freshers | Rs 4-8 LPA

Job Role : Associate Software Developer
Qualification : B.E/B/Tech/M.E. / M.Tech
Experience : Freshers
Job Location : Pune
Package : Rs 4-8 LPA

Apply Now:- https://www.allcoding1.com/2024/02/sas-off-campus-drive-2024-associate_9.html?m=1

Telegram:- @allcoding1
🎯 Microsoft Bulk Hiring 2024 | For Software Engineer

Degree:- BE, B Tech, BA, B COM, BBA, BSC, BCA, ME, M Tech, MCA, MA, M COM, MSC, Any Graduate
Batch:-  2018, 2019, 2020, 2021, 2022, 2023 ,2024 & 2025

Apply now:- https://www.allcoding1.com/2024/02/microsoft-bulk-hiring-2024-for-software.html

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🎯Tech Mahindra Off Campus drive

Job Role Associate Software Engineer
Qualification B.E/B.Tech/MCA/M.Sc
Experience Freshers
Batch 2022/2023
Salary Rs.3.25 LPA & 5.5LPA (for super coders)
Job Location Across India
Venue Location Virtual(Online)
Last Date 4 February 2024

Apply now:- https://www.allcoding1.com/2024/02/tech-mahindra-off-campus-drive-2024.html?m=1

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26) D
27) C
28)A

@allcoding1
#include <bits/stdc++.h>
using namespace std;

int getMinimumMoves(string word) {
    unordered_map<char, int> freq;
    int moves = 0;

    for (char c : word) {
        freq[c]++;
    }

    for (auto& entry : freq) {
        moves += entry.second / 2;
    }

    return moves;
}

Minimum length word

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#include <iostream>
#include <vector>
#include <unordered_map>
#include <sstream>

using namespace std;

vector<string> computeParameterValue(vector<vector<string>>& sources) {
    unordered_map<string, string> final_parameters;
    vector<string> order_of_keys;

    for (auto& source : sources) {
        for (auto& pair : source) {
            stringstream ss(pair);
            string key, value;
            getline(ss, key, ':');
            getline(ss, value, ':');

            if (final_parameters.find(key) == final_parameters.end()) {
                order_of_keys.push_back(key);
            }
            final_parameters[key] = value;
        }
    }

    vector<string> final_parameters_list;
    for (auto& key : order_of_keys) {
        final_parameters_list.push_back(final_parameters[key]);
    }

    return final_parameters_list;
}

Stock Analysis

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static int getAnagramPeriod(String input_str) {
        int n = input_str.length();
       
        for (int period = 1; period <= n; period++) {
            if (n % period == 0) {
                String subString = input_str.substring(0, period);
                boolean valid = true;

                for (int i = 0; i < n; i += period) {
                    if (!isAnagram(subString, input_str.substring(i, i + period))) {
                        valid = false;
                        break;
                    }
                }

                if (valid) {
                    return period;
                }
            }
        }

        return -1;
    }

    static boolean isAnagram(String str1, String str2) {
        char[] charArray1 = str1.toCharArray();
        char[] charArray2 = str2.toCharArray();
        Arrays.sort(charArray1);
        Arrays.sort(charArray2);
        return Arrays.equals(charArray1, charArray2);
    }

Anagram Period

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int solve(int N, vector<int> A, int T) {
    int xa = 0;
    for(int i=0; i<N; i++) {
        xa ^= A[i];
    }
    int d = xa ^ T;
    if(d == 0) return 0;
    int ops = 0;
    while(d > 0) {
        ops += d & 1;
        d >>= 1;
    }
    return ops;
}

Flip or flop

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🎯EY is hiring for Data and Analytics

Expected Salary: 5-10 LPA

🔗Apply here: https://eyglobal.yello.co/jobs/Zz403Fi4A5JV05N-0NtWSQ?job_board_id=c1riT--B2O-KySgYWsZO1Q