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Bit Logic
C++
Telegram:- @allcoding1
int solve(vector<vector<int>> arr) {
    int n = arr.size();
    vector<vector<int>> dp(n, vector<int>(n));
    int maxi = 0;

    for(int i = 0; i < n; i++) {
        for(int j = 0; j < n; j++) {
            if(i == 0 || j == 0) {
                dp[i][j] = arr[i][j];
            } else if(arr[i][j] == 1) {
                dp[i][j] = min({dp[i-1][j], dp[i][j-1], dp[i-1][j-1]}) + 1;
            }
            maxi = max(maxi, dp[i][j]);
        }
    }

    return maxi;
}

IBM

C++

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return min(e-b+1, numChapters)
Python 3
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class Solution {
public:
     void bfs(vector<vector<int>>&vis,vector<vector<char>>&grid,int i,int j,int n,int m)
    {
        vis[i][j]=1;
        queue<pair<int,int>>q;
        q.push({i,j});
        while(!q.empty())
        {
            int row=q.front().first;
            int col=q.front().second;
            q.pop();
            int delrow[4]={1,0,-1,0};
            int delcol[4]={0,1,0,-1};
                   for(int k=0;k<=3;k++){
                    int nrow=row+delrow[k];
                    int ncol=col+delcol[k];
                    if(nrow>=0 and nrow<n and ncol>=0 and ncol<m and grid[nrow][ncol]=='1' and !vis[nrow][ncol])
                    {
                        vis[nrow][ncol]=1;
                        q.push({nrow,ncol});
                    }
                }
            }
        }
    int numIslands(vector<vector<char>>& grid) {
    int n=grid.size();
        int m=grid[0].size();
        vector<vector<int>>vis(n,vector<int>(m,0));
        int cnt=0;
        for(int i=0;i<n;i++)
        {
            for(int j=0;j<m;j++)
            {
                if(!vis[i][j] and grid[i][j]=='1')
                {
                    cnt++;
                    bfs(vis,grid,i,j,n,m);
                }
            }
        }
        return cnt;
    }
};

Zeta

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