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Infosys Hiring

Deadline: 30 june
Test date : 3 july

Apply Now:-
https://surveys.infosysapps.com/r/a/SPOffcampusregistration_Jul2025
Company name: Rolls Royce
Role: Data Engineer Intern
Batch Eligible: 2026 & 2027 graduates

Apply now:
https://rollsroyce.wd3.myworkdayjobs.com/en-US/Apprentice/job/Bangalore/Internship---Data-Engineer_JR6139999
HSBC Hiring



Role:- Full Stack Developer /Consultant Specialist
Job ID :- 0000LHJ5
Location :- Bangalore, India Area of interest
Technology:- Job type
Permanent - Full Time
Work style :- Office Working
Opening date:- 29-Jun-2025
Closing date:- 05-Jul-2025

Apply:- http://www.itjobs.services/2025/07/hsbc-hiring-full-stack-developer.html
2
NTT Data Hiring Entry-Level Associate Software Development Engineer

Job Title : Associate Software Development Engineer

Job Location : Hyderabad, Bangalore, New Delhi

Salary : Best In Industry

Experience : Freshers/Early Careers

Qualification : Technical Graduate BE/B.Tech/MCA/ BSC/BCA/BBA/ or Related

Batch : 2025/2024/2023/2022 or Any

Apply Now : https://careers.services.global.ntt/global/en/job/R-132084/apply?source=LinkedIn
5
Citi Recruitment 2025: Apply for Chat Operations Officer – Freshers Eligible

Location: Pune

Qualification: Any Graduate

Experience: 0 – 3 Years

Apply - https://jobs.citi.com/job/-/-/287/82504726944
1
Exciting Opportunities in Tech

Company: Winfo Solutions
Role: Trainee Software Engineer
Experience: 0+ Years
Location: Hyderabad, Bangalore
Apply Now: https://lnkd.in/g4RhReEx


Company: PayPal
Role: Software Engineer
Experience: 2+ Years
Location: Bangalore
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Company: Experian
Role: Software Engineer
Experience: 1+ Years
Location: Hyderabad
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Company: Yext
Role: Software Engineer
Experience: 1+ Years
Location: Hyderabad
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2
Zoho hiring for Software Developer role

Salary : 5 - 19 LPA (Expected)
Experience : Freshers/ Experienced

Apply Now : https://careers.zohocorp.com/jobs/careers/2803000614929615/Software-Developers?source=CareerSite
#include <bits/stdc++.h>
using namespace std;

int Solution::findRadius(vector<int> &A, vector<int> &B) {
if (B.empty()) return INT_MAX;

sort(B.begin(), B.end());
int radius = 0;
for (int a : A) {
auto it = lower_bound(B.begin(), B.end(), a);

int dist = INT_MAX;
if (it != B.end()) {
dist = min(dist, abs(*it - a));
}
if (it != B.begin()) {
dist = min(dist, abs(*(it - 1) - a));
}

radius = max(radius, dist);
}
return radius;
}

Wifi Router Installation
C++
100% Correct Code

Amazon ML school exam

Telegram:- @allcoding1
1
S2: 4xy
S7: 6
S12: 0
Q4: 1/2
S22: (2, 3)
S28: Target/Mean Encoding
S29: TimeSeriesSplit
S38: 15
S43: 2/5
S59: Mode > Median > Mean

ML - 2: The data has a Gaussian distribution
ML - 7: Updating prior beliefs with observed data using Bayes' theorem
ML - 12: The probability distribution over actions given states
ML - 17: Internal covariate shift
ML - 23: Boosting reduces bias, bagging reduces variance
ML - 24: Binary Cross-Entropy
S48: 30/84
S60: 150
S53: 2/3
S68: Prior × Likelihood


Amazon Machine Learning Summer School:

Exam Date: 3rd August 2025
Exam Duration: 60 mins

10:30 AM

Test format:
Section 1 - MCQ section - 20 questions
Section 2 - DSA type coding section - 2 questions

Answers available 👇👇👇
Telegram channel:- @allcoding1
1
M1: Encode sequential order

T1: Regularization

M16: Likelihood × Prior

ML2: SGD can escape local minima due to its noisy updates

ML3: Recursive Feature Elimination (RFE)

ML4: Gini Index

M4: It overfits the training data

M7: 0

M2: Strong negative linear relationship

S13: No real solution
S17: Local minimum
S23: Converges by Limit Comparison with 1/n²
S30: Collect recent user data and evaluate model drift
S31: Data leakage inflated model performance
S39: 6/216

Amazon ML School MCQ Answers 1:15 PM
Kill the enemy
C++
Amazon 1.15 PM


#include <vector>
#include <algorithm>

int solve(std::vector<int> &A, int B) {
long long m1 = 0, m2 = 0;

for (int val : A) {
if (val > m1) {
m2 = m1;
m1 = val;
} else if (val > m2) {
m2 = val;
}
}

long long b = B;
long long s = m1 + m2;

if (s == 0) {
return b > 0 ? -1 : 0;
}

long long k = b / s;
int ans = k * 2;
long long rem = b % s;

if (rem == 0) {
return ans;
} else if (rem <= m1) {
return ans + 1;
} else {
return ans + 2;
}
}
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