#include <iostream>
#include <string>
#include <vector>
using namespace std;

int numDecodings(string msg) {
    int MOD = 1000000007;
    int n = msg.size();
   
    vector<long long> dp(n + 1, 0);
    dp[0] = 1;
   
    if (msg[0] == '0')
        dp[1] = 0;
    else if (msg[0] == '*')
        dp[1] = 9;
    else
        dp[1] = 1;
   
    for (int i = 2; i <= n; ++i) {
        if (msg[i - 1] == '0') {
           
            if (msg[i - 2] == '1' || msg[i - 2] == '2')
                dp[i] += dp[i - 2];
            else if (msg[i - 2] == '*')
                dp[i] += 2 * dp[i - 2];
        } else if (msg[i - 1] >= '1' && msg[i - 1] <= '9') {
     
            dp[i] += dp[i - 1];
           
            if (msg[i - 2] == '1' || (msg[i - 2] == '2' && msg[i - 1] <= '6'))
                dp[i] += dp[i - 2];
            else if (msg[i - 2] == '*') {
               
                if (msg[i - 1] <= '6')
                    dp[i] += 2 * dp[i - 2];
                else
                    dp[i] += dp[i - 2];
            }
        } else if (msg[i - 1] == '*') {
            dp[i] += 9 * dp[i - 1];
           
            if (msg[i - 2] == '1')
                dp[i] += 9 * dp[i - 2];
            else if (msg[i - 2] == '2')
                dp[i] += 6 * dp[i - 2];
            else if (msg[i - 2] == '*')
                dp[i] += 15 * dp[i - 2];
        }
       
        dp[i] %= MOD;
    }
   
    return dp[n];
}

Number of ways decode


Accenture exam

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heights = [int(i) for i in input().split()]
freq_dict = {}
for h in heights:
if h in freq_dict:
  freq_dict[h] += 1
else:
  freq_dict[h] = 1
for h in sorted(freq_dict):
print(h, freq_dict[h])

Accenture exam

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#include <iostream>
#include <sstream>
#include <string>
#include <vector>

std::string stemmer(const std::string& text) {
    std::stringstream ss(text);
    std::string word;
    std::vector<std::string> stemmed_words;

    while (ss >> word) {
        if (word.size() > 2 && (word.substr(word.size() - 2) == "ed" word.substr(word.size() - 2) == "ly" word.substr(word.size() - 3) == "ing")) {
            word = word.substr(0, word.size() - 2);
        }
        if (word.size() > 8) {
            word = word.substr(0, 8);
        }
        stemmed_words.push_back(word);
    }

    std::string result;
    for (const std::string& stemmed_word : stemmed_words) {
        result += stemmed_word + " ";
    }


    result.pop_back();
    return result;
}

int main() {
    std::string text = "an extremely dangerous dog is barking";
    std::cout << stemmer(text) << std::endl;  // Output: "an extreme dangerou dog is bark"

    return 0;
}

Suffix stripping stemmer

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class Message(object):
    def init(self, message: str, sender: int, receiver: int) -> None:
        self.message = message
        self.sender = sender
        self.receiver = receiver

    def str(self) -> str:
        return self.message

    def eq(self, other: object) -> bool:
        if not isinstance(other, Message):
            return False
        return self.message == other.message

Message Objects

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#include <iostream>
#include <string>
#include <unordered_map>

using namespace std;

long getkRepValue(string user_history, long k) {
    long n = user_history.size();
    unordered_map<char, long> count;
    long left = 0, right = 0, ans = 0;

    while (right < n) {
        count[user_history[right]]++;
        while (count[user_history[right]] >= k && left <= right) {
            ans += n - right;
            count[user_history[left]]--;
            left++;
        }
        right++;
    }

    return ans;
} 

Machine learning
Amazon

int solve(vector<int> tc) {
    int n = tc.size();
    vector<int> p(n), s(n);

    p[0] = tc[0];
    for (int i = 1; i < n; ++i) {
        p[i] = p[i - 1] + tc[i];
    }

    s[n - 1] = tc[n - 1];
    for (int i = n - 2; i >= 0; --i) {
        s[i] = s[i + 1] + tc[i];
    }

    int m = max(p[0], s[0]);
    for (int i = 1; i < n; ++i) {
        m = max(m, max(p[i], s[i]));
    }

    return m;
}

Amazon

#include <vector>
#include <unordered_map>
#include <iostream>

using namespace std;

int getMinTransactions(int n, vector<vector<int>>& debt) {
    unordered_map<int, int> balance
    for (const auto& d : debt) {
        balance[d[0]] -= d[2];
        balance[d[1]] += d[2];
    }
   
    vector<int> transactions;
    for (const auto& entry : balance) {
        if (entry.second != 0) {
            transactions.push_back(entry.second);
        }
    }

    int count = 0;
    int i = 0, j = transactions.size() - 1;
    while (i < j) {
        if (transactions[i] + transactions[j] == 0) {
            count++;
            i++;
            j--;
        } else if (transactions[i] + transactions[j] > 0) {
            transactions[i] += transactions[j];
            j--;
            count++;
        } else {
            transactions[j] += transactions[i];
            i++;
            count++;
        }
    }
    return count;
}

Transaction Simplification

#include<bits/stdc++.h>
using namespace std;
string str, bad_string;
struct node{
    bool end_mark;
    node *next[10];
    node()
    {
        end_mark = false;
        for(int i = 0; i<10; i++)
            next[i] = NULL;
    }
}*root;
bool add(string s)
{
    node *current = root;
    for(int i = 0; i<s.size(); i++)
    {
        int nw = s[i] - 'a';
        if(i == (s.size()-1) && current->next[nw] != NULL)
            return false;
        if(current->next[nw] == NULL)
            current->next[nw] = new node();
        current = current->next[nw];
        if(current->end_mark)
            return false;
    }
    current->end_mark = true;
    return true;
}

int main()
{
    int i, N;
    bool ok = true;
    cin >> N;
    root = new node();
    for(i = 1; i<=N; i++)
    {
        cin >> str;
        if(!ok)
            continue;
        ok = add(str);
        if(!ok)
            bad_string = str;
    }
    if(ok)
        printf("GOOD SET\n");
    else
    {
        printf("BAD SET\n");
        cout << bad_string << endl;
    }
}

Good Bad String
Uber

#include <bits/stdc++.h>
using namespace std;

const int MOD = 1e9 + 7;

long long solution(int n, vector<long long>& a, vector<long long>& b) {
    long long ans = 0;

    int minP = min_element(a.begin(), a.end()) - a.begin();
    int minQ = min_element(b.begin(), b.end()) - b.begin();

    for (int i = 0; i < n; i++) {
        if (i == minP || i == minQ)
            continue;

        ans += min(a[minP] * b[i], b[minQ] * a[i]);
        ans %= MOD;
    }

    if (minP != minQ) {
        ans += a[minP] * b[minQ];
        ans %= MOD;
    }

    return ans;
}.

professor code
Uber