class Solution:

def intersect(self, nums1: List[int], nums2: List[int]) -> List[int]:

dict1 = dict()

for i in nums1:

if i not in dict1:

dict1[i] = 1

else:

dict1[i] += 1

ret = []

for i in nums2:

if i in dict1 and dict1[i]>0:

ret.append(i)

dict1[i] -= 1

return ret



Python3

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class Solution:
    def intersect(self, nums1: List[int], nums2: List[int]) -> List[int]:
        dict1 = dict()
        for i in nums1:
            if i not in dict1:
                dict1[i] = 1
            else:
                dict1[i] += 1
        ret = []
        for i in nums2:
            if i in dict1 and dict1[i]>0:
                ret.append(i)
                dict1[i] -= 1
        return ret


Python
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int Children = 0,Adult = 0;
        for(int i=0;i<A.length;i++){
            if(A[i] <= 18){
                Children++;
            }
            else{
                Adult++;
            }
        }
        System.out.println("Children count:"+Children);
         System.out.println("Adult count:"+Adult);

Java

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Test class derived...

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All are correct

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Compile_time error

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Reverse of an array

Python3

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