3Q) Ans
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4Q) Ans
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5) data in statement 2 alone ....
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6) data is insufficient
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7) Peternal grandfathers brother
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Reasoning

1)Shri
2)A and C
5) data in statement 2 alone ....
6)data is insufficient
7) Peternal grandfathers brother
8)T*U#V....
9)Suraj and Hill
10)the candidate is to be selected


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Advanced quantitative
1)5/24
2)352
3)48 x^273x+388=0
4)30,30
5)14

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Advanced quantitative
1)5/24
2)352
3)48 x^273x+388=0
4)30,30
5)14
6)41
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Advanced apitude

1)5/24
2)228
3)48X^2+21X+102=0
4) 30,30
5) 14
6) 41
7) 12870


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Advanced apitude

1)5/24
2)228
3)48X^2+21X+102=0
4) 30,30
5) 14
6) 41
7) 12870
8) ii and iii
9) 2 and 3 only

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Advanced apitude

1)5/24
2)228
3)48X^2+21X+102=0
4) 30,30
5) 14
6) 41
7) 12870
8) ii and iii
9) 2 and 3 only

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Advanced apitude

1)5/24
2)228
3)48X^2+21X+102=0
4) 30,30
5) 14
6) 41
7) 12870
8) ii and iii
9) 2 and 3
10)1 and 4 only

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Advance apti answers

1. 5/24

2. 352

3. 48x^2-273x+338=0

4. 30,30

5. 120

6. 15

7. 1080

8. II and III only

9. I and II only

10. I and IV only

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Python
Jack and Jill Code
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n=int(input())
jk=list(map(int,input().split()))
jl=list(map(int,input().split()))
l=len(jk)
jksum=0
jlsum=0
lind=[]
while l!=0:
b=[]
ind=jk.index(max(jk))
jksum+=max(jk)
lind.append(ind)
//@allcoding1
for i in range(0,len(jl)):
if i not in lind:
b.append(jl[i])
l-=1
jlsum+=max(b)
if jksum>jlsum:
print("jack")
elif jksum==jlsum:
print("Tie")
else:
print("jill")

Python
Jack and Jill Code
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Python
Jack and Jill Code
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TCS NQT 6pm
1)2772
2)10
3)2

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TCS NQT 6pm
1)2772
2)10
3)2
4)280

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TCS NQT 6pm
1)2772
2)10
3)2
4)280
5)720

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TCS NQT 6pm
1)2772
2)10
3)2
4)280
5)720
6)B=A

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TCS NQT 6pm
1)2772
2)10
3)2
4)280
5)720
6)B=A
7)294674

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