Kepada batch 09 juga, good luck for your upcoming exams, especially spm 2026. Be ready with every subject, conquer the chapter, jangan belajar last minit, dengar cakap cikgu dan jangan skip sekolah/kelas tambahan

Let x=length of the rectangle
h = height of the rectangle

Black line = h/tan(60°) = (h√3)/3

Using Pythagoras' Theorem,
[(h√3)/3 + x]² + h² = 36
h²/3 + (2xh√3)/3 + x² + h² - 36 = 0
h²(4/3) + [(2x√3)/3]h + (x²-36) = 0
h = [-(2x√3)/3 + √[(4x²/3)-(16/3)(x²-36)]]/(8/3)
h = [-x√3 + 3√(48-x²)]/4

Area of the rectangle, A = xh = x([-x√3 + 3√(48-x²)]/4)

dA/dx = (72-3x²-x√(144-3x²))/(2√(48-x²))

At Maximum, dA/dx = 0
(72-3x²-x√(144-3x²))/(2√(48-x²)) = 0
72-3x²-x√(144-3x²) = 0
=> x=-6 or x=2√3

Max A = 6√3

day 1 of studying addmaths everyday...🔥🔥 make sure u do 3 questions atleast a day...

Percayalah cakap saya, mula lah sekarang. Jangan tunggu saat akhir. Pesanan yang sama dari saya, sebab saya dah tengok pelbagai situasi pelajar saat2 last nak spm

It is given that the diameter of the circle is divided into 4 equal parts, find the area of the shaded region if the radius of the circle = 4 cm.

Try this guys. This should be easy

Day 02 of studying addmaths everyday

Red Curve: y = 2x³ - x² - 14x
Blue Curve: y = 4x - x²

Find the area of the shaded region.

Kenapa B) −5 salah ❌
Terlupa darab 3 × 4 = 12. Ramai yang guna 10 instead of 12 masa buat complete the square