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$(25-t) dt from 0 to t = 132
(25t-t²/2) from 0 to t = 132
(25t-t²/2)-(25(0)-0²/2) = 132
25t-t²/2 = 132
t²-50t+264=0
By using QF,
t = 6 or 44
Since t<25
t=6h
(25t-t²/2) from 0 to t = 132
(25t-t²/2)-(25(0)-0²/2) = 132
25t-t²/2 = 132
t²-50t+264=0
By using QF,
t = 6 or 44
Since t<25
t=6h
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AddMath Spmnetic!™⚡️
$(25-t) dt from 0 to t = 132 (25t-t²/2) from 0 to t = 132 (25t-t²/2)-(25(0)-0²/2) = 132 25t-t²/2 = 132 t²-50t+264=0 By using QF, t = 6 or 44 Since t<25 t=6h
Here is the answer from tony, but for this question, we can solve it in using physics f4c2 formula, either U can use displacement formula or average speed * time formula... Since the initial speed is 25m squared per hour and the total displacement(in this case total area is 132) and since the acceleration is (-1)(acceleration is derivative of the rate, 25-t...)
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Here is a progression method by Julius to solve this question...guys this is the beauty of maths... one question, but U can use calculus/physics/progression... Though the core is the same...
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AddMath Spmnetic!™⚡️
The diagram shows a 50 pence coin. It's shape is formed by joining seven arcs with the same arc length. Given that the radius of the circle that forms the arc is equal to 1cm, find the area of the 50 pence coin.
Fun fact guys, this is the world 1st 7 sided coin...
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Hi semua!!! Good luck untuk chemistry esok!!! Harap soalan senang😭
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Hi guys, how was chemistry?? For me, it was hard😭
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Hi guys for this type of question, U can check Ur answer by adding all x coordinates and dividing by 3, and all y cordinates divide by 3, to get the final h,k coordinates
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